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| Mirrors > Home > MPE Home > Th. List > bcxmaslem1 | Structured version Visualization version GIF version | ||
| Description: Lemma for bcxmas 15762. (Contributed by Paul Chapman, 18-May-2007.) |
| Ref | Expression |
|---|---|
| bcxmaslem1 | ⊢ (𝐴 = 𝐵 → ((𝑁 + 𝐴)C𝐴) = ((𝑁 + 𝐵)C𝐵)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | oveq2 7368 | . 2 ⊢ (𝐴 = 𝐵 → (𝑁 + 𝐴) = (𝑁 + 𝐵)) | |
| 2 | id 22 | . 2 ⊢ (𝐴 = 𝐵 → 𝐴 = 𝐵) | |
| 3 | 1, 2 | oveq12d 7378 | 1 ⊢ (𝐴 = 𝐵 → ((𝑁 + 𝐴)C𝐴) = ((𝑁 + 𝐵)C𝐵)) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 = wceq 1542 (class class class)co 7360 + caddc 11033 Ccbc 14229 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1797 ax-4 1811 ax-5 1912 ax-6 1969 ax-7 2010 ax-8 2116 ax-9 2124 ax-ext 2709 |
| This theorem depends on definitions: df-bi 207 df-an 396 df-or 849 df-3an 1089 df-tru 1545 df-fal 1555 df-ex 1782 df-sb 2069 df-clab 2716 df-cleq 2729 df-clel 2812 df-rab 3401 df-v 3443 df-dif 3905 df-un 3907 df-ss 3919 df-nul 4287 df-if 4481 df-sn 4582 df-pr 4584 df-op 4588 df-uni 4865 df-br 5100 df-iota 6449 df-fv 6501 df-ov 7363 |
| This theorem is referenced by: bcxmas 15762 sylow1lem1 19531 |
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