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Theorem symdifass 4207
Description: Symmetric difference is associative. (Contributed by Scott Fenton, 24-Apr-2012.) (Proof shortened by BJ, 7-Sep-2022.)
Assertion
Ref Expression
symdifass ((𝐴 △ 𝐵) △ 𝐶) = (𝐴 △ (𝐵 △ 𝐶))

Proof of Theorem symdifass
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 elsymdifxor 4205 . . 3 (𝑥 ∈ ((𝐴 △ 𝐵) △ 𝐶) ↔ (𝑥 ∈ (𝐴 △ 𝐵) ⊻ 𝑥 ∈ 𝐶))
2 elsymdifxor 4205 . . . . 5 (𝑥 ∈ (𝐴 △ 𝐵) ↔ (𝑥 ∈ 𝐴 ⊻ 𝑥 ∈ 𝐵))
3 biid 264 . . . . 5 (𝑥 ∈ 𝐶 ↔ 𝑥 ∈ 𝐶)
42, 3xorbi12i 1554 . . . 4 ((𝑥 ∈ (𝐴 △ 𝐵) ⊻ 𝑥 ∈ 𝐶) ↔ ((𝑥 ∈ 𝐴 ⊻ 𝑥 ∈ 𝐵) ⊻ 𝑥 ∈ 𝐶))
5 xorass 1545 . . . 4 (((𝑥 ∈ 𝐴 ⊻ 𝑥 ∈ 𝐵) ⊻ 𝑥 ∈ 𝐶) ↔ (𝑥 ∈ 𝐴 ⊻ (𝑥 ∈ 𝐵 ⊻ 𝑥 ∈ 𝐶)))
6 biid 264 . . . . 5 (𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐴)
7 elsymdifxor 4205 . . . . . 6 (𝑥 ∈ (𝐵 △ 𝐶) ↔ (𝑥 ∈ 𝐵 ⊻ 𝑥 ∈ 𝐶))
87bicomi 227 . . . . 5 ((𝑥 ∈ 𝐵 ⊻ 𝑥 ∈ 𝐶) ↔ 𝑥 ∈ (𝐵 △ 𝐶))
96, 8xorbi12i 1554 . . . 4 ((𝑥 ∈ 𝐴 ⊻ (𝑥 ∈ 𝐵 ⊻ 𝑥 ∈ 𝐶)) ↔ (𝑥 ∈ 𝐴 ⊻ 𝑥 ∈ (𝐵 △ 𝐶)))
104, 5, 93bitri 300 . . 3 ((𝑥 ∈ (𝐴 △ 𝐵) ⊻ 𝑥 ∈ 𝐶) ↔ (𝑥 ∈ 𝐴 ⊻ 𝑥 ∈ (𝐵 △ 𝐶)))
11 elsymdifxor 4205 . . . 4 (𝑥 ∈ (𝐴 △ (𝐵 △ 𝐶)) ↔ (𝑥 ∈ 𝐴 ⊻ 𝑥 ∈ (𝐵 △ 𝐶)))
1211bicomi 227 . . 3 ((𝑥 ∈ 𝐴 ⊻ 𝑥 ∈ (𝐵 △ 𝐶)) ↔ 𝑥 ∈ (𝐴 △ (𝐵 △ 𝐶)))
131, 10, 123bitri 300 . 2 (𝑥 ∈ ((𝐴 △ 𝐵) △ 𝐶) ↔ 𝑥 ∈ (𝐴 △ (𝐵 △ 𝐶)))
1413eqriv 2757 1 ((𝐴 △ 𝐵) △ 𝐶) = (𝐴 △ (𝐵 △ 𝐶))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ⊻ wxo 1541   = wceq 1570   ∈ wcel 2145   △ csymdif 4197
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-xor 1542  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-v 3452  df-dif 3901  df-un 3903  df-symdif 4198
This theorem is used by: (None)
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