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Theorem iscnrm3rlem1 49328
Description: Lemma for iscnrm3rlem2 49329. The hypothesis could be generalized to (𝜑 → (𝑆𝑇) ⊆ 𝑋). (Contributed by Zhi Wang, 5-Sep-2024.)
Hypothesis
Ref Expression
iscnrm3rlem1.1 (𝜑𝑆𝑋)
Assertion
Ref Expression
iscnrm3rlem1 (𝜑 → (𝑆𝑇) = (𝑆 ∩ (𝑋 ∖ (𝑆𝑇))))

Proof of Theorem iscnrm3rlem1
StepHypRef Expression
1 difindi 4246 . . . 4 (𝑋 ∖ (𝑆𝑇)) = ((𝑋𝑆) ∪ (𝑋𝑇))
21ineq2i 4171 . . 3 (𝑆 ∩ (𝑋 ∖ (𝑆𝑇))) = (𝑆 ∩ ((𝑋𝑆) ∪ (𝑋𝑇)))
3 indi 4238 . . 3 (𝑆 ∩ ((𝑋𝑆) ∪ (𝑋𝑇))) = ((𝑆 ∩ (𝑋𝑆)) ∪ (𝑆 ∩ (𝑋𝑇)))
4 disjdif 4426 . . . . 5 (𝑆 ∩ (𝑋𝑆)) = ∅
54uneq1i 4118 . . . 4 ((𝑆 ∩ (𝑋𝑆)) ∪ (𝑆 ∩ (𝑋𝑇))) = (∅ ∪ (𝑆 ∩ (𝑋𝑇)))
6 0un 4350 . . . 4 (∅ ∪ (𝑆 ∩ (𝑋𝑇))) = (𝑆 ∩ (𝑋𝑇))
7 indif2 4235 . . . 4 (𝑆 ∩ (𝑋𝑇)) = ((𝑆𝑋) ∖ 𝑇)
85, 6, 73eqtri 2764 . . 3 ((𝑆 ∩ (𝑋𝑆)) ∪ (𝑆 ∩ (𝑋𝑇))) = ((𝑆𝑋) ∖ 𝑇)
92, 3, 83eqtri 2764 . 2 (𝑆 ∩ (𝑋 ∖ (𝑆𝑇))) = ((𝑆𝑋) ∖ 𝑇)
10 iscnrm3rlem1.1 . . . 4 (𝜑𝑆𝑋)
11 dfss2 3921 . . . 4 (𝑆𝑋 ↔ (𝑆𝑋) = 𝑆)
1210, 11sylib 218 . . 3 (𝜑 → (𝑆𝑋) = 𝑆)
1312difeq1d 4079 . 2 (𝜑 → ((𝑆𝑋) ∖ 𝑇) = (𝑆𝑇))
149, 13eqtr2id 2785 1 (𝜑 → (𝑆𝑇) = (𝑆 ∩ (𝑋 ∖ (𝑆𝑇))))
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1542  cdif 3900  cun 3901  cin 3902  wss 3903  c0 4287
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-ext 2709
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-3an 1089  df-tru 1545  df-fal 1555  df-ex 1782  df-sb 2069  df-clab 2716  df-cleq 2729  df-clel 2812  df-rab 3402  df-v 3444  df-dif 3906  df-un 3908  df-in 3910  df-ss 3920  df-nul 4288
This theorem is referenced by:  iscnrm3rlem2  49329
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