ILE Home Intuitionistic Logic Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  ILE Home  >  Th. List  >  elop Unicode version

Theorem elop 4123
Description: An ordered pair has two elements. Exercise 3 of [TakeutiZaring] p. 15. (Contributed by NM, 5-Aug-1993.) (Revised by Mario Carneiro, 26-Apr-2015.)
Hypotheses
Ref Expression
elop.1  |-  A  e. 
_V
elop.2  |-  B  e. 
_V
elop.3  |-  C  e. 
_V
Assertion
Ref Expression
elop  |-  ( A  e.  <. B ,  C >.  <-> 
( A  =  { B }  \/  A  =  { B ,  C } ) )

Proof of Theorem elop
StepHypRef Expression
1 elop.2 . . . 4  |-  B  e. 
_V
2 elop.3 . . . 4  |-  C  e. 
_V
31, 2dfop 3674 . . 3  |-  <. B ,  C >.  =  { { B } ,  { B ,  C } }
43eleq2i 2184 . 2  |-  ( A  e.  <. B ,  C >.  <-> 
A  e.  { { B } ,  { B ,  C } } )
5 elop.1 . . 3  |-  A  e. 
_V
65elpr 3518 . 2  |-  ( A  e.  { { B } ,  { B ,  C } }  <->  ( A  =  { B }  \/  A  =  { B ,  C } ) )
74, 6bitri 183 1  |-  ( A  e.  <. B ,  C >.  <-> 
( A  =  { B }  \/  A  =  { B ,  C } ) )
Colors of variables: wff set class
Syntax hints:    <-> wb 104    \/ wo 682    = wceq 1316    e. wcel 1465   _Vcvv 2660   {csn 3497   {cpr 3498   <.cop 3500
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 683  ax-5 1408  ax-7 1409  ax-gen 1410  ax-ie1 1454  ax-ie2 1455  ax-8 1467  ax-10 1468  ax-11 1469  ax-i12 1470  ax-bndl 1471  ax-4 1472  ax-17 1491  ax-i9 1495  ax-ial 1499  ax-i5r 1500  ax-ext 2099
This theorem depends on definitions:  df-bi 116  df-3an 949  df-tru 1319  df-nf 1422  df-sb 1721  df-clab 2104  df-cleq 2110  df-clel 2113  df-nfc 2247  df-v 2662  df-un 3045  df-sn 3503  df-pr 3504  df-op 3506
This theorem is referenced by:  relop  4659  bdop  13000
  Copyright terms: Public domain W3C validator