Theorem eqnetrd 2399

Description: Substitution of equal classes into an inequality. (Contributed by NM, 4-Jul-2012.)

Hypotheses

Ref	Expression
eqnetrd.1	⊢ (𝜑 → 𝐴 = 𝐵)
eqnetrd.2	⊢ (𝜑 → 𝐵 ≠ 𝐶)

Assertion

Ref	Expression
eqnetrd	⊢ (𝜑 → 𝐴 ≠ 𝐶)

Proof of Theorem eqnetrd

Step	Hyp	Ref	Expression
1		eqnetrd.2	. 2 ⊢ (𝜑 → 𝐵 ≠ 𝐶)
2		eqnetrd.1	. . 3 ⊢ (𝜑 → 𝐴 = 𝐵)
3	2	neeq1d 2393	. 2 ⊢ (𝜑 → (𝐴 ≠ 𝐶 ↔ 𝐵 ≠ 𝐶))
4	1, 3	mpbird 167	1 ⊢ (𝜑 → 𝐴 ≠ 𝐶)

Syntax hints:   → wi 4   = wceq 1372   ≠ wne 2375

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-5 1469  ax-gen 1471  ax-4 1532  ax-17 1548  ax-ext 2186

This theorem depends on definitions:  df-bi 117  df-cleq 2197  df-ne 2376

This theorem is referenced by:  eqnetrrd  2401  ifnetruedc  3612  ifnefals  3613  frecabcl  6475  frecsuclem  6482  omp1eomlem  7178  xaddnemnf  9961  xaddnepnf  9962  hashprg  10934  bezoutr1  12273  phibndlem  12457  dfphi2  12461  lgsne0  15433  2sqlem8a  15517  2sqlem8  15518