Theorem risset 2560

Description: Two ways to say "𝐴 belongs to 𝐵". (Contributed by NM, 22-Nov-1994.)

Assertion

Ref	Expression
risset	⊢ (𝐴 ∈ 𝐵 ↔ ∃𝑥 ∈ 𝐵 𝑥 = 𝐴)

Distinct variable groups:   𝑥,𝐴   𝑥,𝐵

Proof of Theorem risset

Step	Hyp	Ref	Expression
1		exancom 1656	. 2 ⊢ (∃𝑥(𝑥 ∈ 𝐵 ∧ 𝑥 = 𝐴) ↔ ∃𝑥(𝑥 = 𝐴 ∧ 𝑥 ∈ 𝐵))
2		df-rex 2516	. 2 ⊢ (∃𝑥 ∈ 𝐵 𝑥 = 𝐴 ↔ ∃𝑥(𝑥 ∈ 𝐵 ∧ 𝑥 = 𝐴))
3		df-clel 2227	. 2 ⊢ (𝐴 ∈ 𝐵 ↔ ∃𝑥(𝑥 = 𝐴 ∧ 𝑥 ∈ 𝐵))
4	1, 2, 3	3bitr4ri 213	1 ⊢ (𝐴 ∈ 𝐵 ↔ ∃𝑥 ∈ 𝐵 𝑥 = 𝐴)

Syntax hints:   ∧ wa 104   ↔ wb 105   = wceq 1397  ∃wex 1540   ∈ wcel 2202  ∃wrex 2511

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1495  ax-gen 1497  ax-ie1 1541  ax-ie2 1542  ax-4 1558  ax-ial 1582

This theorem depends on definitions:  df-bi 117  df-clel 2227  df-rex 2516

This theorem is referenced by:  clel5  2943  reueq  3005  reuind  3011  0el  3517  iunid  4026  sucel  4507  reusv3  4557  fvmptt  5738  releldm2  6347  qsid  6768  rerecclap  8909  nndiv  9183  zq  9859  4fvwrd4  10374  conjnmzb  13866  bj-bdcel  16432