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Theorem ceqsrex2v 2881
Description: Elimination of a restricted existential quantifier, using implicit substitution. (Contributed by NM, 29-Oct-2005.)
Hypotheses
Ref Expression
ceqsrex2v.1 (𝑥 = 𝐴 → (𝜑𝜓))
ceqsrex2v.2 (𝑦 = 𝐵 → (𝜓𝜒))
Assertion
Ref Expression
ceqsrex2v ((𝐴𝐶𝐵𝐷) → (∃𝑥𝐶𝑦𝐷 ((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ 𝜒))
Distinct variable groups:   𝑥,𝑦,𝐴   𝑥,𝐵,𝑦   𝑥,𝐶   𝑥,𝐷,𝑦   𝜓,𝑥   𝜒,𝑦
Allowed substitution hints:   𝜑(𝑥,𝑦)   𝜓(𝑦)   𝜒(𝑥)   𝐶(𝑦)

Proof of Theorem ceqsrex2v
StepHypRef Expression
1 anass 401 . . . . . 6 (((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ (𝑥 = 𝐴 ∧ (𝑦 = 𝐵𝜑)))
21rexbii 2494 . . . . 5 (∃𝑦𝐷 ((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ ∃𝑦𝐷 (𝑥 = 𝐴 ∧ (𝑦 = 𝐵𝜑)))
3 r19.42v 2644 . . . . 5 (∃𝑦𝐷 (𝑥 = 𝐴 ∧ (𝑦 = 𝐵𝜑)) ↔ (𝑥 = 𝐴 ∧ ∃𝑦𝐷 (𝑦 = 𝐵𝜑)))
42, 3bitri 184 . . . 4 (∃𝑦𝐷 ((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ (𝑥 = 𝐴 ∧ ∃𝑦𝐷 (𝑦 = 𝐵𝜑)))
54rexbii 2494 . . 3 (∃𝑥𝐶𝑦𝐷 ((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ ∃𝑥𝐶 (𝑥 = 𝐴 ∧ ∃𝑦𝐷 (𝑦 = 𝐵𝜑)))
6 ceqsrex2v.1 . . . . . 6 (𝑥 = 𝐴 → (𝜑𝜓))
76anbi2d 464 . . . . 5 (𝑥 = 𝐴 → ((𝑦 = 𝐵𝜑) ↔ (𝑦 = 𝐵𝜓)))
87rexbidv 2488 . . . 4 (𝑥 = 𝐴 → (∃𝑦𝐷 (𝑦 = 𝐵𝜑) ↔ ∃𝑦𝐷 (𝑦 = 𝐵𝜓)))
98ceqsrexv 2879 . . 3 (𝐴𝐶 → (∃𝑥𝐶 (𝑥 = 𝐴 ∧ ∃𝑦𝐷 (𝑦 = 𝐵𝜑)) ↔ ∃𝑦𝐷 (𝑦 = 𝐵𝜓)))
105, 9bitrid 192 . 2 (𝐴𝐶 → (∃𝑥𝐶𝑦𝐷 ((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ ∃𝑦𝐷 (𝑦 = 𝐵𝜓)))
11 ceqsrex2v.2 . . 3 (𝑦 = 𝐵 → (𝜓𝜒))
1211ceqsrexv 2879 . 2 (𝐵𝐷 → (∃𝑦𝐷 (𝑦 = 𝐵𝜓) ↔ 𝜒))
1310, 12sylan9bb 462 1 ((𝐴𝐶𝐵𝐷) → (∃𝑥𝐶𝑦𝐷 ((𝑥 = 𝐴𝑦 = 𝐵) ∧ 𝜑) ↔ 𝜒))
Colors of variables: wff set class
Syntax hints:  wi 4  wa 104  wb 105   = wceq 1363  wcel 2158  wrex 2466
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 710  ax-5 1457  ax-7 1458  ax-gen 1459  ax-ie1 1503  ax-ie2 1504  ax-8 1514  ax-10 1515  ax-11 1516  ax-i12 1517  ax-bndl 1519  ax-4 1520  ax-17 1536  ax-i9 1540  ax-ial 1544  ax-i5r 1545  ax-ext 2169
This theorem depends on definitions:  df-bi 117  df-tru 1366  df-nf 1471  df-sb 1773  df-clab 2174  df-cleq 2180  df-clel 2183  df-nfc 2318  df-rex 2471  df-v 2751
This theorem is referenced by: (None)
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