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| Mirrors > Home > ILE Home > Th. List > sucel | GIF version | ||
| Description: Membership of a successor in another class. (Contributed by NM, 29-Jun-2004.) |
| Ref | Expression |
|---|---|
| sucel | ⊢ (suc 𝐴 ∈ 𝐵 ↔ ∃𝑥 ∈ 𝐵 ∀𝑦(𝑦 ∈ 𝑥 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | risset 2538 | . 2 ⊢ (suc 𝐴 ∈ 𝐵 ↔ ∃𝑥 ∈ 𝐵 𝑥 = suc 𝐴) | |
| 2 | dfcleq 2203 | . . . 4 ⊢ (𝑥 = suc 𝐴 ↔ ∀𝑦(𝑦 ∈ 𝑥 ↔ 𝑦 ∈ suc 𝐴)) | |
| 3 | vex 2782 | . . . . . . 7 ⊢ 𝑦 ∈ V | |
| 4 | 3 | elsuc 4474 | . . . . . 6 ⊢ (𝑦 ∈ suc 𝐴 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴)) |
| 5 | 4 | bibi2i 227 | . . . . 5 ⊢ ((𝑦 ∈ 𝑥 ↔ 𝑦 ∈ suc 𝐴) ↔ (𝑦 ∈ 𝑥 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴))) |
| 6 | 5 | albii 1496 | . . . 4 ⊢ (∀𝑦(𝑦 ∈ 𝑥 ↔ 𝑦 ∈ suc 𝐴) ↔ ∀𝑦(𝑦 ∈ 𝑥 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴))) |
| 7 | 2, 6 | bitri 184 | . . 3 ⊢ (𝑥 = suc 𝐴 ↔ ∀𝑦(𝑦 ∈ 𝑥 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴))) |
| 8 | 7 | rexbii 2517 | . 2 ⊢ (∃𝑥 ∈ 𝐵 𝑥 = suc 𝐴 ↔ ∃𝑥 ∈ 𝐵 ∀𝑦(𝑦 ∈ 𝑥 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴))) |
| 9 | 1, 8 | bitri 184 | 1 ⊢ (suc 𝐴 ∈ 𝐵 ↔ ∃𝑥 ∈ 𝐵 ∀𝑦(𝑦 ∈ 𝑥 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴))) |
| Colors of variables: wff set class |
| Syntax hints: ↔ wb 105 ∨ wo 712 ∀wal 1373 = wceq 1375 ∈ wcel 2180 ∃wrex 2489 suc csuc 4433 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-io 713 ax-5 1473 ax-7 1474 ax-gen 1475 ax-ie1 1519 ax-ie2 1520 ax-8 1530 ax-10 1531 ax-11 1532 ax-i12 1533 ax-bndl 1535 ax-4 1536 ax-17 1552 ax-i9 1556 ax-ial 1560 ax-i5r 1561 ax-ext 2191 |
| This theorem depends on definitions: df-bi 117 df-tru 1378 df-nf 1487 df-sb 1789 df-clab 2196 df-cleq 2202 df-clel 2205 df-nfc 2341 df-rex 2494 df-v 2781 df-un 3181 df-sn 3652 df-suc 4439 |
| This theorem is referenced by: (None) |
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