Theorem ssrabdf 45874

Description: Subclass of a restricted class abstraction (deduction form). (Contributed by Glauco Siliprandi, 5-Jan-2025.)

Hypotheses

Ref	Expression
ssrabdf.1	⊢ Ⅎ𝑥𝐴
ssrabdf.2	⊢ Ⅎ𝑥𝐵
ssrabdf.3	⊢ Ⅎ𝑥𝜑
ssrabdf.4	⊢ (𝜑 → 𝐵 ⊆ 𝐴)
ssrabdf.5	⊢ ((𝜑 ∧ 𝑥 ∈ 𝐵) → 𝜓)

Assertion

Ref	Expression
ssrabdf	⊢ (𝜑 → 𝐵 ⊆ {𝑥 ∈ 𝐴 ∣ 𝜓})

Proof of Theorem ssrabdf

Step	Hyp	Ref	Expression
1		ssrabdf.4	. 2 ⊢ (𝜑 → 𝐵 ⊆ 𝐴)
2		ssrabdf.3	. . 3 ⊢ Ⅎ𝑥𝜑
3		ssrabdf.5	. . 3 ⊢ ((𝜑 ∧ 𝑥 ∈ 𝐵) → 𝜓)
4	2, 3	ralrimia 3267	. 2 ⊢ (𝜑 → ∀𝑥 ∈ 𝐵 𝜓)
5		ssrabdf.2	. . 3 ⊢ Ⅎ𝑥𝐵
6		ssrabdf.1	. . 3 ⊢ Ⅎ𝑥𝐴
7	5, 6	ssrabf 45873	. 2 ⊢ (𝐵 ⊆ {𝑥 ∈ 𝐴 ∣ 𝜓} ↔ (𝐵 ⊆ 𝐴 ∧ ∀𝑥 ∈ 𝐵 𝜓))
8	1, 4, 7	sylanbrc 595	1 ⊢ (𝜑 → 𝐵 ⊆ {𝑥 ∈ 𝐴 ∣ 𝜓})

This proof depends on syntax axioms:   → wi 4   ∧ wa 401  Ⅎwnf 1816   ∈ wcel 2146  Ⅎwnfc 2913  ∀wral 3082  {crab 3419   ⊆ wss 3908

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-10 2179  ax-11 2195  ax-12 2216  ax-ext 2738

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1573  df-ex 1813  df-nf 1817  df-sb 2100  df-clab 2745  df-cleq 2758  df-clel 2841  df-nfc 2915  df-ral 3083  df-rab 3420  df-ss 3925

This theorem is used by:  smfpimne2  47595