Theorem xpeq2d 4755

Description: Equality deduction for cross product. (Contributed by Jeff Madsen, 17-Jun-2010.)

Hypothesis

Ref	Expression
xpeq1d.1	⊢ (𝜑 → 𝐴 = 𝐵)

Assertion

Ref	Expression
xpeq2d	⊢ (𝜑 → (𝐶 × 𝐴) = (𝐶 × 𝐵))

Proof of Theorem xpeq2d

Step	Hyp	Ref	Expression
1		xpeq1d.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		xpeq2 4746	. 2 ⊢ (𝐴 = 𝐵 → (𝐶 × 𝐴) = (𝐶 × 𝐵))
3	1, 2	syl 14	1 ⊢ (𝜑 → (𝐶 × 𝐴) = (𝐶 × 𝐵))

Syntax hints:   → wi 4   = wceq 1398   × cxp 4729

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-11 1555  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2213

This theorem depends on definitions:  df-bi 117  df-tru 1401  df-nf 1510  df-sb 1811  df-clab 2218  df-cleq 2224  df-clel 2227  df-opab 4156  df-xp 4737

This theorem is referenced by:  csbresg  5022  fconstg  5542  fvdiagfn  6905  mapsncnv  6907  xpsneng  7049  exp3val  10849  mulgval  13772  reldvg  15473  dvfvalap  15475