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Theorem mppspstlem 36422
Description: Lemma for mppspst 36425. (Contributed by Mario Carneiro, 18-Jul-2016.)
Hypotheses
Ref Expression
mppsval.p 𝑃 = (mPreSt‘𝑇)
mppsval.j 𝐽 = (mPPSt‘𝑇)
mppsval.c 𝐶 = (mCls‘𝑇)
Assertion
Ref Expression
mppspstlem {⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∣ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ))} ⊆ 𝑃
Distinct variable groups:   𝑎,𝑑,ℎ,𝐶   𝑃,𝑎,𝑑,ℎ   𝑇,𝑎,𝑑,ℎ
Allowed substitution hints:   𝐽(ℎ, 𝑎, 𝑑)

Proof of Theorem mppspstlem
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 df-oprab 7424 . 2 {⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∣ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ))} = {𝑥 ∣ ∃𝑑∃ℎ∃𝑎(𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∧ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ)))}
2 df-ot 4858 . . . . . . . . . 10 ⟨𝑑, ℎ, 𝑎⟩ = ⟨⟨𝑑, ℎ⟩, 𝑎⟩
32eqeq2i 2773 . . . . . . . . 9 (𝑥 = ⟨𝑑, ℎ, 𝑎⟩ ↔ 𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩)
43biimpri 231 . . . . . . . 8 (𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ → 𝑥 = ⟨𝑑, ℎ, 𝑎⟩)
54eleq1d 2845 . . . . . . 7 (𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ → (𝑥 ∈ 𝑃 ↔ ⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃))
65biimpar 483 . . . . . 6 ((𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∧ ⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃) → 𝑥 ∈ 𝑃)
76adantrr 730 . . . . 5 ((𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∧ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ))) → 𝑥 ∈ 𝑃)
87exlimiv 1962 . . . 4 (∃𝑎(𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∧ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ))) → 𝑥 ∈ 𝑃)
98exlimivv 1964 . . 3 (∃𝑑∃ℎ∃𝑎(𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∧ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ))) → 𝑥 ∈ 𝑃)
109abssi 3993 . 2 {𝑥 ∣ ∃𝑑∃ℎ∃𝑎(𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∧ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ)))} ⊆ 𝑃
111, 10eqsstri 3954 1 {⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∣ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ))} ⊆ 𝑃
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ∧ wa 401   = wceq 1569  ∃wex 1811   ∈ wcel 2144  {cab 2738   ⊆ wss 3895  ⟨cop 4834  ⟨cotp 4857  ‘cfv 6538  (class class class)co 7420  {coprab 7421  mPreStcmpst 36324  mClscmcls 36328  mPPStcmpps 36329
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1572  df-ex 1812  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-ss 3896  df-ot 4858  df-oprab 7424
This theorem is used by:  mppsval  36423  mppspst  36425
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