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| Mirrors > Home > ILE Home > Th. List > intnanrd | GIF version | ||
| Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.) |
| Ref | Expression |
|---|---|
| intnand.1 | ⊢ (𝜑 → ¬ 𝜓) |
| Ref | Expression |
|---|---|
| intnanrd | ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | intnand.1 | . 2 ⊢ (𝜑 → ¬ 𝜓) | |
| 2 | simpl 109 | . 2 ⊢ ((𝜓 ∧ 𝜒) → 𝜓) | |
| 3 | 1, 2 | nsyl 631 | 1 ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 3 → wi 4 ∧ wa 104 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-in1 617 ax-in2 618 |
| This theorem is referenced by: dcand 938 bianfd 954 3bior1fand 1387 frecabcl 6560 frecsuclem 6567 xrrebnd 10044 fzpreddisj 10296 iseqf1olemqk 10759 gcdsupex 12518 gcdsupcl 12519 nndvdslegcd 12526 divgcdnn 12536 sqgcd 12590 coprm 12706 pclemdc 12851 1arith 12930 ctiunctlemudc 13048 gsum0g 13469 gsumval2 13470 lgsval2lem 15729 lgsval4a 15741 lgsdilem 15746 |
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