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| Mirrors > Home > ILE Home > Th. List > eqtr | GIF version | ||
| Description: Transitive law for class equality. Proposition 4.7(3) of [TakeutiZaring] p. 13. (Contributed by NM, 25-Jan-2004.) |
| Ref | Expression |
|---|---|
| eqtr | ⊢ ((𝐴 = 𝐵 ∧ 𝐵 = 𝐶) → 𝐴 = 𝐶) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | eqeq1 2245 | . 2 ⊢ (𝐴 = 𝐵 → (𝐴 = 𝐶 ↔ 𝐵 = 𝐶)) | |
| 2 | 1 | biimpar 297 | 1 ⊢ ((𝐴 = 𝐵 ∧ 𝐵 = 𝐶) → 𝐴 = 𝐶) |
| Colors of variables: wff set class |
| This proof depends on syntax axioms: → wi 4 ∧ wa 104 = wceq 1402 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-5 1500 ax-gen 1502 ax-4 1563 ax-17 1579 ax-ext 2220 |
| This proof depends on definitions: df-bi 117 df-cleq 2231 |
| This theorem is used by: eqtr2 2257 eqtr3 2258 sylan9eq 2291 eqvinc 2949 eqvincg 2950 uneqdifeqim 3613 preqsn 3900 dtruex 4706 relresfld 5317 relcoi1 5319 eqer 6839 xpider 6880 addlsub 8696 uhgr2edg 16447 bj-findis 17005 |
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