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Theorem anandi 557
Description: Distribution of conjunction over conjunction. (Contributed by NM, 14-Aug-1995.)
Assertion
Ref Expression
anandi ((𝜑 ∧ (𝜓𝜒)) ↔ ((𝜑𝜓) ∧ (𝜑𝜒)))

Proof of Theorem anandi
StepHypRef Expression
1 anidm 388 . . 3 ((𝜑𝜑) ↔ 𝜑)
21anbi1i 446 . 2 (((𝜑𝜑) ∧ (𝜓𝜒)) ↔ (𝜑 ∧ (𝜓𝜒)))
3 an4 553 . 2 (((𝜑𝜑) ∧ (𝜓𝜒)) ↔ ((𝜑𝜓) ∧ (𝜑𝜒)))
42, 3bitr3i 184 1 ((𝜑 ∧ (𝜓𝜒)) ↔ ((𝜑𝜓) ∧ (𝜑𝜒)))
Colors of variables: wff set class
Syntax hints:  wa 102  wb 103
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106
This theorem depends on definitions:  df-bi 115
This theorem is referenced by:  anandi3  937  moanim  2022  difundi  3251  inrab  3271  uniin  3673  xpcom  4977  fin  5197  fndmin  5406  nnaord  6268  ltexprlemdisj  7165
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