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Theorem errel 8700
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 8690 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (𝑅 ∪ (𝑅𝑅)) ⊆ 𝑅))
21simp1bi 1161 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1567  cun 3911  wss 3913  ccnv 5658  dom cdm 5659  ccom 5663  Rel wrel 5664   Er wer 8687
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 210  df-an 401  df-3an 1103  df-er 8690
This theorem is referenced by:  ercl  8702  ersym  8703  ertr  8706  ercnv  8712  erssxp  8714  erth  8745  iiner  8783  qusxpid  19247  eqg0el  19250  frgpuplem  19838  ismntop  34357  topfneec  36751  prter3  39541
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