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Theorem bj-rep 37312
Description: Version of the axiom of replacement requiring the functional relation in the axiom to be a (total) function from ax-rep 5226 (in the form of axrep6 5235). (Contributed by BJ, 14-Mar-2026.) (Proof modification is discouraged.) (New usage is discouraded.)
Assertion
Ref Expression
bj-rep 𝑥(∀𝑦𝑥 ∃!𝑧𝜑 → ∃𝑡𝑧(𝑧𝑡 ↔ ∃𝑦𝑥 𝜑))
Distinct variable groups:   𝑥,𝑦,𝑧,𝑡   𝜑,𝑥,𝑡
Allowed substitution hints:   𝜑(𝑦,𝑧)

Proof of Theorem bj-rep
StepHypRef Expression
1 df-ral 3053 . . . 4 (∀𝑦𝑥 ∃!𝑧𝜑 ↔ ∀𝑦(𝑦𝑥 → ∃!𝑧𝜑))
2 eumo 2579 . . . . . . 7 (∃!𝑧𝜑 → ∃*𝑧𝜑)
32imim2i 16 . . . . . 6 ((𝑦𝑥 → ∃!𝑧𝜑) → (𝑦𝑥 → ∃*𝑧𝜑))
4 moanimv 2620 . . . . . 6 (∃*𝑧(𝑦𝑥𝜑) ↔ (𝑦𝑥 → ∃*𝑧𝜑))
53, 4sylibr 234 . . . . 5 ((𝑦𝑥 → ∃!𝑧𝜑) → ∃*𝑧(𝑦𝑥𝜑))
65alimi 1813 . . . 4 (∀𝑦(𝑦𝑥 → ∃!𝑧𝜑) → ∀𝑦∃*𝑧(𝑦𝑥𝜑))
71, 6sylbi 217 . . 3 (∀𝑦𝑥 ∃!𝑧𝜑 → ∀𝑦∃*𝑧(𝑦𝑥𝜑))
8 axrep6 5235 . . . 4 (∀𝑦∃*𝑧(𝑦𝑥𝜑) → ∃𝑡𝑧(𝑧𝑡 ↔ ∃𝑦𝑥 (𝑦𝑥𝜑)))
9 rexanid 3087 . . . . . . 7 (∃𝑦𝑥 (𝑦𝑥𝜑) ↔ ∃𝑦𝑥 𝜑)
109bibi2i 337 . . . . . 6 ((𝑧𝑡 ↔ ∃𝑦𝑥 (𝑦𝑥𝜑)) ↔ (𝑧𝑡 ↔ ∃𝑦𝑥 𝜑))
1110albii 1821 . . . . 5 (∀𝑧(𝑧𝑡 ↔ ∃𝑦𝑥 (𝑦𝑥𝜑)) ↔ ∀𝑧(𝑧𝑡 ↔ ∃𝑦𝑥 𝜑))
1211exbii 1850 . . . 4 (∃𝑡𝑧(𝑧𝑡 ↔ ∃𝑦𝑥 (𝑦𝑥𝜑)) ↔ ∃𝑡𝑧(𝑧𝑡 ↔ ∃𝑦𝑥 𝜑))
138, 12sylib 218 . . 3 (∀𝑦∃*𝑧(𝑦𝑥𝜑) → ∃𝑡𝑧(𝑧𝑡 ↔ ∃𝑦𝑥 𝜑))
147, 13syl 17 . 2 (∀𝑦𝑥 ∃!𝑧𝜑 → ∃𝑡𝑧(𝑧𝑡 ↔ ∃𝑦𝑥 𝜑))
1514ax-gen 1797 1 𝑥(∀𝑦𝑥 ∃!𝑧𝜑 → ∃𝑡𝑧(𝑧𝑡 ↔ ∃𝑦𝑥 𝜑))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206  wa 395  wal 1540  wex 1781  ∃*wmo 2538  ∃!weu 2569  wral 3052  wrex 3062
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-rep 5226
This theorem depends on definitions:  df-bi 207  df-an 396  df-ex 1782  df-mo 2540  df-eu 2570  df-ral 3053  df-rex 3063
This theorem is referenced by: (None)
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