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| Mirrors > Home > ILE Home > Th. List > intnanrd | GIF version | ||
| Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.) |
| Ref | Expression |
|---|---|
| intnand.1 | ⊢ (𝜑 → ¬ 𝜓) |
| Ref | Expression |
|---|---|
| intnanrd | ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | intnand.1 | . 2 ⊢ (𝜑 → ¬ 𝜓) | |
| 2 | simpl 109 | . 2 ⊢ ((𝜓 ∧ 𝜒) → 𝜓) | |
| 3 | 1, 2 | nsyl 637 | 1 ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 3 → wi 4 ∧ wa 104 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-in1 623 ax-in2 624 |
| This theorem is referenced by: dcand 945 bianfd 961 3bior1fand 1394 frecabcl 6660 frecsuclem 6667 xrrebnd 10200 fzpreddisj 10456 iseqf1olemqk 10922 gcdsupex 12712 gcdsupcl 12713 nndvdslegcd 12720 divgcdnn 12730 sqgcd 12784 coprm 12900 pclemdc 13045 1arith 13124 ctiunctlemudc 13306 gzsum0 13690 gzsumval2 13691 lgsval2lem 16043 lgsval4a 16055 lgsdilem 16060 trlsegvdegfi 16622 |
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