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Theorem errel 8765
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 8755 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (◡𝑅 ∪ (𝑅 ∘ 𝑅)) ⊆ 𝑅))
21simp1bi 1163 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   = wceq 1570   ⊆ wss 3900   ∪ cun 4152  ◡ccnv 5657  dom cdm 5658   ∘ ccom 5662  Rel wrel 5663   Er wer 8752
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-an 402  df-3an 1105  df-er 8755
This theorem is used by:  ercl  8767  ersym  8768  ertr  8771  ercnv  8777  erssxp  8779  erth  8810  iiner  8848  qusxpid  19445  eqg0el  19448  frgpuplem  20037  ismntop  34769  topfneec  37358  prter3  40205
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