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| Mirrors > Home > ILE Home > Th. List > intnanrd | GIF version | ||
| Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.) |
| Ref | Expression |
|---|---|
| intnand.1 | ⊢ (𝜑 → ¬ 𝜓) |
| Ref | Expression |
|---|---|
| intnanrd | ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | intnand.1 | . 2 ⊢ (𝜑 → ¬ 𝜓) | |
| 2 | simpl 109 | . 2 ⊢ ((𝜓 ∧ 𝜒) → 𝜓) | |
| 3 | 1, 2 | nsyl 637 | 1 ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Colors of variables: wff set class |
| This proof depends on syntax axioms: ¬ wn 3 → wi 4 ∧ wa 104 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-in1 623 ax-in2 624 |
| This theorem is used by: dcand 945 bianfd 961 3bior1fand 1394 frecabcl 6670 frecsuclem 6677 xrrebnd 10221 fzpreddisj 10478 iseqf1olemqk 10944 gcdsupex 12734 gcdsupcl 12735 nndvdslegcd 12742 divgcdnn 12752 sqgcd 12806 coprm 12922 pclemdc 13067 1arith 13146 ctiunctlemudc 13328 gzsum0 13713 gzsumval2 13714 lgsval2lem 16129 lgsval4a 16141 lgsdilem 16146 trlsegvdegfi 16708 |
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