Theorem feq3d 5336

Description: Equality deduction for functions. (Contributed by AV, 1-Jan-2020.)

Hypothesis

Ref	Expression
feq2d.1	⊢ (𝜑 → 𝐴 = 𝐵)

Assertion

Ref	Expression
feq3d	⊢ (𝜑 → (𝐹:𝑋⟶𝐴 ↔ 𝐹:𝑋⟶𝐵))

Proof of Theorem feq3d

Step	Hyp	Ref	Expression
1		feq2d.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		feq3 5332	. 2 ⊢ (𝐴 = 𝐵 → (𝐹:𝑋⟶𝐴 ↔ 𝐹:𝑋⟶𝐵))
3	1, 2	syl 14	1 ⊢ (𝜑 → (𝐹:𝑋⟶𝐴 ↔ 𝐹:𝑋⟶𝐵))

Syntax hints:   → wi 4   ↔ wb 104   = wceq 1348  ⟶wf 5194

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1440  ax-7 1441  ax-gen 1442  ax-ie1 1486  ax-ie2 1487  ax-8 1497  ax-11 1499  ax-4 1503  ax-17 1519  ax-i9 1523  ax-ial 1527  ax-i5r 1528  ax-ext 2152

This theorem depends on definitions:  df-bi 116  df-nf 1454  df-sb 1756  df-clab 2157  df-cleq 2163  df-clel 2166  df-in 3127  df-ss 3134  df-f 5202

This theorem is referenced by:  uptx  13068  txcn  13069