Theorem 3reeanv 3236

Description: Rearrange three restricted existential quantifiers. (Contributed by Jeff Madsen, 11-Jun-2010.)

Assertion

Ref	Expression
3reeanv	⊢ (∃𝑥 ∈ 𝐴 ∃𝑦 ∈ 𝐵 ∃𝑧 ∈ 𝐶 (𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (∃𝑥 ∈ 𝐴 𝜑 ∧ ∃𝑦 ∈ 𝐵 𝜓 ∧ ∃𝑧 ∈ 𝐶 𝜒))

Distinct variable groups:   𝜑,𝑦,𝑧   𝜓,𝑥,𝑧   𝜒,𝑥,𝑦   𝑦,𝐴   𝑥,𝐵,𝑧   𝑥,𝐶,𝑦

Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑦)   𝜒(𝑧)   𝐴(𝑥, 𝑧)   𝐵(𝑦)   𝐶(𝑧)

Proof of Theorem 3reeanv

Step	Hyp	Ref	Expression
1		r19.41v 3193	. . 3 ⊢ (∃𝑥 ∈ 𝐴 (∃𝑦 ∈ 𝐵 (𝜑 ∧ 𝜓) ∧ ∃𝑧 ∈ 𝐶 𝜒) ↔ (∃𝑥 ∈ 𝐴 ∃𝑦 ∈ 𝐵 (𝜑 ∧ 𝜓) ∧ ∃𝑧 ∈ 𝐶 𝜒))
2		reeanv 3235	. . 3 ⊢ (∃𝑥 ∈ 𝐴 ∃𝑦 ∈ 𝐵 (𝜑 ∧ 𝜓) ↔ (∃𝑥 ∈ 𝐴 𝜑 ∧ ∃𝑦 ∈ 𝐵 𝜓))
3	1, 2	bianbi 639	. 2 ⊢ (∃𝑥 ∈ 𝐴 (∃𝑦 ∈ 𝐵 (𝜑 ∧ 𝜓) ∧ ∃𝑧 ∈ 𝐶 𝜒) ↔ ((∃𝑥 ∈ 𝐴 𝜑 ∧ ∃𝑦 ∈ 𝐵 𝜓) ∧ ∃𝑧 ∈ 𝐶 𝜒))
4		df-3an 1105	. . . . 5 ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ ((𝜑 ∧ 𝜓) ∧ 𝜒))
5	4	2rexbii 3139	. . . 4 ⊢ (∃𝑦 ∈ 𝐵 ∃𝑧 ∈ 𝐶 (𝜑 ∧ 𝜓 ∧ 𝜒) ↔ ∃𝑦 ∈ 𝐵 ∃𝑧 ∈ 𝐶 ((𝜑 ∧ 𝜓) ∧ 𝜒))
6		reeanv 3235	. . . 4 ⊢ (∃𝑦 ∈ 𝐵 ∃𝑧 ∈ 𝐶 ((𝜑 ∧ 𝜓) ∧ 𝜒) ↔ (∃𝑦 ∈ 𝐵 (𝜑 ∧ 𝜓) ∧ ∃𝑧 ∈ 𝐶 𝜒))
7	5, 6	bitri 278	. . 3 ⊢ (∃𝑦 ∈ 𝐵 ∃𝑧 ∈ 𝐶 (𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (∃𝑦 ∈ 𝐵 (𝜑 ∧ 𝜓) ∧ ∃𝑧 ∈ 𝐶 𝜒))
8	7	rexbii 3110	. 2 ⊢ (∃𝑥 ∈ 𝐴 ∃𝑦 ∈ 𝐵 ∃𝑧 ∈ 𝐶 (𝜑 ∧ 𝜓 ∧ 𝜒) ↔ ∃𝑥 ∈ 𝐴 (∃𝑦 ∈ 𝐵 (𝜑 ∧ 𝜓) ∧ ∃𝑧 ∈ 𝐶 𝜒))
9		df-3an 1105	. 2 ⊢ ((∃𝑥 ∈ 𝐴 𝜑 ∧ ∃𝑦 ∈ 𝐵 𝜓 ∧ ∃𝑧 ∈ 𝐶 𝜒) ↔ ((∃𝑥 ∈ 𝐴 𝜑 ∧ ∃𝑦 ∈ 𝐵 𝜓) ∧ ∃𝑧 ∈ 𝐶 𝜒))
10	3, 8, 9	3bitr4i 306	1 ⊢ (∃𝑥 ∈ 𝐴 ∃𝑦 ∈ 𝐵 ∃𝑧 ∈ 𝐶 (𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (∃𝑥 ∈ 𝐴 𝜑 ∧ ∃𝑦 ∈ 𝐵 𝜓 ∧ ∃𝑧 ∈ 𝐶 𝜒))

This proof depends on syntax axioms:   ↔ wb 209   ∧ wa 401   ∧ w3a 1103  ∃wrex 3087

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943

This proof depends on definitions:  df-bi 210  df-an 402  df-3an 1105  df-ex 1813  df-ral 3078  df-rex 3088

This theorem is used by:  poxp2  8160  poxp3  8167  imasmnd2  18968  imasgrp2  19265  imasrng  20399  imasring  20560  axeuclid  29541  lshpkrlem6  40172