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Theorem bj-opabssvv 37355
Description: A variant of relopabiv 5769 (which could be proved from it, similarly to relxp 5642 from xpss 5640). (Contributed by BJ, 28-Dec-2023.)
Assertion
Ref Expression
bj-opabssvv {⟨𝑥, 𝑦⟩ ∣ 𝜑} ⊆ (V × V)
Distinct variable group:   𝑥,𝑦
Allowed substitution hints:   𝜑(𝑥,𝑦)

Proof of Theorem bj-opabssvv
StepHypRef Expression
1 vex 3444 . . . . 5 𝑥 ∈ V
2 vex 3444 . . . . 5 𝑦 ∈ V
31, 2pm3.2i 470 . . . 4 (𝑥 ∈ V ∧ 𝑦 ∈ V)
43a1i 11 . . 3 (𝜑 → (𝑥 ∈ V ∧ 𝑦 ∈ V))
54ssopab2i 5498 . 2 {⟨𝑥, 𝑦⟩ ∣ 𝜑} ⊆ {⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ V ∧ 𝑦 ∈ V)}
6 df-xp 5630 . 2 (V × V) = {⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ V ∧ 𝑦 ∈ V)}
75, 6sseqtrri 3983 1 {⟨𝑥, 𝑦⟩ ∣ 𝜑} ⊆ (V × V)
Colors of variables: wff setvar class
Syntax hints:  wa 395  wcel 2113  Vcvv 3440  wss 3901  {copab 5160   × cxp 5622
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2115  ax-9 2123  ax-ext 2708
This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1544  df-ex 1781  df-sb 2068  df-clab 2715  df-cleq 2728  df-clel 2811  df-v 3442  df-ss 3918  df-opab 5161  df-xp 5630
This theorem is referenced by: (None)
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