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| Mirrors > Home > ILE Home > Th. List > intnanrd | GIF version | ||
| Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.) |
| Ref | Expression |
|---|---|
| intnand.1 | ⊢ (𝜑 → ¬ 𝜓) |
| Ref | Expression |
|---|---|
| intnanrd | ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | intnand.1 | . 2 ⊢ (𝜑 → ¬ 𝜓) | |
| 2 | simpl 109 | . 2 ⊢ ((𝜓 ∧ 𝜒) → 𝜓) | |
| 3 | 1, 2 | nsyl 631 | 1 ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 3 → wi 4 ∧ wa 104 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-in1 617 ax-in2 618 |
| This theorem is referenced by: dcand 938 bianfd 954 3bior1fand 1387 frecabcl 6551 frecsuclem 6558 xrrebnd 10027 fzpreddisj 10279 iseqf1olemqk 10741 gcdsupex 12493 gcdsupcl 12494 nndvdslegcd 12501 divgcdnn 12511 sqgcd 12565 coprm 12681 pclemdc 12826 1arith 12905 ctiunctlemudc 13023 gsum0g 13444 gsumval2 13445 lgsval2lem 15704 lgsval4a 15716 lgsdilem 15721 |
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