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Mirrors > Home > ILE Home > Th. List > xpeq2d | GIF version |
Description: Equality deduction for cross product. (Contributed by Jeff Madsen, 17-Jun-2010.) |
Ref | Expression |
---|---|
xpeq1d.1 | ⊢ (𝜑 → 𝐴 = 𝐵) |
Ref | Expression |
---|---|
xpeq2d | ⊢ (𝜑 → (𝐶 × 𝐴) = (𝐶 × 𝐵)) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | xpeq1d.1 | . 2 ⊢ (𝜑 → 𝐴 = 𝐵) | |
2 | xpeq2 4549 | . 2 ⊢ (𝐴 = 𝐵 → (𝐶 × 𝐴) = (𝐶 × 𝐵)) | |
3 | 1, 2 | syl 14 | 1 ⊢ (𝜑 → (𝐶 × 𝐴) = (𝐶 × 𝐵)) |
Colors of variables: wff set class |
Syntax hints: → wi 4 = wceq 1331 × cxp 4532 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 105 ax-ia2 106 ax-ia3 107 ax-5 1423 ax-7 1424 ax-gen 1425 ax-ie1 1469 ax-ie2 1470 ax-8 1482 ax-11 1484 ax-4 1487 ax-17 1506 ax-i9 1510 ax-ial 1514 ax-i5r 1515 ax-ext 2119 |
This theorem depends on definitions: df-bi 116 df-tru 1334 df-nf 1437 df-sb 1736 df-clab 2124 df-cleq 2130 df-clel 2133 df-opab 3985 df-xp 4540 |
This theorem is referenced by: csbresg 4817 fconstg 5314 fvdiagfn 6580 mapsncnv 6582 xpsneng 6709 exp3val 10288 reldvg 12806 dvfvalap 12808 |
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