Theorem xpeq2d 4800

Description: Equality deduction for cross product. (Contributed by Jeff Madsen, 17-Jun-2010.)

Hypothesis

Ref	Expression
xpeq1d.1	⊢ (𝜑 → 𝐴 = 𝐵)

Assertion

Ref	Expression
xpeq2d	⊢ (𝜑 → (𝐶 × 𝐴) = (𝐶 × 𝐵))

Proof of Theorem xpeq2d

Step	Hyp	Ref	Expression
1		xpeq1d.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		xpeq2 4791	. 2 ⊢ (𝐴 = 𝐵 → (𝐶 × 𝐴) = (𝐶 × 𝐵))
3	1, 2	syl 14	1 ⊢ (𝜑 → (𝐶 × 𝐴) = (𝐶 × 𝐵))

This proof depends on syntax axioms:   → wi 4   = wceq 1402   × cxp 4774

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-11 1559  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-ext 2220

This proof depends on definitions:  df-bi 117  df-tru 1405  df-nf 1514  df-sb 1816  df-clab 2225  df-cleq 2231  df-clel 2234  df-opab 4194  df-xp 4782

This theorem is used by:  csbresg  5068  fconstg  5592  fvdiagfn  6979  mapsncnv  6981  xpsneng  7124  exp3val  10999  mulgval  13984  reldvg  15905  dvfvalap  15907