Theorem xpeq1d 4705

Description: Equality deduction for cross product. (Contributed by Jeff Madsen, 17-Jun-2010.)

Hypothesis

Ref	Expression
xpeq1d.1	⊢ (𝜑 → 𝐴 = 𝐵)

Assertion

Ref	Expression
xpeq1d	⊢ (𝜑 → (𝐴 × 𝐶) = (𝐵 × 𝐶))

Proof of Theorem xpeq1d

Step	Hyp	Ref	Expression
1		xpeq1d.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		xpeq1 4696	. 2 ⊢ (𝐴 = 𝐵 → (𝐴 × 𝐶) = (𝐵 × 𝐶))
3	1, 2	syl 14	1 ⊢ (𝜑 → (𝐴 × 𝐶) = (𝐵 × 𝐶))

Syntax hints:   → wi 4   = wceq 1373   × cxp 4680

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1471  ax-7 1472  ax-gen 1473  ax-ie1 1517  ax-ie2 1518  ax-8 1528  ax-11 1530  ax-4 1534  ax-17 1550  ax-i9 1554  ax-ial 1558  ax-i5r 1559  ax-ext 2188

This theorem depends on definitions:  df-bi 117  df-tru 1376  df-nf 1485  df-sb 1787  df-clab 2193  df-cleq 2199  df-clel 2202  df-opab 4113  df-xp 4688

This theorem is referenced by:  xpssres  5002  ixpsnf1o  6835  xpfi  7043  hashxp  10988  psrval  14498  mpl0fi  14534  dvmptc  15259