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| Mirrors > Home > ILE Home > Th. List > intnanrd | GIF version | ||
| Description: Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.) |
| Ref | Expression |
|---|---|
| intnand.1 | ⊢ (𝜑 → ¬ 𝜓) |
| Ref | Expression |
|---|---|
| intnanrd | ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | intnand.1 | . 2 ⊢ (𝜑 → ¬ 𝜓) | |
| 2 | simpl 109 | . 2 ⊢ ((𝜓 ∧ 𝜒) → 𝜓) | |
| 3 | 1, 2 | nsyl 633 | 1 ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒)) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 3 → wi 4 ∧ wa 104 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-in1 619 ax-in2 620 |
| This theorem is referenced by: dcand 940 bianfd 956 3bior1fand 1389 frecabcl 6565 frecsuclem 6572 xrrebnd 10054 fzpreddisj 10306 iseqf1olemqk 10770 gcdsupex 12533 gcdsupcl 12534 nndvdslegcd 12541 divgcdnn 12551 sqgcd 12605 coprm 12721 pclemdc 12866 1arith 12945 ctiunctlemudc 13063 gsum0g 13484 gsumval2 13485 lgsval2lem 15745 lgsval4a 15757 lgsdilem 15762 trlsegvdegfi 16324 |
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