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| Mirrors > Home > ILE Home > Th. List > eqeq1 | GIF version | ||
| Description: Equality implies equivalence of equalities. (Contributed by NM, 5-Aug-1993.) |
| Ref | Expression |
|---|---|
| eqeq1 | ⊢ (𝐴 = 𝐵 → (𝐴 = 𝐶 ↔ 𝐵 = 𝐶)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | dfcleq 2190 | . . . . . 6 ⊢ (𝐴 = 𝐵 ↔ ∀𝑥(𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐵)) | |
| 2 | 1 | biimpi 120 | . . . . 5 ⊢ (𝐴 = 𝐵 → ∀𝑥(𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐵)) |
| 3 | 2 | 19.21bi 1572 | . . . 4 ⊢ (𝐴 = 𝐵 → (𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐵)) |
| 4 | 3 | bibi1d 233 | . . 3 ⊢ (𝐴 = 𝐵 → ((𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐶) ↔ (𝑥 ∈ 𝐵 ↔ 𝑥 ∈ 𝐶))) |
| 5 | 4 | albidv 1838 | . 2 ⊢ (𝐴 = 𝐵 → (∀𝑥(𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐶) ↔ ∀𝑥(𝑥 ∈ 𝐵 ↔ 𝑥 ∈ 𝐶))) |
| 6 | dfcleq 2190 | . 2 ⊢ (𝐴 = 𝐶 ↔ ∀𝑥(𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐶)) | |
| 7 | dfcleq 2190 | . 2 ⊢ (𝐵 = 𝐶 ↔ ∀𝑥(𝑥 ∈ 𝐵 ↔ 𝑥 ∈ 𝐶)) | |
| 8 | 5, 6, 7 | 3bitr4g 223 | 1 ⊢ (𝐴 = 𝐵 → (𝐴 = 𝐶 ↔ 𝐵 = 𝐶)) |
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