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| Mirrors > Home > ILE Home > Th. List > sucel | GIF version | ||
| Description: Membership of a successor in another class. (Contributed by NM, 29-Jun-2004.) |
| Ref | Expression |
|---|---|
| sucel | ⊢ (suc 𝐴 ∈ 𝐵 ↔ ∃𝑥 ∈ 𝐵 ∀𝑦(𝑦 ∈ 𝑥 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | risset 2560 | . 2 ⊢ (suc 𝐴 ∈ 𝐵 ↔ ∃𝑥 ∈ 𝐵 𝑥 = suc 𝐴) | |
| 2 | dfcleq 2225 | . . . 4 ⊢ (𝑥 = suc 𝐴 ↔ ∀𝑦(𝑦 ∈ 𝑥 ↔ 𝑦 ∈ suc 𝐴)) | |
| 3 | vex 2805 | . . . . . . 7 ⊢ 𝑦 ∈ V | |
| 4 | 3 | elsuc 4503 | . . . . . 6 ⊢ (𝑦 ∈ suc 𝐴 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴)) |
| 5 | 4 | bibi2i 227 | . . . . 5 ⊢ ((𝑦 ∈ 𝑥 ↔ 𝑦 ∈ suc 𝐴) ↔ (𝑦 ∈ 𝑥 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴))) |
| 6 | 5 | albii 1518 | . . . 4 ⊢ (∀𝑦(𝑦 ∈ 𝑥 ↔ 𝑦 ∈ suc 𝐴) ↔ ∀𝑦(𝑦 ∈ 𝑥 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴))) |
| 7 | 2, 6 | bitri 184 | . . 3 ⊢ (𝑥 = suc 𝐴 ↔ ∀𝑦(𝑦 ∈ 𝑥 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴))) |
| 8 | 7 | rexbii 2539 | . 2 ⊢ (∃𝑥 ∈ 𝐵 𝑥 = suc 𝐴 ↔ ∃𝑥 ∈ 𝐵 ∀𝑦(𝑦 ∈ 𝑥 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴))) |
| 9 | 1, 8 | bitri 184 | 1 ⊢ (suc 𝐴 ∈ 𝐵 ↔ ∃𝑥 ∈ 𝐵 ∀𝑦(𝑦 ∈ 𝑥 ↔ (𝑦 ∈ 𝐴 ∨ 𝑦 = 𝐴))) |
| Colors of variables: wff set class |
| Syntax hints: ↔ wb 105 ∨ wo 715 ∀wal 1395 = wceq 1397 ∈ wcel 2202 ∃wrex 2511 suc csuc 4462 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-io 716 ax-5 1495 ax-7 1496 ax-gen 1497 ax-ie1 1541 ax-ie2 1542 ax-8 1552 ax-10 1553 ax-11 1554 ax-i12 1555 ax-bndl 1557 ax-4 1558 ax-17 1574 ax-i9 1578 ax-ial 1582 ax-i5r 1583 ax-ext 2213 |
| This theorem depends on definitions: df-bi 117 df-tru 1400 df-nf 1509 df-sb 1811 df-clab 2218 df-cleq 2224 df-clel 2227 df-nfc 2363 df-rex 2516 df-v 2804 df-un 3204 df-sn 3675 df-suc 4468 |
| This theorem is referenced by: (None) |
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