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Theorem errel 8706
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 8696 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (𝑅 ∪ (𝑅𝑅)) ⊆ 𝑅))
21simp1bi 1163 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4   = wceq 1570  cun 3897  wss 3899  ccnv 5654  dom cdm 5655  ccom 5659  Rel wrel 5660   Er wer 8693
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-an 402  df-3an 1105  df-er 8696
This theorem is used by:  ercl  8708  ersym  8709  ertr  8712  ercnv  8718  erssxp  8720  erth  8751  iiner  8789  qusxpid  19308  eqg0el  19311  frgpuplem  19899  ismntop  34536  topfneec  36974  prter3  39755
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