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Theorem iscnrm3rlem1 45673
Description: Lemma for iscnrm3rlem2 45674. The hypothesis could be generalized to (𝜑 → (𝑆𝑇) ⊆ 𝑋). (Contributed by Zhi Wang, 5-Sep-2024.)
Hypothesis
Ref Expression
iscnrm3rlem1.1 (𝜑𝑆𝑋)
Assertion
Ref Expression
iscnrm3rlem1 (𝜑 → (𝑆𝑇) = (𝑆 ∩ (𝑋 ∖ (𝑆𝑇))))

Proof of Theorem iscnrm3rlem1
StepHypRef Expression
1 difindi 4188 . . . 4 (𝑋 ∖ (𝑆𝑇)) = ((𝑋𝑆) ∪ (𝑋𝑇))
21ineq2i 4116 . . 3 (𝑆 ∩ (𝑋 ∖ (𝑆𝑇))) = (𝑆 ∩ ((𝑋𝑆) ∪ (𝑋𝑇)))
3 indi 4180 . . 3 (𝑆 ∩ ((𝑋𝑆) ∪ (𝑋𝑇))) = ((𝑆 ∩ (𝑋𝑆)) ∪ (𝑆 ∩ (𝑋𝑇)))
4 disjdif 4371 . . . . 5 (𝑆 ∩ (𝑋𝑆)) = ∅
54uneq1i 4066 . . . 4 ((𝑆 ∩ (𝑋𝑆)) ∪ (𝑆 ∩ (𝑋𝑇))) = (∅ ∪ (𝑆 ∩ (𝑋𝑇)))
6 0un 4291 . . . 4 (∅ ∪ (𝑆 ∩ (𝑋𝑇))) = (𝑆 ∩ (𝑋𝑇))
7 indif2 4177 . . . 4 (𝑆 ∩ (𝑋𝑇)) = ((𝑆𝑋) ∖ 𝑇)
85, 6, 73eqtri 2785 . . 3 ((𝑆 ∩ (𝑋𝑆)) ∪ (𝑆 ∩ (𝑋𝑇))) = ((𝑆𝑋) ∖ 𝑇)
92, 3, 83eqtri 2785 . 2 (𝑆 ∩ (𝑋 ∖ (𝑆𝑇))) = ((𝑆𝑋) ∖ 𝑇)
10 iscnrm3rlem1.1 . . . 4 (𝜑𝑆𝑋)
11 df-ss 3877 . . . 4 (𝑆𝑋 ↔ (𝑆𝑋) = 𝑆)
1210, 11sylib 221 . . 3 (𝜑 → (𝑆𝑋) = 𝑆)
1312difeq1d 4029 . 2 (𝜑 → ((𝑆𝑋) ∖ 𝑇) = (𝑆𝑇))
149, 13syl5req 2806 1 (𝜑 → (𝑆𝑇) = (𝑆 ∩ (𝑋 ∖ (𝑆𝑇))))
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1538  cdif 3857  cun 3858  cin 3859  wss 3860  c0 4227
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1911  ax-6 1970  ax-7 2015  ax-8 2113  ax-9 2121  ax-ext 2729
This theorem depends on definitions:  df-bi 210  df-an 400  df-or 845  df-tru 1541  df-fal 1551  df-ex 1782  df-sb 2070  df-clab 2736  df-cleq 2750  df-clel 2830  df-rab 3079  df-v 3411  df-dif 3863  df-un 3865  df-in 3867  df-ss 3877  df-nul 4228
This theorem is referenced by:  iscnrm3rlem2  45674
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