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Theorem errel 8682
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 8672 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (𝑅 ∪ (𝑅𝑅)) ⊆ 𝑅))
21simp1bi 1157 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1559  cun 3900  wss 3902  ccnv 5642  dom cdm 5643  ccom 5647  Rel wrel 5648   Er wer 8669
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 209  df-an 400  df-3an 1099  df-er 8672
This theorem is referenced by:  ercl  8684  ersym  8685  ertr  8688  ercnv  8694  erssxp  8696  erth  8727  iiner  8765  eqg0el  19215  frgpuplem  19803  qusxpid  33510  ismntop  34284  topfneec  36676  prter3  39467
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