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| Mirrors > Home > ILE Home > Th. List > intnanrd | GIF version | ||
| Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.) |
| Ref | Expression |
|---|---|
| intnand.1 | ⊢ (𝜑 → ¬ 𝜓) |
| Ref | Expression |
|---|---|
| intnanrd | ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | intnand.1 | . 2 ⊢ (𝜑 → ¬ 𝜓) | |
| 2 | simpl 109 | . 2 ⊢ ((𝜓 ∧ 𝜒) → 𝜓) | |
| 3 | 1, 2 | nsyl 637 | 1 ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Colors of variables: wff set class |
| This proof depends on syntax axioms: ¬ wn 3 → wi 4 ∧ wa 104 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-in1 623 ax-in2 624 |
| This theorem is used by: dcand 945 bianfd 961 3bior1fand 1394 frecabcl 6670 frecsuclem 6677 xrrebnd 10231 fzpreddisj 10488 iseqf1olemqk 10957 gcdsupex 12750 gcdsupcl 12751 nndvdslegcd 12758 divgcdnn 12768 sqgcd 12822 coprm 12939 pclemdc 13087 1arith 13166 ctiunctlemudc 13377 gzsum0 13762 gzsumval2 13763 lgsval2lem 16227 lgsval4a 16239 lgsdilem 16244 trlsegvdegfi 16806 |
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