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| Mirrors > Home > ILE Home > Th. List > intnanrd | GIF version | ||
| Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.) |
| Ref | Expression |
|---|---|
| intnand.1 | ⊢ (𝜑 → ¬ 𝜓) |
| Ref | Expression |
|---|---|
| intnanrd | ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | intnand.1 | . 2 ⊢ (𝜑 → ¬ 𝜓) | |
| 2 | simpl 109 | . 2 ⊢ ((𝜓 ∧ 𝜒) → 𝜓) | |
| 3 | 1, 2 | nsyl 633 | 1 ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 3 → wi 4 ∧ wa 104 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-in1 619 ax-in2 620 |
| This theorem is referenced by: dcand 940 bianfd 956 3bior1fand 1389 frecabcl 6564 frecsuclem 6571 xrrebnd 10053 fzpreddisj 10305 iseqf1olemqk 10768 gcdsupex 12527 gcdsupcl 12528 nndvdslegcd 12535 divgcdnn 12545 sqgcd 12599 coprm 12715 pclemdc 12860 1arith 12939 ctiunctlemudc 13057 gsum0g 13478 gsumval2 13479 lgsval2lem 15738 lgsval4a 15750 lgsdilem 15755 |
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