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| Mirrors > Home > ILE Home > Th. List > intnanrd | GIF version | ||
| Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.) |
| Ref | Expression |
|---|---|
| intnand.1 | ⊢ (𝜑 → ¬ 𝜓) |
| Ref | Expression |
|---|---|
| intnanrd | ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | intnand.1 | . 2 ⊢ (𝜑 → ¬ 𝜓) | |
| 2 | simpl 109 | . 2 ⊢ ((𝜓 ∧ 𝜒) → 𝜓) | |
| 3 | 1, 2 | nsyl 637 | 1 ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Colors of variables: wff set class |
| This proof depends on syntax axioms: ¬ wn 3 → wi 4 ∧ wa 104 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-in1 623 ax-in2 624 |
| This theorem is used by: dcand 945 bianfd 961 3bior1fand 1394 frecabcl 6675 frecsuclem 6682 xrrebnd 10237 fzpreddisj 10494 iseqf1olemqk 10964 gcdsupex 12758 gcdsupcl 12759 nndvdslegcd 12766 divgcdnn 12776 sqgcd 12830 coprm 12947 pclemdc 13095 1arith 13174 ctiunctlemudc 13385 gzsum0 13771 gzsumval2 13772 lgsval2lem 16351 lgsval4a 16363 lgsdilem 16368 trlsegvdegfi 16930 idjudju 17269 |
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