Theorem ssrabdf 46223

Description: Subclass of a restricted class abstraction (deduction form). (Contributed by Glauco Siliprandi, 5-Jan-2025.)

Hypotheses

Ref	Expression
ssrabdf.1	⊢ Ⅎ𝑥𝐴
ssrabdf.2	⊢ Ⅎ𝑥𝐵
ssrabdf.3	⊢ Ⅎ𝑥𝜑
ssrabdf.4	⊢ (𝜑 → 𝐵 ⊆ 𝐴)
ssrabdf.5	⊢ ((𝜑 ∧ 𝑥 ∈ 𝐵) → 𝜓)

Assertion

Ref	Expression
ssrabdf	⊢ (𝜑 → 𝐵 ⊆ {𝑥 ∈ 𝐴 ∣ 𝜓})

Proof of Theorem ssrabdf

Step	Hyp	Ref	Expression
1		ssrabdf.4	. 2 ⊢ (𝜑 → 𝐵 ⊆ 𝐴)
2		ssrabdf.3	. . 3 ⊢ Ⅎ𝑥𝜑
3		ssrabdf.5	. . 3 ⊢ ((𝜑 ∧ 𝑥 ∈ 𝐵) → 𝜓)
4	2, 3	ralrimia 3261	. 2 ⊢ (𝜑 → ∀𝑥 ∈ 𝐵 𝜓)
5		ssrabdf.2	. . 3 ⊢ Ⅎ𝑥𝐵
6		ssrabdf.1	. . 3 ⊢ Ⅎ𝑥𝐴
7	5, 6	ssrabf 46222	. 2 ⊢ (𝐵 ⊆ {𝑥 ∈ 𝐴 ∣ 𝜓} ↔ (𝐵 ⊆ 𝐴 ∧ ∀𝑥 ∈ 𝐵 𝜓))
8	1, 4, 7	sylanbrc 595	1 ⊢ (𝜑 → 𝐵 ⊆ {𝑥 ∈ 𝐴 ∣ 𝜓})

This proof depends on syntax axioms:   → wi 4   ∧ wa 401  Ⅎwnf 1815   ∈ wcel 2144  Ⅎwnfc 2907  ∀wral 3076  {crab 3412   ⊆ wss 3895

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-10 2177  ax-11 2193  ax-12 2212  ax-ext 2732

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1572  df-ex 1812  df-nf 1816  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ral 3077  df-rab 3413  df-ss 3896

This theorem is used by:  smfpimne2  47943