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Theorem disjxun0 33216
Description: Simplify a disjoint union. (Contributed by Thierry Arnoux, 27-Nov-2023.)
Hypothesis
Ref Expression
disjxun0.1 ((𝜑 ∧ 𝑥 ∈ 𝐵) → 𝐶 = ∅)
Assertion
Ref Expression
disjxun0 (𝜑 → (Disj 𝑥 ∈ (𝐴 ∪ 𝐵)𝐶 ↔ Disj 𝑥 ∈ 𝐴 𝐶))
Distinct variable group:   𝜑,𝑥
Allowed substitution hints:   𝐴(𝑥)   𝐵(𝑥)   𝐶(𝑥)

Proof of Theorem disjxun0
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 disjxun0.1 . . . . 5 ((𝜑 ∧ 𝑥 ∈ 𝐵) → 𝐶 = ∅)
2 nel02 4284 . . . . 5 (𝐶 = ∅ → ¬ 𝑦 ∈ 𝐶)
31, 2syl 18 . . . 4 ((𝜑 ∧ 𝑥 ∈ 𝐵) → ¬ 𝑦 ∈ 𝐶)
43rmounid 33139 . . 3 (𝜑 → (∃*𝑥 ∈ (𝐴 ∪ 𝐵)𝑦 ∈ 𝐶 ↔ ∃*𝑥 ∈ 𝐴 𝑦 ∈ 𝐶))
54albidv 1952 . 2 (𝜑 → (∀𝑦∃*𝑥 ∈ (𝐴 ∪ 𝐵)𝑦 ∈ 𝐶 ↔ ∀𝑦∃*𝑥 ∈ 𝐴 𝑦 ∈ 𝐶))
6 df-disj 5070 . 2 (Disj 𝑥 ∈ (𝐴 ∪ 𝐵)𝐶 ↔ ∀𝑦∃*𝑥 ∈ (𝐴 ∪ 𝐵)𝑦 ∈ 𝐶)
7 df-disj 5070 . 2 (Disj 𝑥 ∈ 𝐴 𝐶 ↔ ∀𝑦∃*𝑥 ∈ 𝐴 𝑦 ∈ 𝐶)
85, 6, 73bitr4g 317 1 (𝜑 → (Disj 𝑥 ∈ (𝐴 ∪ 𝐵)𝐶 ↔ Disj 𝑥 ∈ 𝐴 𝐶))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ↔ wb 209   ∧ wa 401  ∀wal 1567   = wceq 1569   ∈ wcel 2144  ∃*wrmo 3364   ∪ cun 4149  ∅c0 4278  Disj wdisj 5069
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1572  df-fal 1582  df-ex 1812  df-sb 2099  df-mo 2564  df-clab 2739  df-cleq 2752  df-clel 2835  df-rmo 3365  df-v 3452  df-dif 4047  df-un 4151  df-nul 4279  df-disj 5070
This theorem is used by:  tocyccntz  33752
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