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Theorem sbn 2317
Description: Negation inside and outside of substitution are equivalent. (Contributed by NM, 14-May-1993.) (Proof shortened by Wolf Lammen, 30-Apr-2018.) Revise df-sb 2100. (Revised by BJ, 25-Dec-2020.)
Assertion
Ref Expression
sbn ([𝑡 / 𝑥] ¬ 𝜑 ↔ ¬ [𝑡 / 𝑥]𝜑)

Proof of Theorem sbn
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 dfsb 2101 . 2 ([𝑡 / 𝑥] ¬ 𝜑 ↔ ∀𝑦(𝑦 = 𝑡 → ∀𝑥(𝑥 = 𝑦 → ¬ 𝜑)))
2 alinexa 1876 . . . 4 (∀𝑥(𝑥 = 𝑦 → ¬ 𝜑) ↔ ¬ ∃𝑥(𝑥 = 𝑦𝜑))
32imbi2i 339 . . 3 ((𝑦 = 𝑡 → ∀𝑥(𝑥 = 𝑦 → ¬ 𝜑)) ↔ (𝑦 = 𝑡 → ¬ ∃𝑥(𝑥 = 𝑦𝜑)))
43albii 1852 . 2 (∀𝑦(𝑦 = 𝑡 → ∀𝑥(𝑥 = 𝑦 → ¬ 𝜑)) ↔ ∀𝑦(𝑦 = 𝑡 → ¬ ∃𝑥(𝑥 = 𝑦𝜑)))
5 alinexa 1876 . . 3 (∀𝑦(𝑦 = 𝑡 → ¬ ∃𝑥(𝑥 = 𝑦𝜑)) ↔ ¬ ∃𝑦(𝑦 = 𝑡 ∧ ∃𝑥(𝑥 = 𝑦𝜑)))
6 dfsb7 2316 . . 3 ([𝑡 / 𝑥]𝜑 ↔ ∃𝑦(𝑦 = 𝑡 ∧ ∃𝑥(𝑥 = 𝑦𝜑)))
75, 6xchbinxr 338 . 2 (∀𝑦(𝑦 = 𝑡 → ¬ ∃𝑥(𝑥 = 𝑦𝜑)) ↔ ¬ [𝑡 / 𝑥]𝜑)
81, 4, 73bitri 300 1 ([𝑡 / 𝑥] ¬ 𝜑 ↔ ¬ [𝑡 / 𝑥]𝜑)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3  wi 4  wb 209  wa 401  wal 1568  wex 1812  [wsb 2099
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-10 2179  ax-12 2216
This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-nf 1817  df-sb 2100
This theorem is used by:  sbex  2318  sbi2  2339  sbor  2343  sbcng  3793  difab  4263  difopab  5819  wl-sb8eft  38265  wl-sb8et  38267  pm13.196a  45184  ichn  48265
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