MPE Home Metamath Proof Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >  prssg Structured version   Visualization version   GIF version

Theorem prssg 4786
Description: A pair of elements of a class is a subset of the class. Theorem 7.5 of [Quine] p. 49. (Contributed by NM, 22-Mar-2006.) (Proof shortened by Andrew Salmon, 29-Jun-2011.)
Assertion
Ref Expression
prssg ((𝐴𝑉𝐵𝑊) → ((𝐴𝐶𝐵𝐶) ↔ {𝐴, 𝐵} ⊆ 𝐶))

Proof of Theorem prssg
StepHypRef Expression
1 snssg 4750 . . 3 (𝐴𝑉 → (𝐴𝐶 ↔ {𝐴} ⊆ 𝐶))
2 snssg 4750 . . 3 (𝐵𝑊 → (𝐵𝐶 ↔ {𝐵} ⊆ 𝐶))
31, 2bi2anan9 638 . 2 ((𝐴𝑉𝐵𝑊) → ((𝐴𝐶𝐵𝐶) ↔ ({𝐴} ⊆ 𝐶 ∧ {𝐵} ⊆ 𝐶)))
4 unss 4156 . . 3 (({𝐴} ⊆ 𝐶 ∧ {𝐵} ⊆ 𝐶) ↔ ({𝐴} ∪ {𝐵}) ⊆ 𝐶)
5 df-pr 4595 . . . 4 {𝐴, 𝐵} = ({𝐴} ∪ {𝐵})
65sseq1i 3978 . . 3 ({𝐴, 𝐵} ⊆ 𝐶 ↔ ({𝐴} ∪ {𝐵}) ⊆ 𝐶)
74, 6bitr4i 278 . 2 (({𝐴} ⊆ 𝐶 ∧ {𝐵} ⊆ 𝐶) ↔ {𝐴, 𝐵} ⊆ 𝐶)
83, 7bitrdi 287 1 ((𝐴𝑉𝐵𝑊) → ((𝐴𝐶𝐵𝐶) ↔ {𝐴, 𝐵} ⊆ 𝐶))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206  wa 395  wcel 2109  cun 3915  wss 3917  {csn 4592  {cpr 4594
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-ext 2702
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-tru 1543  df-ex 1780  df-sb 2066  df-clab 2709  df-cleq 2722  df-clel 2804  df-v 3452  df-un 3922  df-ss 3934  df-sn 4593  df-pr 4595
This theorem is referenced by:  prss  4787  prssi  4788  prsspwg  4790  ssprss  4791  prelpw  5409  hashdmpropge2  14455  lspvadd  21010  umgredgprv  29041  usgredgprvALT  29129  dfnbgr2  29271  nbuhgr  29277  uhgrnbgr0nb  29288  2wlkdlem6  29868  1wlkdlem2  30074  prssad  32465  prssbd  32466  tpssg  32473  coss0  38477  dihmeetlem2N  41300  mnuprdlem2  44269  fourierdlem20  46132  fourierdlem50  46161  fourierdlem54  46165  fourierdlem64  46175  fourierdlem76  46187  omeunle  46521  dfclnbgr2  47828  dfsclnbgr2  47850  dfvopnbgr2  47857  isubgr3stgrlem7  47975
  Copyright terms: Public domain W3C validator