Theorem axc11n11r 37800

Description: Proof of axc11n 2458 from { ax-1 6-- ax-7 2043, axc9 2414, axc11r 2400 } (note that axc16 2299 is provable from { ax-1 6-- ax-7 2043, axc11r 2400 }).

Theorem axc11n 2458 proves (over minimal calculus) that axc11 2462 and axc11r 2400 are equivalent. Therefore, axc11n11 37799 and axc11n11r 37800 prove that one can use one or the other as an axiom, provided one assumes the axioms listed above (axc11 2462 appears slightly stronger since axc11n11r 37800 requires axc9 2414 while axc11n11 37799 does not).

(Contributed by BJ, 6-Jul-2021.) (Proof modification is discouraged.)

Assertion

Ref	Expression
axc11n11r	⊢ (∀𝑥 𝑥 = 𝑦 → ∀𝑦 𝑦 = 𝑥)

Proof of Theorem axc11n11r

Dummy variable 𝑧 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		equcomi 2052	. . . . 5 ⊢ (𝑥 = 𝑦 → 𝑦 = 𝑥)
2		axc16 2299	. . . . 5 ⊢ (∀𝑦 𝑦 = 𝑧 → (𝑦 = 𝑥 → ∀𝑦 𝑦 = 𝑥))
3	1, 2	syl5 35	. . . 4 ⊢ (∀𝑦 𝑦 = 𝑧 → (𝑥 = 𝑦 → ∀𝑦 𝑦 = 𝑥))
4	3	spsd 2227	. . 3 ⊢ (∀𝑦 𝑦 = 𝑧 → (∀𝑥 𝑥 = 𝑦 → ∀𝑦 𝑦 = 𝑥))
5	4	exlimiv 1965	. 2 ⊢ (∃𝑧∀𝑦 𝑦 = 𝑧 → (∀𝑥 𝑥 = 𝑦 → ∀𝑦 𝑦 = 𝑥))
6		alnex 1814	. . 3 ⊢ (∀𝑧 ¬ ∀𝑦 𝑦 = 𝑧 ↔ ¬ ∃𝑧∀𝑦 𝑦 = 𝑧)
7		ax6evr 2050	. . . . 5 ⊢ ∃𝑧 𝑥 = 𝑧
8		19.29 1908	. . . . 5 ⊢ ((∀𝑧 ¬ ∀𝑦 𝑦 = 𝑧 ∧ ∃𝑧 𝑥 = 𝑧) → ∃𝑧(¬ ∀𝑦 𝑦 = 𝑧 ∧ 𝑥 = 𝑧))
9	7, 8	mpan2 704	. . . 4 ⊢ (∀𝑧 ¬ ∀𝑦 𝑦 = 𝑧 → ∃𝑧(¬ ∀𝑦 𝑦 = 𝑧 ∧ 𝑥 = 𝑧))
10		axc9 2414	. . . . . . . . . . . 12 ⊢ (¬ ∀𝑦 𝑦 = 𝑥 → (¬ ∀𝑦 𝑦 = 𝑧 → (𝑥 = 𝑧 → ∀𝑦 𝑥 = 𝑧)))
11	10	impcom 413	. . . . . . . . . . 11 ⊢ ((¬ ∀𝑦 𝑦 = 𝑧 ∧ ¬ ∀𝑦 𝑦 = 𝑥) → (𝑥 = 𝑧 → ∀𝑦 𝑥 = 𝑧))
12		axc11r 2400	. . . . . . . . . . 11 ⊢ (∀𝑥 𝑥 = 𝑦 → (∀𝑦 𝑥 = 𝑧 → ∀𝑥 𝑥 = 𝑧))
13	11, 12	syl9 78	. . . . . . . . . 10 ⊢ ((¬ ∀𝑦 𝑦 = 𝑧 ∧ ¬ ∀𝑦 𝑦 = 𝑥) → (∀𝑥 𝑥 = 𝑦 → (𝑥 = 𝑧 → ∀𝑥 𝑥 = 𝑧)))
14		aev 2094	. . . . . . . . . 10 ⊢ (∀𝑥 𝑥 = 𝑧 → ∀𝑦 𝑦 = 𝑥)
15	13, 14	syl8 77	. . . . . . . . 9 ⊢ ((¬ ∀𝑦 𝑦 = 𝑧 ∧ ¬ ∀𝑦 𝑦 = 𝑥) → (∀𝑥 𝑥 = 𝑦 → (𝑥 = 𝑧 → ∀𝑦 𝑦 = 𝑥)))
16	15	ex 418	. . . . . . . 8 ⊢ (¬ ∀𝑦 𝑦 = 𝑧 → (¬ ∀𝑦 𝑦 = 𝑥 → (∀𝑥 𝑥 = 𝑦 → (𝑥 = 𝑧 → ∀𝑦 𝑦 = 𝑥))))
17	16	com24 96	. . . . . . 7 ⊢ (¬ ∀𝑦 𝑦 = 𝑧 → (𝑥 = 𝑧 → (∀𝑥 𝑥 = 𝑦 → (¬ ∀𝑦 𝑦 = 𝑥 → ∀𝑦 𝑦 = 𝑥))))
18	17	imp 412	. . . . . 6 ⊢ ((¬ ∀𝑦 𝑦 = 𝑧 ∧ 𝑥 = 𝑧) → (∀𝑥 𝑥 = 𝑦 → (¬ ∀𝑦 𝑦 = 𝑥 → ∀𝑦 𝑦 = 𝑥)))
19		pm2.18 129	. . . . . 6 ⊢ ((¬ ∀𝑦 𝑦 = 𝑥 → ∀𝑦 𝑦 = 𝑥) → ∀𝑦 𝑦 = 𝑥)
20	18, 19	syl6 36	. . . . 5 ⊢ ((¬ ∀𝑦 𝑦 = 𝑧 ∧ 𝑥 = 𝑧) → (∀𝑥 𝑥 = 𝑦 → ∀𝑦 𝑦 = 𝑥))
21	20	exlimiv 1965	. . . 4 ⊢ (∃𝑧(¬ ∀𝑦 𝑦 = 𝑧 ∧ 𝑥 = 𝑧) → (∀𝑥 𝑥 = 𝑦 → ∀𝑦 𝑦 = 𝑥))
22	9, 21	syl 18	. . 3 ⊢ (∀𝑧 ¬ ∀𝑦 𝑦 = 𝑧 → (∀𝑥 𝑥 = 𝑦 → ∀𝑦 𝑦 = 𝑥))
23	6, 22	sylbir 238	. 2 ⊢ (¬ ∃𝑧∀𝑦 𝑦 = 𝑧 → (∀𝑥 𝑥 = 𝑦 → ∀𝑦 𝑦 = 𝑥))
24	5, 23	pm2.61i 184	1 ⊢ (∀𝑥 𝑥 = 𝑦 → ∀𝑦 𝑦 = 𝑥)

This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ∧ wa 401  ∀wal 1568  ∃wex 1812

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-10 2180  ax-12 2216  ax-13 2404

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1573  df-ex 1813  df-nf 1817

This theorem is used by: (None)