Theorem elrabrd 3648

Description: Deduction version of elrab 3645, just like elrabd 3647, but backwards direction. (Contributed by Thierry Arnoux, 15-Jan-2026.)

Hypotheses

Ref	Expression
elrabrd.1	⊢ (𝑥 = 𝐴 → (𝜓 ↔ 𝜒))
elrabrd.2	⊢ (𝜑 → 𝐴 ∈ {𝑥 ∈ 𝐵 ∣ 𝜓})

Assertion

Ref	Expression
elrabrd	⊢ (𝜑 → 𝜒)

Distinct variable groups:   𝑥,𝐴   𝑥,𝐵   𝜒,𝑥

Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑥)

Proof of Theorem elrabrd

Step	Hyp	Ref	Expression
1		elrabrd.2	. . 3 ⊢ (𝜑 → 𝐴 ∈ {𝑥 ∈ 𝐵 ∣ 𝜓})
2		elrabrd.1	. . . 4 ⊢ (𝑥 = 𝐴 → (𝜓 ↔ 𝜒))
3	2	elrab 3645	. . 3 ⊢ (𝐴 ∈ {𝑥 ∈ 𝐵 ∣ 𝜓} ↔ (𝐴 ∈ 𝐵 ∧ 𝜒))
4	1, 3	sylib 221	. 2 ⊢ (𝜑 → (𝐴 ∈ 𝐵 ∧ 𝜒))
5	4	simprd 501	1 ⊢ (𝜑 → 𝜒)

This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1570   ∈ wcel 2145  {crab 3412

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732

This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-rab 3413  df-v 3452

This theorem is used by:  plngcplem  29182  elcgrabasi  29294  cycpmconjslem2  33635  selvply1rhmlemb  34070  selvply1rhm0  34077  extvfvvcl  34086  extvfvcl  34087  mplmulmvr  34090  evlextv  34093  mplvrpmlem  34094  mplvrpmrhm  34098  psrmonprod  34103  esplymhp  34119  esplyfv1  34120  esplyfval3  34123  esplyind  34126  nmuladdel  36877