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Theorem eqtr 2188
Description: Transitive law for class equality. Proposition 4.7(3) of [TakeutiZaring] p. 13. (Contributed by NM, 25-Jan-2004.)
Assertion
Ref Expression
eqtr  |-  ( ( A  =  B  /\  B  =  C )  ->  A  =  C )

Proof of Theorem eqtr
StepHypRef Expression
1 eqeq1 2177 . 2  |-  ( A  =  B  ->  ( A  =  C  <->  B  =  C ) )
21biimpar 295 1  |-  ( ( A  =  B  /\  B  =  C )  ->  A  =  C )
Colors of variables: wff set class
Syntax hints:    -> wi 4    /\ wa 103    = wceq 1348
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1440  ax-gen 1442  ax-4 1503  ax-17 1519  ax-ext 2152
This theorem depends on definitions:  df-bi 116  df-cleq 2163
This theorem is referenced by:  eqtr2  2189  eqtr3  2190  sylan9eq  2223  eqvinc  2853  eqvincg  2854  uneqdifeqim  3500  preqsn  3762  dtruex  4543  relresfld  5140  relcoi1  5142  eqer  6545  xpider  6584  addlsub  8289  bj-findis  14014
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