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Theorem 3vded21 817
Description: A 3-variable theorem. Experiment with weak deduction theorem. (Contributed by NM, 31-Oct-1998.)
Hypotheses
Ref Expression
3vded21.1 c ≤ ((a →0 b) →0 (c →2 b))
3vded21.2 c ≤ (a →0 b)
Assertion
Ref Expression
3vded21 c ≤ b

Proof of Theorem 3vded21
StepHypRef Expression
1 3vded21.2 . . . . . . 7 c ≤ (a →0 b)
2 df-i0 43 . . . . . . 7 (a →0 b) = (a⊥ ∪ b)
31, 2lbtr 139 . . . . . 6 c ≤ (a⊥ ∪ b)
4 3vded21.1 . . . . . . 7 c ≤ ((a →0 b) →0 (c →2 b))
5 df-i0 43 . . . . . . . 8 ((a →0 b) →0 (c →2 b)) = ((a →0 b)⊥ ∪ (c →2 b))
62ax-r4 37 . . . . . . . . 9 (a →0 b)⊥ = (a⊥ ∪ b)⊥
7 df-i2 45 . . . . . . . . . 10 (c →2 b) = (b ∪ (c⊥ ∩ b⊥ ))
8 anor3 90 . . . . . . . . . . 11 (c⊥ ∩ b⊥ ) = (c ∪ b)⊥
98lor 70 . . . . . . . . . 10 (b ∪ (c⊥ ∩ b⊥ )) = (b ∪ (c ∪ b)⊥ )
107, 9ax-r2 36 . . . . . . . . 9 (c →2 b) = (b ∪ (c ∪ b)⊥ )
116, 102or 72 . . . . . . . 8 ((a →0 b)⊥ ∪ (c →2 b)) = ((a⊥ ∪ b)⊥ ∪ (b ∪ (c ∪ b)⊥ ))
12 ax-a2 31 . . . . . . . 8 ((a⊥ ∪ b)⊥ ∪ (b ∪ (c ∪ b)⊥ )) = ((b ∪ (c ∪ b)⊥ ) ∪ (a⊥ ∪ b)⊥ )
135, 11, 123tr 65 . . . . . . 7 ((a →0 b) →0 (c →2 b)) = ((b ∪ (c ∪ b)⊥ ) ∪ (a⊥ ∪ b)⊥ )
144, 13lbtr 139 . . . . . 6 c ≤ ((b ∪ (c ∪ b)⊥ ) ∪ (a⊥ ∪ b)⊥ )
153, 14ler2an 173 . . . . 5 c ≤ ((a⊥ ∪ b) ∩ ((b ∪ (c ∪ b)⊥ ) ∪ (a⊥ ∪ b)⊥ ))
16 comor2 462 . . . . . . . 8 (a⊥ ∪ b) C b
173leror 152 . . . . . . . . . . . 12 (c ∪ b) ≤ ((a⊥ ∪ b) ∪ b)
18 ax-a3 32 . . . . . . . . . . . . 13 ((a⊥ ∪ b) ∪ b) = (a⊥ ∪ (b ∪ b))
19 oridm 110 . . . . . . . . . . . . . 14 (b ∪ b) = b
2019lor 70 . . . . . . . . . . . . 13 (a⊥ ∪ (b ∪ b)) = (a⊥ ∪ b)
2118, 20ax-r2 36 . . . . . . . . . . . 12 ((a⊥ ∪ b) ∪ b) = (a⊥ ∪ b)
2217, 21lbtr 139 . . . . . . . . . . 11 (c ∪ b) ≤ (a⊥ ∪ b)
2322lecom 180 . . . . . . . . . 10 (c ∪ b) C (a⊥ ∪ b)
2423comcom 453 . . . . . . . . 9 (a⊥ ∪ b) C (c ∪ b)
2524comcom2 183 . . . . . . . 8 (a⊥ ∪ b) C (c ∪ b)⊥
2616, 25com2or 483 . . . . . . 7 (a⊥ ∪ b) C (b ∪ (c ∪ b)⊥ )
27 comid 187 . . . . . . . 8 (a⊥ ∪ b) C (a⊥ ∪ b)
2827comcom2 183 . . . . . . 7 (a⊥ ∪ b) C (a⊥ ∪ b)⊥
2926, 28fh1 469 . . . . . 6 ((a⊥ ∪ b) ∩ ((b ∪ (c ∪ b)⊥ ) ∪ (a⊥ ∪ b)⊥ )) = (((a⊥ ∪ b) ∩ (b ∪ (c ∪ b)⊥ )) ∪ ((a⊥ ∪ b) ∩ (a⊥ ∪ b)⊥ ))
30 or0 102 . . . . . . 7 ((((a⊥ ∪ b) ∩ b) ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ )) ∪ 0) = (((a⊥ ∪ b) ∩ b) ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ ))
3116, 25fh1 469 . . . . . . . . 9 ((a⊥ ∪ b) ∩ (b ∪ (c ∪ b)⊥ )) = (((a⊥ ∪ b) ∩ b) ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ ))
3231ax-r1 35 . . . . . . . 8 (((a⊥ ∪ b) ∩ b) ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ )) = ((a⊥ ∪ b) ∩ (b ∪ (c ∪ b)⊥ ))
33 dff 101 . . . . . . . 8 0 = ((a⊥ ∪ b) ∩ (a⊥ ∪ b)⊥ )
3432, 332or 72 . . . . . . 7 ((((a⊥ ∪ b) ∩ b) ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ )) ∪ 0) = (((a⊥ ∪ b) ∩ (b ∪ (c ∪ b)⊥ )) ∪ ((a⊥ ∪ b) ∩ (a⊥ ∪ b)⊥ ))
35 ax-a2 31 . . . . . . . . . 10 (a⊥ ∪ b) = (b ∪ a⊥ )
3635ran 78 . . . . . . . . 9 ((a⊥ ∪ b) ∩ b) = ((b ∪ a⊥ ) ∩ b)
37 ancom 74 . . . . . . . . 9 ((b ∪ a⊥ ) ∩ b) = (b ∩ (b ∪ a⊥ ))
38 anabs 121 . . . . . . . . 9 (b ∩ (b ∪ a⊥ )) = b
3936, 37, 383tr 65 . . . . . . . 8 ((a⊥ ∪ b) ∩ b) = b
4039ax-r5 38 . . . . . . 7 (((a⊥ ∪ b) ∩ b) ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ )) = (b ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ ))
4130, 34, 403tr2 64 . . . . . 6 (((a⊥ ∪ b) ∩ (b ∪ (c ∪ b)⊥ )) ∪ ((a⊥ ∪ b) ∩ (a⊥ ∪ b)⊥ )) = (b ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ ))
4229, 41ax-r2 36 . . . . 5 ((a⊥ ∪ b) ∩ ((b ∪ (c ∪ b)⊥ ) ∪ (a⊥ ∪ b)⊥ )) = (b ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ ))
4315, 42lbtr 139 . . . 4 c ≤ (b ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ ))
4443leran 153 . . 3 (c ∩ (c ∪ b)) ≤ ((b ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ )) ∩ (c ∪ b))
45 anabs 121 . . 3 (c ∩ (c ∪ b)) = c
46 comor2 462 . . . . 5 (c ∪ b) C b
47 comid 187 . . . . . . 7 (c ∪ b) C (c ∪ b)
4847comcom2 183 . . . . . 6 (c ∪ b) C (c ∪ b)⊥
4923, 48com2an 484 . . . . 5 (c ∪ b) C ((a⊥ ∪ b) ∩ (c ∪ b)⊥ )
5046, 49fh1r 473 . . . 4 ((b ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ )) ∩ (c ∪ b)) = ((b ∩ (c ∪ b)) ∪ (((a⊥ ∪ b) ∩ (c ∪ b)⊥ ) ∩ (c ∪ b)))
51 ax-a2 31 . . . . . . 7 (c ∪ b) = (b ∪ c)
5251lan 77 . . . . . 6 (b ∩ (c ∪ b)) = (b ∩ (b ∪ c))
53 anabs 121 . . . . . 6 (b ∩ (b ∪ c)) = b
5452, 53ax-r2 36 . . . . 5 (b ∩ (c ∪ b)) = b
55 an32 83 . . . . . 6 (((a⊥ ∪ b) ∩ (c ∪ b)⊥ ) ∩ (c ∪ b)) = (((a⊥ ∪ b) ∩ (c ∪ b)) ∩ (c ∪ b)⊥ )
56 anass 76 . . . . . 6 (((a⊥ ∪ b) ∩ (c ∪ b)) ∩ (c ∪ b)⊥ ) = ((a⊥ ∪ b) ∩ ((c ∪ b) ∩ (c ∪ b)⊥ ))
57 dff 101 . . . . . . . . 9 0 = ((c ∪ b) ∩ (c ∪ b)⊥ )
5857lan 77 . . . . . . . 8 ((a⊥ ∪ b) ∩ 0) = ((a⊥ ∪ b) ∩ ((c ∪ b) ∩ (c ∪ b)⊥ ))
5958ax-r1 35 . . . . . . 7 ((a⊥ ∪ b) ∩ ((c ∪ b) ∩ (c ∪ b)⊥ )) = ((a⊥ ∪ b) ∩ 0)
60 an0 108 . . . . . . 7 ((a⊥ ∪ b) ∩ 0) = 0
6159, 60ax-r2 36 . . . . . 6 ((a⊥ ∪ b) ∩ ((c ∪ b) ∩ (c ∪ b)⊥ )) = 0
6255, 56, 613tr 65 . . . . 5 (((a⊥ ∪ b) ∩ (c ∪ b)⊥ ) ∩ (c ∪ b)) = 0
6354, 622or 72 . . . 4 ((b ∩ (c ∪ b)) ∪ (((a⊥ ∪ b) ∩ (c ∪ b)⊥ ) ∩ (c ∪ b))) = (b ∪ 0)
6450, 63ax-r2 36 . . 3 ((b ∪ ((a⊥ ∪ b) ∩ (c ∪ b)⊥ )) ∩ (c ∪ b)) = (b ∪ 0)
6544, 45, 64le3tr2 141 . 2 c ≤ (b ∪ 0)
66 or0 102 . 2 (b ∪ 0) = b
6765, 66lbtr 139 1 c ≤ b
Colors of variables:    term
This proof depends on syntax axioms:   ≤ wle 2  ⊥ wn 4   ∪ wo 6   ∩ wa 7  0wf 9   →0 wi0 11   →2 wi2 13
This proof depends on axioms:  ax-a1 30  ax-a2 31  ax-a3 32  ax-a4 33  ax-a5 34  ax-r1 35  ax-r2 36  ax-r4 37  ax-r5 38  ax-r3 439
This proof depends on definitions:  df-b 39  df-a 40  df-t 41  df-f 42  df-i0 43  df-i2 45  df-le1 130  df-le2 131  df-c1 132  df-c2 133
This theorem is used by:  3vded22  818
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