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Theorem rmoeq1 3400
Description: Equality theorem for restricted at-most-one quantifier. (Contributed by Alexander van der Vekens, 17-Jun-2017.) Remove usage of ax-10 2176, ax-11 2192, and ax-12 2213. (Revised by Steven Nguyen, 30-Apr-2023.) Avoid ax-8 2145. (Revised by Wolf Lammen, 12-Mar-2025.)
Assertion
Ref Expression
rmoeq1 (𝐴 = 𝐵 → (∃*𝑥𝐴 𝜑 ↔ ∃*𝑥𝐵 𝜑))
Distinct variable groups:   𝑥,𝐴   𝑥,𝐵
Allowed substitution hint:   𝜑(𝑥)

Proof of Theorem rmoeq1
Dummy variable 𝑧 is distinct from all other variables.
StepHypRef Expression
1 dfcleq 2756 . . . . . 6 (𝐴 = 𝐵 ↔ ∀𝑥(𝑥𝐴𝑥𝐵))
21biimpi 219 . . . . 5 (𝐴 = 𝐵 → ∀𝑥(𝑥𝐴𝑥𝐵))
3 anbi1 644 . . . . . . 7 ((𝑥𝐴𝑥𝐵) → ((𝑥𝐴𝜑) ↔ (𝑥𝐵𝜑)))
43imbi1d 344 . . . . . 6 ((𝑥𝐴𝑥𝐵) → (((𝑥𝐴𝜑) → 𝑥 = 𝑧) ↔ ((𝑥𝐵𝜑) → 𝑥 = 𝑧)))
54alimi 1841 . . . . 5 (∀𝑥(𝑥𝐴𝑥𝐵) → ∀𝑥(((𝑥𝐴𝜑) → 𝑥 = 𝑧) ↔ ((𝑥𝐵𝜑) → 𝑥 = 𝑧)))
6 albi 1848 . . . . 5 (∀𝑥(((𝑥𝐴𝜑) → 𝑥 = 𝑧) ↔ ((𝑥𝐵𝜑) → 𝑥 = 𝑧)) → (∀𝑥((𝑥𝐴𝜑) → 𝑥 = 𝑧) ↔ ∀𝑥((𝑥𝐵𝜑) → 𝑥 = 𝑧)))
72, 5, 63syl 19 . . . 4 (𝐴 = 𝐵 → (∀𝑥((𝑥𝐴𝜑) → 𝑥 = 𝑧) ↔ ∀𝑥((𝑥𝐵𝜑) → 𝑥 = 𝑧)))
87exbidv 1951 . . 3 (𝐴 = 𝐵 → (∃𝑧𝑥((𝑥𝐴𝜑) → 𝑥 = 𝑧) ↔ ∃𝑧𝑥((𝑥𝐵𝜑) → 𝑥 = 𝑧)))
9 dfmo 2568 . . 3 (∃*𝑥(𝑥𝐴𝜑) ↔ ∃𝑧𝑥((𝑥𝐴𝜑) → 𝑥 = 𝑧))
10 dfmo 2568 . . 3 (∃*𝑥(𝑥𝐵𝜑) ↔ ∃𝑧𝑥((𝑥𝐵𝜑) → 𝑥 = 𝑧))
118, 9, 103bitr4g 317 . 2 (𝐴 = 𝐵 → (∃*𝑥(𝑥𝐴𝜑) ↔ ∃*𝑥(𝑥𝐵𝜑)))
12 df-rmo 3369 . 2 (∃*𝑥𝐴 𝜑 ↔ ∃*𝑥(𝑥𝐴𝜑))
13 df-rmo 3369 . 2 (∃*𝑥𝐵 𝜑 ↔ ∃*𝑥(𝑥𝐵𝜑))
1411, 12, 133bitr4g 317 1 (𝐴 = 𝐵 → (∃*𝑥𝐴 𝜑 ↔ ∃*𝑥𝐵 𝜑))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 209  wa 400  wal 1568   = wceq 1570  wex 1809  wcel 2143  ∃*wmo 2565  ∃*wrmo 3368
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-9 2153  ax-ext 2735
This theorem depends on definitions:  df-bi 210  df-an 401  df-ex 1810  df-mo 2567  df-cleq 2755  df-rmo 3369
This theorem is referenced by:  reueq1  3401  rmoeqd  3402  rmosn  4685  rmoeqdv  36744  poimirlem2  38293
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