Theorem ifsbdc 3588

Description: Distribute a function over an if-clause. (Contributed by Jim Kingdon, 1-Jan-2022.)

Hypotheses

Ref	Expression
ifsbdc.1	⊢ (if(𝜑, 𝐴, 𝐵) = 𝐴 → 𝐶 = 𝐷)
ifsbdc.2	⊢ (if(𝜑, 𝐴, 𝐵) = 𝐵 → 𝐶 = 𝐸)

Assertion

Ref	Expression
ifsbdc	⊢ (DECID 𝜑 → 𝐶 = if(𝜑, 𝐷, 𝐸))

Proof of Theorem ifsbdc

Step	Hyp	Ref	Expression
1		exmiddc 838	. 2 ⊢ (DECID 𝜑 → (𝜑 ∨ ¬ 𝜑))
2		iftrue 3580	. . . . 5 ⊢ (𝜑 → if(𝜑, 𝐴, 𝐵) = 𝐴)
3		ifsbdc.1	. . . . 5 ⊢ (if(𝜑, 𝐴, 𝐵) = 𝐴 → 𝐶 = 𝐷)
4	2, 3	syl 14	. . . 4 ⊢ (𝜑 → 𝐶 = 𝐷)
5		iftrue 3580	. . . 4 ⊢ (𝜑 → if(𝜑, 𝐷, 𝐸) = 𝐷)
6	4, 5	eqtr4d 2242	. . 3 ⊢ (𝜑 → 𝐶 = if(𝜑, 𝐷, 𝐸))
7		iffalse 3583	. . . . 5 ⊢ (¬ 𝜑 → if(𝜑, 𝐴, 𝐵) = 𝐵)
8		ifsbdc.2	. . . . 5 ⊢ (if(𝜑, 𝐴, 𝐵) = 𝐵 → 𝐶 = 𝐸)
9	7, 8	syl 14	. . . 4 ⊢ (¬ 𝜑 → 𝐶 = 𝐸)
10		iffalse 3583	. . . 4 ⊢ (¬ 𝜑 → if(𝜑, 𝐷, 𝐸) = 𝐸)
11	9, 10	eqtr4d 2242	. . 3 ⊢ (¬ 𝜑 → 𝐶 = if(𝜑, 𝐷, 𝐸))
12	6, 11	jaoi 718	. 2 ⊢ ((𝜑 ∨ ¬ 𝜑) → 𝐶 = if(𝜑, 𝐷, 𝐸))
13	1, 12	syl 14	1 ⊢ (DECID 𝜑 → 𝐶 = if(𝜑, 𝐷, 𝐸))

Syntax hints:  ¬ wn 3   → wi 4   ∨ wo 710  DECID wdc 836   = wceq 1373  ifcif 3575

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in2 616  ax-io 711  ax-5 1471  ax-7 1472  ax-gen 1473  ax-ie1 1517  ax-ie2 1518  ax-8 1528  ax-11 1530  ax-4 1534  ax-17 1550  ax-i9 1554  ax-ial 1558  ax-i5r 1559  ax-ext 2188

This theorem depends on definitions:  df-bi 117  df-dc 837  df-nf 1485  df-sb 1787  df-clab 2193  df-cleq 2199  df-clel 2202  df-if 3576

This theorem is referenced by:  fvifdc  5611  lgsneg  15576  lgsdilem  15579