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Theorem clublem 44554
Description: If a superset 𝑌 of 𝑋 possesses the property parameterized in 𝑥 in 𝜓, then 𝑌 is a superset of the closure of that property for the set 𝑋. (Contributed by RP, 23-Jul-2020.)
Hypotheses
Ref Expression
clublem.y (𝜑 → 𝑌 ∈ V)
clublem.sub (𝑥 = 𝑌 → (𝜓 ↔ 𝜒))
clublem.sup (𝜑 → 𝑋 ⊆ 𝑌)
clublem.maj (𝜑 → 𝜒)
Assertion
Ref Expression
clublem (𝜑 → ∩ {𝑥 ∣ (𝑋 ⊆ 𝑥 ∧ 𝜓)} ⊆ 𝑌)
Distinct variable groups:   𝜒,𝑥   𝑥,𝑋   𝑥,𝑌
Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑥)

Proof of Theorem clublem
StepHypRef Expression
1 clublem.sup . . 3 (𝜑 → 𝑋 ⊆ 𝑌)
2 clublem.maj . . 3 (𝜑 → 𝜒)
3 clublem.y . . . . 5 (𝜑 → 𝑌 ∈ V)
43a1d 26 . . . 4 (𝜑 → ((𝑋 ⊆ 𝑌 ∧ 𝜒) → 𝑌 ∈ V))
5 clublem.sub . . . . . 6 (𝑥 = 𝑌 → (𝜓 ↔ 𝜒))
65cleq2lem 44552 . . . . 5 (𝑥 = 𝑌 → ((𝑋 ⊆ 𝑥 ∧ 𝜓) ↔ (𝑋 ⊆ 𝑌 ∧ 𝜒)))
76elab3g 3638 . . . 4 (((𝑋 ⊆ 𝑌 ∧ 𝜒) → 𝑌 ∈ V) → (𝑌 ∈ {𝑥 ∣ (𝑋 ⊆ 𝑥 ∧ 𝜓)} ↔ (𝑋 ⊆ 𝑌 ∧ 𝜒)))
84, 7syl 18 . . 3 (𝜑 → (𝑌 ∈ {𝑥 ∣ (𝑋 ⊆ 𝑥 ∧ 𝜓)} ↔ (𝑋 ⊆ 𝑌 ∧ 𝜒)))
91, 2, 8mpbir2and 726 . 2 (𝜑 → 𝑌 ∈ {𝑥 ∣ (𝑋 ⊆ 𝑥 ∧ 𝜓)})
10 intss1 4922 . 2 (𝑌 ∈ {𝑥 ∣ (𝑋 ⊆ 𝑥 ∧ 𝜓)} → ∩ {𝑥 ∣ (𝑋 ⊆ 𝑥 ∧ 𝜓)} ⊆ 𝑌)
119, 10syl 18 1 (𝜑 → ∩ {𝑥 ∣ (𝑋 ⊆ 𝑥 ∧ 𝜓)} ⊆ 𝑌)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1570   ∈ wcel 2145  {cab 2738  Vcvv 3450   ⊆ wss 3898  ∩ cint 4906
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-v 3452  df-ss 3915  df-int 4907
This theorem is used by:  mptrcllem  44557  trclubgNEW  44562
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