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Theorem errel 8655
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 8645 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (𝑅 ∪ (𝑅𝑅)) ⊆ 𝑅))
21simp1bi 1146 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1542  cun 3901  wss 3903  ccnv 5631  dom cdm 5632  ccom 5636  Rel wrel 5637   Er wer 8642
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 207  df-an 396  df-3an 1089  df-er 8645
This theorem is referenced by:  ercl  8657  ersym  8658  ertr  8661  ercnv  8667  erssxp  8669  erth  8700  iiner  8738  eqg0el  19124  frgpuplem  19713  qusxpid  33455  ismntop  34203  topfneec  36568  prter3  39255
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