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Theorem indifdi 4222
Description: Distribute intersection over difference. (Contributed by BTernaryTau, 14-Aug-2024.)
Assertion
Ref Expression
indifdi (𝐴 ∩ (𝐵𝐶)) = ((𝐴𝐵) ∖ (𝐴𝐶))

Proof of Theorem indifdi
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 elin 3899 . . 3 (𝑥 ∈ (𝐴 ∩ (𝐵𝐶)) ↔ (𝑥𝐴𝑥 ∈ (𝐵𝐶)))
2 eldif 3893 . . . 4 (𝑥 ∈ (𝐵𝐶) ↔ (𝑥𝐵 ∧ ¬ 𝑥𝐶))
32anbi2i 629 . . 3 ((𝑥𝐴𝑥 ∈ (𝐵𝐶)) ↔ (𝑥𝐴 ∧ (𝑥𝐵 ∧ ¬ 𝑥𝐶)))
4 abai 832 . . . . 5 ((𝑥𝐴 ∧ ¬ 𝑥𝐶) ↔ (𝑥𝐴 ∧ (𝑥𝐴 → ¬ 𝑥𝐶)))
54anbi2i 629 . . . 4 ((𝑥𝐵 ∧ (𝑥𝐴 ∧ ¬ 𝑥𝐶)) ↔ (𝑥𝐵 ∧ (𝑥𝐴 ∧ (𝑥𝐴 → ¬ 𝑥𝐶))))
6 an12 651 . . . 4 ((𝑥𝐴 ∧ (𝑥𝐵 ∧ ¬ 𝑥𝐶)) ↔ (𝑥𝐵 ∧ (𝑥𝐴 ∧ ¬ 𝑥𝐶)))
7 eldif 3893 . . . . 5 (𝑥 ∈ ((𝐴𝐵) ∖ (𝐴𝐶)) ↔ (𝑥 ∈ (𝐴𝐵) ∧ ¬ 𝑥 ∈ (𝐴𝐶)))
8 elin 3899 . . . . . . 7 (𝑥 ∈ (𝐴𝐵) ↔ (𝑥𝐴𝑥𝐵))
98bicomi 225 . . . . . 6 ((𝑥𝐴𝑥𝐵) ↔ 𝑥 ∈ (𝐴𝐵))
10 imnan 400 . . . . . . 7 ((𝑥𝐴 → ¬ 𝑥𝐶) ↔ ¬ (𝑥𝐴𝑥𝐶))
11 elin 3899 . . . . . . 7 (𝑥 ∈ (𝐴𝐶) ↔ (𝑥𝐴𝑥𝐶))
1210, 11xchbinxr 336 . . . . . 6 ((𝑥𝐴 → ¬ 𝑥𝐶) ↔ ¬ 𝑥 ∈ (𝐴𝐶))
139, 12anbi12i 634 . . . . 5 (((𝑥𝐴𝑥𝐵) ∧ (𝑥𝐴 → ¬ 𝑥𝐶)) ↔ (𝑥 ∈ (𝐴𝐵) ∧ ¬ 𝑥 ∈ (𝐴𝐶)))
14 an21 650 . . . . 5 (((𝑥𝐴𝑥𝐵) ∧ (𝑥𝐴 → ¬ 𝑥𝐶)) ↔ (𝑥𝐵 ∧ (𝑥𝐴 ∧ (𝑥𝐴 → ¬ 𝑥𝐶))))
157, 13, 143bitr2i 300 . . . 4 (𝑥 ∈ ((𝐴𝐵) ∖ (𝐴𝐶)) ↔ (𝑥𝐵 ∧ (𝑥𝐴 ∧ (𝑥𝐴 → ¬ 𝑥𝐶))))
165, 6, 153bitr4i 304 . . 3 ((𝑥𝐴 ∧ (𝑥𝐵 ∧ ¬ 𝑥𝐶)) ↔ 𝑥 ∈ ((𝐴𝐵) ∖ (𝐴𝐶)))
171, 3, 163bitri 298 . 2 (𝑥 ∈ (𝐴 ∩ (𝐵𝐶)) ↔ 𝑥 ∈ ((𝐴𝐵) ∖ (𝐴𝐶)))
1817eqriv 2736 1 (𝐴 ∩ (𝐵𝐶)) = ((𝐴𝐵) ∖ (𝐴𝐶))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wa 396   = wceq 1547  wcel 2119  cdif 3880  cin 3882
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802  ax-4 1816  ax-5 1917  ax-6 1974  ax-7 2015  ax-8 2121  ax-9 2129  ax-ext 2711
This theorem depends on definitions:  df-bi 208  df-an 397  df-tru 1550  df-ex 1787  df-sb 2074  df-clab 2718  df-cleq 2731  df-clel 2814  df-v 3433  df-dif 3886  df-in 3890
This theorem is referenced by:  indifdir  4223  resdifdi  6187  iscnrm3rlem4  49433
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