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Theorem errel 8646
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 8636 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (𝑅 ∪ (𝑅𝑅)) ⊆ 𝑅))
21simp1bi 1146 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1542  cun 3888  wss 3890  ccnv 5623  dom cdm 5624  ccom 5628  Rel wrel 5629   Er wer 8633
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 207  df-an 396  df-3an 1089  df-er 8636
This theorem is referenced by:  ercl  8648  ersym  8649  ertr  8652  ercnv  8658  erssxp  8660  erth  8691  iiner  8729  eqg0el  19149  frgpuplem  19738  qusxpid  33438  ismntop  34186  topfneec  36553  prter3  39342
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