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Theorem mppspstlem 36516
Description: Lemma for mppspst 36519. (Contributed by Mario Carneiro, 18-Jul-2016.)
Hypotheses
Ref Expression
mppsval.p 𝑃 = (mPreSt‘𝑇)
mppsval.j 𝐽 = (mPPSt‘𝑇)
mppsval.c 𝐶 = (mCls‘𝑇)
Assertion
Ref Expression
mppspstlem {⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∣ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ))} ⊆ 𝑃
Distinct variable groups:   𝑎,𝑑,ℎ,𝐶   𝑃,𝑎,𝑑,ℎ   𝑇,𝑎,𝑑,ℎ
Allowed substitution hints:   𝐽(ℎ, 𝑎, 𝑑)

Proof of Theorem mppspstlem
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 df-oprab 7450 . 2 {⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∣ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ))} = {𝑥 ∣ ∃𝑑∃ℎ∃𝑎(𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∧ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ)))}
2 df-ot 4862 . . . . . . . . . 10 ⟨𝑑, ℎ, 𝑎⟩ = ⟨⟨𝑑, ℎ⟩, 𝑎⟩
32eqeq2i 2776 . . . . . . . . 9 (𝑥 = ⟨𝑑, ℎ, 𝑎⟩ ↔ 𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩)
43biimpri 231 . . . . . . . 8 (𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ → 𝑥 = ⟨𝑑, ℎ, 𝑎⟩)
54eleq1d 2849 . . . . . . 7 (𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ → (𝑥 ∈ 𝑃 ↔ ⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃))
65biimpar 483 . . . . . 6 ((𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∧ ⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃) → 𝑥 ∈ 𝑃)
76adantrr 730 . . . . 5 ((𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∧ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ))) → 𝑥 ∈ 𝑃)
87exlimiv 1965 . . . 4 (∃𝑎(𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∧ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ))) → 𝑥 ∈ 𝑃)
98exlimivv 1967 . . 3 (∃𝑑∃ℎ∃𝑎(𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∧ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ))) → 𝑥 ∈ 𝑃)
109abssi 3996 . 2 {𝑥 ∣ ∃𝑑∃ℎ∃𝑎(𝑥 = ⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∧ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ)))} ⊆ 𝑃
111, 10eqsstri 3959 1 {⟨⟨𝑑, ℎ⟩, 𝑎⟩ ∣ (⟨𝑑, ℎ, 𝑎⟩ ∈ 𝑃 ∧ 𝑎 ∈ (𝑑𝐶ℎ))} ⊆ 𝑃
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ∧ wa 401   = wceq 1570  ∃wex 1812   ∈ wcel 2147  {cab 2741   ⊆ wss 3900  ⟨cop 4838  ⟨cotp 4861  ‘cfv 6561  (class class class)co 7446  {coprab 7447  mPreStcmpst 36418  mClscmcls 36422  mPPStcmpps 36423
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-ss 3901  df-ot 4862  df-oprab 7450
This theorem is used by:  mppsval  36517  mppspst  36519
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