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Mirrors > Home > MPE Home > Th. List > el | Structured version Visualization version GIF version |
Description: Any set is an element of some other set. See elALT 5460 for a shorter proof using more axioms, and see elALT2 5387 for a proof that uses ax-9 2118 and ax-pow 5383 instead of ax-pr 5447. (Contributed by NM, 4-Jan-2002.) (Proof shortened by Andrew Salmon, 25-Jul-2011.) Use ax-pr 5447 instead of ax-9 2118 and ax-pow 5383. (Revised by BTernaryTau, 2-Dec-2024.) |
Ref | Expression |
---|---|
el | ⊢ ∃𝑦 𝑥 ∈ 𝑦 |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | ax-pr 5447 | . 2 ⊢ ∃𝑦∀𝑧((𝑧 = 𝑥 ∨ 𝑧 = 𝑥) → 𝑧 ∈ 𝑦) | |
2 | pm4.25 904 | . . . . . 6 ⊢ (𝑧 = 𝑥 ↔ (𝑧 = 𝑥 ∨ 𝑧 = 𝑥)) | |
3 | 2 | imbi1i 349 | . . . . 5 ⊢ ((𝑧 = 𝑥 → 𝑧 ∈ 𝑦) ↔ ((𝑧 = 𝑥 ∨ 𝑧 = 𝑥) → 𝑧 ∈ 𝑦)) |
4 | 3 | albii 1817 | . . . 4 ⊢ (∀𝑧(𝑧 = 𝑥 → 𝑧 ∈ 𝑦) ↔ ∀𝑧((𝑧 = 𝑥 ∨ 𝑧 = 𝑥) → 𝑧 ∈ 𝑦)) |
5 | elequ1 2115 | . . . . 5 ⊢ (𝑧 = 𝑥 → (𝑧 ∈ 𝑦 ↔ 𝑥 ∈ 𝑦)) | |
6 | 5 | equsalvw 2003 | . . . 4 ⊢ (∀𝑧(𝑧 = 𝑥 → 𝑧 ∈ 𝑦) ↔ 𝑥 ∈ 𝑦) |
7 | 4, 6 | bitr3i 277 | . . 3 ⊢ (∀𝑧((𝑧 = 𝑥 ∨ 𝑧 = 𝑥) → 𝑧 ∈ 𝑦) ↔ 𝑥 ∈ 𝑦) |
8 | 7 | exbii 1846 | . 2 ⊢ (∃𝑦∀𝑧((𝑧 = 𝑥 ∨ 𝑧 = 𝑥) → 𝑧 ∈ 𝑦) ↔ ∃𝑦 𝑥 ∈ 𝑦) |
9 | 1, 8 | mpbi 230 | 1 ⊢ ∃𝑦 𝑥 ∈ 𝑦 |
Colors of variables: wff setvar class |
Syntax hints: → wi 4 ∨ wo 846 ∀wal 1535 ∃wex 1777 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1793 ax-4 1807 ax-5 1909 ax-6 1967 ax-7 2007 ax-8 2110 ax-pr 5447 |
This theorem depends on definitions: df-bi 207 df-an 396 df-or 847 df-ex 1778 |
This theorem is referenced by: sels 5458 dtruOLD 5461 dmep 5948 axpownd 10670 zfcndinf 10687 distel 35767 |
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