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| Mirrors > Home > ILE Home > Th. List > intnanrd | GIF version | ||
| Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.) |
| Ref | Expression |
|---|---|
| intnand.1 | ⊢ (𝜑 → ¬ 𝜓) |
| Ref | Expression |
|---|---|
| intnanrd | ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | intnand.1 | . 2 ⊢ (𝜑 → ¬ 𝜓) | |
| 2 | simpl 109 | . 2 ⊢ ((𝜓 ∧ 𝜒) → 𝜓) | |
| 3 | 1, 2 | nsyl 633 | 1 ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 3 → wi 4 ∧ wa 104 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-in1 619 ax-in2 620 |
| This theorem is referenced by: dcand 941 bianfd 957 3bior1fand 1390 frecabcl 6608 frecsuclem 6615 xrrebnd 10098 fzpreddisj 10351 iseqf1olemqk 10815 gcdsupex 12591 gcdsupcl 12592 nndvdslegcd 12599 divgcdnn 12609 sqgcd 12663 coprm 12779 pclemdc 12924 1arith 13003 ctiunctlemudc 13121 gsum0g 13542 gsumval2 13543 lgsval2lem 15812 lgsval4a 15824 lgsdilem 15829 trlsegvdegfi 16391 |
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