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| Mirrors > Home > MPE Home > Th. List > Mathboxes > functermclem | Structured version Visualization version GIF version | ||
| Description: Lemma for functermc 49540. (Contributed by Zhi Wang, 17-Oct-2025.) |
| Ref | Expression |
|---|---|
| functermclem.1 | ⊢ ((𝜑 ∧ 𝐾𝑅𝐿) → 𝐾 = 𝐹) |
| functermclem.2 | ⊢ (𝜑 → (𝐹𝑅𝐿 ↔ 𝐿 = 𝐺)) |
| Ref | Expression |
|---|---|
| functermclem | ⊢ (𝜑 → (𝐾𝑅𝐿 ↔ (𝐾 = 𝐹 ∧ 𝐿 = 𝐺))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | functermclem.1 | . . 3 ⊢ ((𝜑 ∧ 𝐾𝑅𝐿) → 𝐾 = 𝐹) | |
| 2 | simpr 484 | . . . . 5 ⊢ ((𝜑 ∧ 𝐾𝑅𝐿) → 𝐾𝑅𝐿) | |
| 3 | 1, 2 | eqbrtrrd 5110 | . . . 4 ⊢ ((𝜑 ∧ 𝐾𝑅𝐿) → 𝐹𝑅𝐿) |
| 4 | functermclem.2 | . . . . 5 ⊢ (𝜑 → (𝐹𝑅𝐿 ↔ 𝐿 = 𝐺)) | |
| 5 | 4 | biimpa 476 | . . . 4 ⊢ ((𝜑 ∧ 𝐹𝑅𝐿) → 𝐿 = 𝐺) |
| 6 | 3, 5 | syldan 591 | . . 3 ⊢ ((𝜑 ∧ 𝐾𝑅𝐿) → 𝐿 = 𝐺) |
| 7 | 1, 6 | jca 511 | . 2 ⊢ ((𝜑 ∧ 𝐾𝑅𝐿) → (𝐾 = 𝐹 ∧ 𝐿 = 𝐺)) |
| 8 | simprl 770 | . . 3 ⊢ ((𝜑 ∧ (𝐾 = 𝐹 ∧ 𝐿 = 𝐺)) → 𝐾 = 𝐹) | |
| 9 | 4 | biimpar 477 | . . . 4 ⊢ ((𝜑 ∧ 𝐿 = 𝐺) → 𝐹𝑅𝐿) |
| 10 | 9 | adantrl 716 | . . 3 ⊢ ((𝜑 ∧ (𝐾 = 𝐹 ∧ 𝐿 = 𝐺)) → 𝐹𝑅𝐿) |
| 11 | 8, 10 | eqbrtrd 5108 | . 2 ⊢ ((𝜑 ∧ (𝐾 = 𝐹 ∧ 𝐿 = 𝐺)) → 𝐾𝑅𝐿) |
| 12 | 7, 11 | impbida 800 | 1 ⊢ (𝜑 → (𝐾𝑅𝐿 ↔ (𝐾 = 𝐹 ∧ 𝐿 = 𝐺))) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 ↔ wb 206 ∧ wa 395 = wceq 1541 class class class wbr 5086 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1796 ax-4 1810 ax-5 1911 ax-6 1968 ax-7 2009 ax-8 2113 ax-9 2121 ax-ext 2703 |
| This theorem depends on definitions: df-bi 207 df-an 396 df-or 848 df-3an 1088 df-tru 1544 df-fal 1554 df-ex 1781 df-sb 2068 df-clab 2710 df-cleq 2723 df-clel 2806 df-rab 3396 df-v 3438 df-dif 3900 df-un 3902 df-ss 3914 df-nul 4279 df-if 4471 df-sn 4572 df-pr 4574 df-op 4578 df-br 5087 |
| This theorem is referenced by: functermc 49540 |
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