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Theorem sb8f 2388
Description: Substitution of variable in universal quantifier. Version of sb8 2551 with a disjoint variable condition, not requiring ax-10 2179 or ax-13 2406. (Contributed by NM, 16-May-1993.) (Revised by Wolf Lammen, 19-Jan-2023.) Avoid ax-10 2179. (Revised by SN, 5-Dec-2024.)
Hypothesis
Ref Expression
sb8f.nf 𝑦𝜑
Assertion
Ref Expression
sb8f (∀𝑥𝜑 ↔ ∀𝑦[𝑦 / 𝑥]𝜑)
Distinct variable group:   𝑥,𝑦
Allowed substitution hints:   𝜑(𝑥, 𝑦)

Proof of Theorem sb8f
StepHypRef Expression
1 sb6 2122 . . 3 ([𝑦 / 𝑥]𝜑 ↔ ∀𝑥(𝑥 = 𝑦𝜑))
21albii 1852 . 2 (∀𝑦[𝑦 / 𝑥]𝜑 ↔ ∀𝑦𝑥(𝑥 = 𝑦𝜑))
3 alcom 2197 . 2 (∀𝑦𝑥(𝑥 = 𝑦𝜑) ↔ ∀𝑥𝑦(𝑥 = 𝑦𝜑))
4 sb6 2122 . . . 4 ([𝑥 / 𝑦]𝜑 ↔ ∀𝑦(𝑦 = 𝑥𝜑))
5 sb8f.nf . . . . 5 𝑦𝜑
65sbf 2308 . . . 4 ([𝑥 / 𝑦]𝜑𝜑)
7 equcom 2051 . . . . . 6 (𝑦 = 𝑥𝑥 = 𝑦)
87imbi1i 352 . . . . 5 ((𝑦 = 𝑥𝜑) ↔ (𝑥 = 𝑦𝜑))
98albii 1852 . . . 4 (∀𝑦(𝑦 = 𝑥𝜑) ↔ ∀𝑦(𝑥 = 𝑦𝜑))
104, 6, 93bitr3ri 305 . . 3 (∀𝑦(𝑥 = 𝑦𝜑) ↔ 𝜑)
1110albii 1852 . 2 (∀𝑥𝑦(𝑥 = 𝑦𝜑) ↔ ∀𝑥𝜑)
122, 3, 113bitrri 301 1 (∀𝑥𝜑 ↔ ∀𝑦[𝑦 / 𝑥]𝜑)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4  wb 209  wal 1568  wnf 1816  [wsb 2099
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-11 2195  ax-12 2216
This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-nf 1817  df-sb 2100
This theorem is used by:  mo5f  32864  ax11-pm2  37504  bj-nfcf  37591
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