Theorem cbvopab1davw 36835

Description: Change the first bound variable in an ordered-pair class abstraction. Deduction form. (Contributed by GG, 14-Aug-2025.)

Hypothesis

Ref	Expression
cbvopab1davw.1	⊢ ((𝜑 ∧ 𝑥 = 𝑧) → (𝜓 ↔ 𝜒))

Assertion

Ref	Expression
cbvopab1davw	⊢ (𝜑 → {⟨𝑥, 𝑦⟩ ∣ 𝜓} = {⟨𝑧, 𝑦⟩ ∣ 𝜒})

Distinct variable groups:   𝜑,𝑥,𝑦,𝑧   𝜓,𝑧   𝜒,𝑥

Allowed substitution hints:   𝜓(𝑥, 𝑦)   𝜒(𝑦, 𝑧)

Proof of Theorem cbvopab1davw

Dummy variable 𝑡 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		opeq1 4840	. . . . . . . 8 ⊢ (𝑥 = 𝑧 → ⟨𝑥, 𝑦⟩ = ⟨𝑧, 𝑦⟩)
2	1	adantl 487	. . . . . . 7 ⊢ ((𝜑 ∧ 𝑥 = 𝑧) → ⟨𝑥, 𝑦⟩ = ⟨𝑧, 𝑦⟩)
3	2	eqeq2d 2776	. . . . . 6 ⊢ ((𝜑 ∧ 𝑥 = 𝑧) → (𝑡 = ⟨𝑥, 𝑦⟩ ↔ 𝑡 = ⟨𝑧, 𝑦⟩))
4		cbvopab1davw.1	. . . . . 6 ⊢ ((𝜑 ∧ 𝑥 = 𝑧) → (𝜓 ↔ 𝜒))
5	3, 4	anbi12d 644	. . . . 5 ⊢ ((𝜑 ∧ 𝑥 = 𝑧) → ((𝑡 = ⟨𝑥, 𝑦⟩ ∧ 𝜓) ↔ (𝑡 = ⟨𝑧, 𝑦⟩ ∧ 𝜒)))
6	5	exbidv 1954	. . . 4 ⊢ ((𝜑 ∧ 𝑥 = 𝑧) → (∃𝑦(𝑡 = ⟨𝑥, 𝑦⟩ ∧ 𝜓) ↔ ∃𝑦(𝑡 = ⟨𝑧, 𝑦⟩ ∧ 𝜒)))
7	6	cbvexdvaw 2072	. . 3 ⊢ (𝜑 → (∃𝑥∃𝑦(𝑡 = ⟨𝑥, 𝑦⟩ ∧ 𝜓) ↔ ∃𝑧∃𝑦(𝑡 = ⟨𝑧, 𝑦⟩ ∧ 𝜒)))
8	7	abbidv 2831	. 2 ⊢ (𝜑 → {𝑡 ∣ ∃𝑥∃𝑦(𝑡 = ⟨𝑥, 𝑦⟩ ∧ 𝜓)} = {𝑡 ∣ ∃𝑧∃𝑦(𝑡 = ⟨𝑧, 𝑦⟩ ∧ 𝜒)})
9		df-opab 5176	. 2 ⊢ {⟨𝑥, 𝑦⟩ ∣ 𝜓} = {𝑡 ∣ ∃𝑥∃𝑦(𝑡 = ⟨𝑥, 𝑦⟩ ∧ 𝜓)}
10		df-opab 5176	. 2 ⊢ {⟨𝑧, 𝑦⟩ ∣ 𝜒} = {𝑡 ∣ ∃𝑧∃𝑦(𝑡 = ⟨𝑧, 𝑦⟩ ∧ 𝜒)}
11	8, 9, 10	3eqtr4g 2825	1 ⊢ (𝜑 → {⟨𝑥, 𝑦⟩ ∣ 𝜓} = {⟨𝑧, 𝑦⟩ ∣ 𝜒})

This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1570  ∃wex 1812  {cab 2743  ⟨cop 4597  {copab 5175

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-ext 2737

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2744  df-cleq 2757  df-clel 2840  df-rab 3419  df-v 3459  df-dif 3909  df-un 3911  df-ss 3923  df-nul 4287  df-if 4490  df-sn 4592  df-pr 4594  df-op 4598  df-opab 5176

This theorem is used by:  cbvmptdavw  36838  cbvmptdavw2  36859