Theorem elrabrd 32478

Description: Deduction version of elrab 3642, just like elrabd 3644, but backwards direction. (Contributed by Thierry Arnoux, 15-Jan-2026.)

Hypotheses

Ref	Expression
elrabrd.1	⊢ (𝑥 = 𝐴 → (𝜓 ↔ 𝜒))
elrabrd.2	⊢ (𝜑 → 𝐴 ∈ {𝑥 ∈ 𝐵 ∣ 𝜓})

Assertion

Ref	Expression
elrabrd	⊢ (𝜑 → 𝜒)

Distinct variable groups:   𝑥,𝐴   𝑥,𝐵   𝜒,𝑥

Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑥)

Proof of Theorem elrabrd

Step	Hyp	Ref	Expression
1		elrabrd.2	. . 3 ⊢ (𝜑 → 𝐴 ∈ {𝑥 ∈ 𝐵 ∣ 𝜓})
2		elrabrd.1	. . . 4 ⊢ (𝑥 = 𝐴 → (𝜓 ↔ 𝜒))
3	2	elrab 3642	. . 3 ⊢ (𝐴 ∈ {𝑥 ∈ 𝐵 ∣ 𝜓} ↔ (𝐴 ∈ 𝐵 ∧ 𝜒))
4	1, 3	sylib 218	. 2 ⊢ (𝜑 → (𝐴 ∈ 𝐵 ∧ 𝜒))
5	4	simprd 495	1 ⊢ (𝜑 → 𝜒)

Syntax hints:   → wi 4   ↔ wb 206   ∧ wa 395   = wceq 1541   ∈ wcel 2111  {crab 3395

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2113  ax-9 2121  ax-ext 2703

This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1544  df-ex 1781  df-sb 2068  df-clab 2710  df-cleq 2723  df-clel 2806  df-rab 3396  df-v 3438

This theorem is referenced by:  mplvrpmrhm  33577  esplymhp  33589  esplyfv1  33590