Theorem symdifv 5045

Description: The symmetric difference with the universal class is the complement. (Contributed by Scott Fenton, 24-Apr-2012.)

Assertion

Ref	Expression
symdifv	⊢ (𝐴 △ V) = (V ∖ 𝐴)

Proof of Theorem symdifv

Step	Hyp	Ref	Expression
1		df-symdif 4197	. 2 ⊢ (𝐴 △ V) = ((𝐴 ∖ V) ∪ (V ∖ 𝐴))
2		ssv 3933	. . . 4 ⊢ 𝐴 ⊆ V
3		ssdif0 4313	. . . 4 ⊢ (𝐴 ⊆ V ↔ (𝐴 ∖ V) = ∅)
4	2, 3	mpbi 233	. . 3 ⊢ (𝐴 ∖ V) = ∅
5	4	uneq1i 4162	. 2 ⊢ ((𝐴 ∖ V) ∪ (V ∖ 𝐴)) = (∅ ∪ (V ∖ 𝐴))
6		0un 4345	. 2 ⊢ (∅ ∪ (V ∖ 𝐴)) = (V ∖ 𝐴)
7	1, 5, 6	3eqtri 2787	1 ⊢ (𝐴 △ V) = (V ∖ 𝐴)

This proof depends on syntax axioms:   = wceq 1569  Vcvv 3450   ⊆ wss 3896   ∖ cdif 4044   ∪ cun 4148   △ csymdif 4196  ∅c0 4277

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-ext 2732

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1572  df-fal 1582  df-ex 1812  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-v 3452  df-ss 3897  df-dif 4046  df-un 4150  df-symdif 4197  df-nul 4278

This theorem is used by: (None)