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| Mirrors > Home > MPE Home > Th. List > Mathboxes > compne | Structured version Visualization version GIF version | ||
| Description: The complement of 𝐴 is not equal to 𝐴. (Contributed by Andrew Salmon, 15-Jul-2011.) (Proof shortened by BJ, 11-Nov-2021.) |
| Ref | Expression |
|---|---|
| compne | ⊢ (V ∖ 𝐴) ≠ 𝐴 |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | vn0 4295 | . 2 ⊢ V ≠ ∅ | |
| 2 | id 22 | . . . . . . 7 ⊢ ((V ∖ 𝐴) = 𝐴 → (V ∖ 𝐴) = 𝐴) | |
| 3 | difeq1 4069 | . . . . . . . 8 ⊢ ((V ∖ 𝐴) = 𝐴 → ((V ∖ 𝐴) ∖ 𝐴) = (𝐴 ∖ 𝐴)) | |
| 4 | difabs 4253 | . . . . . . . 8 ⊢ ((V ∖ 𝐴) ∖ 𝐴) = (V ∖ 𝐴) | |
| 5 | difid 4326 | . . . . . . . 8 ⊢ (𝐴 ∖ 𝐴) = ∅ | |
| 6 | 3, 4, 5 | 3eqtr3g 2789 | . . . . . . 7 ⊢ ((V ∖ 𝐴) = 𝐴 → (V ∖ 𝐴) = ∅) |
| 7 | 2, 6 | eqtr3d 2768 | . . . . . 6 ⊢ ((V ∖ 𝐴) = 𝐴 → 𝐴 = ∅) |
| 8 | 7 | difeq2d 4076 | . . . . 5 ⊢ ((V ∖ 𝐴) = 𝐴 → (V ∖ 𝐴) = (V ∖ ∅)) |
| 9 | dif0 4328 | . . . . 5 ⊢ (V ∖ ∅) = V | |
| 10 | 8, 9 | eqtrdi 2782 | . . . 4 ⊢ ((V ∖ 𝐴) = 𝐴 → (V ∖ 𝐴) = V) |
| 11 | 10, 6 | eqtr3d 2768 | . . 3 ⊢ ((V ∖ 𝐴) = 𝐴 → V = ∅) |
| 12 | 11 | necon3i 2960 | . 2 ⊢ (V ≠ ∅ → (V ∖ 𝐴) ≠ 𝐴) |
| 13 | 1, 12 | ax-mp 5 | 1 ⊢ (V ∖ 𝐴) ≠ 𝐴 |
| Colors of variables: wff setvar class |
| Syntax hints: = wceq 1541 ≠ wne 2928 Vcvv 3436 ∖ cdif 3899 ∅c0 4283 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1796 ax-4 1810 ax-5 1911 ax-6 1968 ax-7 2009 ax-8 2113 ax-9 2121 ax-ext 2703 |
| This theorem depends on definitions: df-bi 207 df-an 396 df-or 848 df-tru 1544 df-fal 1554 df-ex 1781 df-sb 2068 df-clab 2710 df-cleq 2723 df-clel 2806 df-ne 2929 df-rab 3396 df-v 3438 df-dif 3905 df-un 3907 df-in 3909 df-nul 4284 |
| This theorem is referenced by: (None) |
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