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| Mirrors > Home > ILE Home > Th. List > intnanrd | GIF version | ||
| Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.) |
| Ref | Expression |
|---|---|
| intnand.1 | ⊢ (𝜑 → ¬ 𝜓) |
| Ref | Expression |
|---|---|
| intnanrd | ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | intnand.1 | . 2 ⊢ (𝜑 → ¬ 𝜓) | |
| 2 | simpl 109 | . 2 ⊢ ((𝜓 ∧ 𝜒) → 𝜓) | |
| 3 | 1, 2 | nsyl 633 | 1 ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 3 → wi 4 ∧ wa 104 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-in1 619 ax-in2 620 |
| This theorem is referenced by: dcand 940 bianfd 956 3bior1fand 1389 frecabcl 6565 frecsuclem 6572 xrrebnd 10054 fzpreddisj 10306 iseqf1olemqk 10769 gcdsupex 12529 gcdsupcl 12530 nndvdslegcd 12537 divgcdnn 12547 sqgcd 12601 coprm 12717 pclemdc 12862 1arith 12941 ctiunctlemudc 13059 gsum0g 13480 gsumval2 13481 lgsval2lem 15741 lgsval4a 15753 lgsdilem 15758 |
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