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| Mirrors > Home > MPE Home > Th. List > Mathboxes > compne | Structured version Visualization version GIF version | ||
| Description: The complement of 𝐴 is not equal to 𝐴. (Contributed by Andrew Salmon, 15-Jul-2011.) (Proof shortened by BJ, 11-Nov-2021.) |
| Ref | Expression |
|---|---|
| compne | ⊢ (V ∖ 𝐴) ≠ 𝐴 |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | vn0 4300 | . 2 ⊢ V ≠ ∅ | |
| 2 | id 23 | . . . . . . 7 ⊢ ((V ∖ 𝐴) = 𝐴 → (V ∖ 𝐴) = 𝐴) | |
| 3 | difeq1 4076 | . . . . . . . 8 ⊢ ((V ∖ 𝐴) = 𝐴 → ((V ∖ 𝐴) ∖ 𝐴) = (𝐴 ∖ 𝐴)) | |
| 4 | difabs 4258 | . . . . . . . 8 ⊢ ((V ∖ 𝐴) ∖ 𝐴) = (V ∖ 𝐴) | |
| 5 | difid 4332 | . . . . . . . 8 ⊢ (𝐴 ∖ 𝐴) = ∅ | |
| 6 | 3, 4, 5 | 3eqtr3g 2823 | . . . . . . 7 ⊢ ((V ∖ 𝐴) = 𝐴 → (V ∖ 𝐴) = ∅) |
| 7 | 2, 6 | eqtr3d 2802 | . . . . . 6 ⊢ ((V ∖ 𝐴) = 𝐴 → 𝐴 = ∅) |
| 8 | 7 | difeq2d 4083 | . . . . 5 ⊢ ((V ∖ 𝐴) = 𝐴 → (V ∖ 𝐴) = (V ∖ ∅)) |
| 9 | dif0 4334 | . . . . 5 ⊢ (V ∖ ∅) = V | |
| 10 | 8, 9 | eqtrdi 2816 | . . . 4 ⊢ ((V ∖ 𝐴) = 𝐴 → (V ∖ 𝐴) = V) |
| 11 | 10, 6 | eqtr3d 2802 | . . 3 ⊢ ((V ∖ 𝐴) = 𝐴 → V = ∅) |
| 12 | 11 | necon3i 2992 | . 2 ⊢ (V ≠ ∅ → (V ∖ 𝐴) ≠ 𝐴) |
| 13 | 1, 12 | ax-mp 5 | 1 ⊢ (V ∖ 𝐴) ≠ 𝐴 |
| Colors of variables: wff setvar class |
| Syntax hints: = wceq 1563 ≠ wne 2960 Vcvv 3457 ∖ cdif 3904 ∅c0 4288 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1818 ax-4 1832 ax-5 1933 ax-6 1990 ax-7 2031 ax-8 2147 ax-9 2155 ax-ext 2737 |
| This theorem depends on definitions: df-bi 210 df-an 401 df-or 861 df-tru 1566 df-fal 1576 df-ex 1803 df-sb 2094 df-clab 2744 df-cleq 2757 df-clel 2840 df-ne 2961 df-rab 3418 df-v 3459 df-dif 3910 df-un 3912 df-in 3914 df-nul 4289 |
| This theorem is referenced by: (None) |
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