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| Mirrors > Home > ILE Home > Th. List > intnanrd | GIF version | ||
| Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.) |
| Ref | Expression |
|---|---|
| intnand.1 | ⊢ (𝜑 → ¬ 𝜓) |
| Ref | Expression |
|---|---|
| intnanrd | ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | intnand.1 | . 2 ⊢ (𝜑 → ¬ 𝜓) | |
| 2 | simpl 109 | . 2 ⊢ ((𝜓 ∧ 𝜒) → 𝜓) | |
| 3 | 1, 2 | nsyl 633 | 1 ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 3 → wi 4 ∧ wa 104 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-in1 619 ax-in2 620 |
| This theorem is referenced by: dcand 941 bianfd 957 3bior1fand 1390 frecabcl 6643 frecsuclem 6650 xrrebnd 10171 fzpreddisj 10427 iseqf1olemqk 10893 gcdsupex 12678 gcdsupcl 12679 nndvdslegcd 12686 divgcdnn 12696 sqgcd 12750 coprm 12866 pclemdc 13011 1arith 13090 ctiunctlemudc 13272 gsum0g 13659 gsumval2 13660 lgsval2lem 16009 lgsval4a 16021 lgsdilem 16026 trlsegvdegfi 16588 |
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