Theorem xpeq2d 4699

Description: Equality deduction for cross product. (Contributed by Jeff Madsen, 17-Jun-2010.)

Hypothesis

Ref	Expression
xpeq1d.1	|- ( ph -> A = B )

Assertion

Ref	Expression
xpeq2d	|- ( ph -> ( C X. A ) = ( C X. B ) )

Proof of Theorem xpeq2d

Step	Hyp	Ref	Expression
1		xpeq1d.1	. 2 |- ( ph -> A = B )
2		xpeq2 4690	. 2 |- ( A = B -> ( C X. A ) = ( C X. B ) )
3	1, 2	syl 14	1 |- ( ph -> ( C X. A ) = ( C X. B ) )

Syntax hints:   -> wi 4   = wceq 1373   X. cxp 4673

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1470  ax-7 1471  ax-gen 1472  ax-ie1 1516  ax-ie2 1517  ax-8 1527  ax-11 1529  ax-4 1533  ax-17 1549  ax-i9 1553  ax-ial 1557  ax-i5r 1558  ax-ext 2187

This theorem depends on definitions:  df-bi 117  df-tru 1376  df-nf 1484  df-sb 1786  df-clab 2192  df-cleq 2198  df-clel 2201  df-opab 4106  df-xp 4681

This theorem is referenced by:  csbresg  4962  fconstg  5472  fvdiagfn  6780  mapsncnv  6782  xpsneng  6917  exp3val  10686  mulgval  13458  reldvg  15151  dvfvalap  15153