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Theorem prsspwg 4791
Description: An unordered pair belongs to the power class of a class iff each member belongs to the class. (Contributed by Thierry Arnoux, 3-Oct-2016.) (Revised by NM, 18-Jan-2018.)
Assertion
Ref Expression
prsspwg ((𝐴𝑉𝐵𝑊) → ({𝐴, 𝐵} ⊆ 𝒫 𝐶 ↔ (𝐴𝐶𝐵𝐶)))

Proof of Theorem prsspwg
StepHypRef Expression
1 prssg 4787 . 2 ((𝐴𝑉𝐵𝑊) → ((𝐴 ∈ 𝒫 𝐶𝐵 ∈ 𝒫 𝐶) ↔ {𝐴, 𝐵} ⊆ 𝒫 𝐶))
2 elpwg 4567 . . 3 (𝐴𝑉 → (𝐴 ∈ 𝒫 𝐶𝐴𝐶))
3 elpwg 4567 . . 3 (𝐵𝑊 → (𝐵 ∈ 𝒫 𝐶𝐵𝐶))
42, 3bi2anan9 650 . 2 ((𝐴𝑉𝐵𝑊) → ((𝐴 ∈ 𝒫 𝐶𝐵 ∈ 𝒫 𝐶) ↔ (𝐴𝐶𝐵𝐶)))
51, 4bitr3d 284 1 ((𝐴𝑉𝐵𝑊) → ({𝐴, 𝐵} ⊆ 𝒫 𝐶 ↔ (𝐴𝐶𝐵𝐶)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4  wb 209  wa 401  wcel 2146  wss 3906  𝒫 cpw 4564  {cpr 4593
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-ext 2737
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2744  df-cleq 2757  df-clel 2840  df-v 3459  df-un 3911  df-ss 3923  df-pw 4566  df-sn 4592  df-pr 4594
This theorem is used by:  prsspw  4812
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