Theorem feq3d 5468

Description: Equality deduction for functions. (Contributed by AV, 1-Jan-2020.)

Hypothesis

Ref	Expression
feq2d.1	⊢ (𝜑 → 𝐴 = 𝐵)

Assertion

Ref	Expression
feq3d	⊢ (𝜑 → (𝐹:𝑋⟶𝐴 ↔ 𝐹:𝑋⟶𝐵))

Proof of Theorem feq3d

Step	Hyp	Ref	Expression
1		feq2d.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		feq3 5464	. 2 ⊢ (𝐴 = 𝐵 → (𝐹:𝑋⟶𝐴 ↔ 𝐹:𝑋⟶𝐵))
3	1, 2	syl 14	1 ⊢ (𝜑 → (𝐹:𝑋⟶𝐴 ↔ 𝐹:𝑋⟶𝐵))

Syntax hints:   → wi 4   ↔ wb 105   = wceq 1395  ⟶wf 5320

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1493  ax-7 1494  ax-gen 1495  ax-ie1 1539  ax-ie2 1540  ax-8 1550  ax-11 1552  ax-4 1556  ax-17 1572  ax-i9 1576  ax-ial 1580  ax-i5r 1581  ax-ext 2211

This theorem depends on definitions:  df-bi 117  df-nf 1507  df-sb 1809  df-clab 2216  df-cleq 2222  df-clel 2225  df-in 3204  df-ss 3211  df-f 5328

This theorem is referenced by:  gsumress  13471  resmhm2b  13565  isghm  13823  uptx  14991  txcn  14992  dvply2g  15483  lgseisenlem3  15794  lgseisenlem4  15795  uhgr0vb  15928  uhgrun  15930  upgrun  15970  umgrun  15972  wksfval  16133  wlkres  16188  gfsumval  16630