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Theorem rmoeq1 3402
Description: Equality theorem for restricted at-most-one quantifier. (Contributed by Alexander van der Vekens, 17-Jun-2017.) Remove usage of ax-10 2179, ax-11 2195, and ax-12 2216. (Revised by Steven Nguyen, 30-Apr-2023.) Avoid ax-8 2148. (Revised by Wolf Lammen, 12-Mar-2025.)
Assertion
Ref Expression
rmoeq1 (𝐴 = 𝐵 → (∃*𝑥𝐴 𝜑 ↔ ∃*𝑥𝐵 𝜑))
Distinct variable groups:   𝑥,𝐴   𝑥,𝐵
Allowed substitution hint:   𝜑(𝑥)

Proof of Theorem rmoeq1
Dummy variable 𝑧 is distinct from all other variables.
StepHypRef Expression
1 dfcleq 2758 . . . . . 6 (𝐴 = 𝐵 ↔ ∀𝑥(𝑥𝐴𝑥𝐵))
21biimpi 219 . . . . 5 (𝐴 = 𝐵 → ∀𝑥(𝑥𝐴𝑥𝐵))
3 anbi1 645 . . . . . . 7 ((𝑥𝐴𝑥𝐵) → ((𝑥𝐴𝜑) ↔ (𝑥𝐵𝜑)))
43imbi1d 344 . . . . . 6 ((𝑥𝐴𝑥𝐵) → (((𝑥𝐴𝜑) → 𝑥 = 𝑧) ↔ ((𝑥𝐵𝜑) → 𝑥 = 𝑧)))
54alimi 1844 . . . . 5 (∀𝑥(𝑥𝐴𝑥𝐵) → ∀𝑥(((𝑥𝐴𝜑) → 𝑥 = 𝑧) ↔ ((𝑥𝐵𝜑) → 𝑥 = 𝑧)))
6 albi 1851 . . . . 5 (∀𝑥(((𝑥𝐴𝜑) → 𝑥 = 𝑧) ↔ ((𝑥𝐵𝜑) → 𝑥 = 𝑧)) → (∀𝑥((𝑥𝐴𝜑) → 𝑥 = 𝑧) ↔ ∀𝑥((𝑥𝐵𝜑) → 𝑥 = 𝑧)))
72, 5, 63syl 19 . . . 4 (𝐴 = 𝐵 → (∀𝑥((𝑥𝐴𝜑) → 𝑥 = 𝑧) ↔ ∀𝑥((𝑥𝐵𝜑) → 𝑥 = 𝑧)))
87exbidv 1954 . . 3 (𝐴 = 𝐵 → (∃𝑧𝑥((𝑥𝐴𝜑) → 𝑥 = 𝑧) ↔ ∃𝑧𝑥((𝑥𝐵𝜑) → 𝑥 = 𝑧)))
9 dfmo 2570 . . 3 (∃*𝑥(𝑥𝐴𝜑) ↔ ∃𝑧𝑥((𝑥𝐴𝜑) → 𝑥 = 𝑧))
10 dfmo 2570 . . 3 (∃*𝑥(𝑥𝐵𝜑) ↔ ∃𝑧𝑥((𝑥𝐵𝜑) → 𝑥 = 𝑧))
118, 9, 103bitr4g 317 . 2 (𝐴 = 𝐵 → (∃*𝑥(𝑥𝐴𝜑) ↔ ∃*𝑥(𝑥𝐵𝜑)))
12 df-rmo 3371 . 2 (∃*𝑥𝐴 𝜑 ↔ ∃*𝑥(𝑥𝐴𝜑))
13 df-rmo 3371 . 2 (∃*𝑥𝐵 𝜑 ↔ ∃*𝑥(𝑥𝐵𝜑))
1411, 12, 133bitr4g 317 1 (𝐴 = 𝐵 → (∃*𝑥𝐴 𝜑 ↔ ∃*𝑥𝐵 𝜑))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4  wb 209  wa 401  wal 1568   = wceq 1570  wex 1812  wcel 2146  ∃*wmo 2567  ∃*wrmo 3370
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-9 2156  ax-ext 2737
This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-mo 2569  df-cleq 2757  df-rmo 3371
This theorem is used by:  reueq1  3403  rmoeqd  3404  rmosn  4687  rmoeqdv  36783  poimirlem2  38332
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