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Theorem kmlem6 10109
Description: Lemma for 5-quantifier AC of Kurt Maes, Th. 4, part of 4 => 1. (Contributed by NM, 26-Mar-2004.)
Assertion
Ref Expression
kmlem6 ((∀𝑧𝑥 𝑧 ≠ ∅ ∧ ∀𝑧𝑥𝑤𝑥 (𝜑𝐴 = ∅)) → ∀𝑧𝑥𝑣𝑧𝑤𝑥 (𝜑 → ¬ 𝑣𝐴))
Distinct variable groups:   𝑣,𝐴   𝑥,𝑣,𝜑   𝑤,𝑣,𝑧,𝑥
Allowed substitution hints:   𝜑(𝑧,𝑤)   𝐴(𝑥,𝑧,𝑤)

Proof of Theorem kmlem6
StepHypRef Expression
1 r19.26 3121 . 2 (∀𝑧𝑥 (𝑧 ≠ ∅ ∧ ∀𝑤𝑥 (𝜑𝐴 = ∅)) ↔ (∀𝑧𝑥 𝑧 ≠ ∅ ∧ ∀𝑧𝑥𝑤𝑥 (𝜑𝐴 = ∅)))
2 n0 4305 . . . . 5 (𝑧 ≠ ∅ ↔ ∃𝑣 𝑣𝑧)
32biimpi 218 . . . 4 (𝑧 ≠ ∅ → ∃𝑣 𝑣𝑧)
4 ne0i 4293 . . . . . . . 8 (𝑣𝐴𝐴 ≠ ∅)
54necon2bi 2986 . . . . . . 7 (𝐴 = ∅ → ¬ 𝑣𝐴)
65imim2i 16 . . . . . 6 ((𝜑𝐴 = ∅) → (𝜑 → ¬ 𝑣𝐴))
76ralimi 3098 . . . . 5 (∀𝑤𝑥 (𝜑𝐴 = ∅) → ∀𝑤𝑥 (𝜑 → ¬ 𝑣𝐴))
87alrimiv 1946 . . . 4 (∀𝑤𝑥 (𝜑𝐴 = ∅) → ∀𝑣𝑤𝑥 (𝜑 → ¬ 𝑣𝐴))
9 19.29r 1893 . . . . 5 ((∃𝑣 𝑣𝑧 ∧ ∀𝑣𝑤𝑥 (𝜑 → ¬ 𝑣𝐴)) → ∃𝑣(𝑣𝑧 ∧ ∀𝑤𝑥 (𝜑 → ¬ 𝑣𝐴)))
10 df-rex 3086 . . . . 5 (∃𝑣𝑧𝑤𝑥 (𝜑 → ¬ 𝑣𝐴) ↔ ∃𝑣(𝑣𝑧 ∧ ∀𝑤𝑥 (𝜑 → ¬ 𝑣𝐴)))
119, 10sylibr 236 . . . 4 ((∃𝑣 𝑣𝑧 ∧ ∀𝑣𝑤𝑥 (𝜑 → ¬ 𝑣𝐴)) → ∃𝑣𝑧𝑤𝑥 (𝜑 → ¬ 𝑣𝐴))
123, 8, 11syl2an 605 . . 3 ((𝑧 ≠ ∅ ∧ ∀𝑤𝑥 (𝜑𝐴 = ∅)) → ∃𝑣𝑧𝑤𝑥 (𝜑 → ¬ 𝑣𝐴))
1312ralimi 3098 . 2 (∀𝑧𝑥 (𝑧 ≠ ∅ ∧ ∀𝑤𝑥 (𝜑𝐴 = ∅)) → ∀𝑧𝑥𝑣𝑧𝑤𝑥 (𝜑 → ¬ 𝑣𝐴))
141, 13sylbir 237 1 ((∀𝑧𝑥 𝑧 ≠ ∅ ∧ ∀𝑧𝑥𝑤𝑥 (𝜑𝐴 = ∅)) → ∀𝑧𝑥𝑣𝑧𝑤𝑥 (𝜑 → ¬ 𝑣𝐴))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wa 399  wal 1557   = wceq 1559  wex 1798  wcel 2141  wne 2956  wral 3075  wrex 3085  c0 4285
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1814  ax-4 1828  ax-5 1929  ax-6 1986  ax-7 2027  ax-8 2143  ax-9 2151  ax-ext 2733
This theorem depends on definitions:  df-bi 209  df-an 400  df-tru 1562  df-fal 1572  df-ex 1799  df-sb 2090  df-clab 2740  df-cleq 2753  df-clel 2836  df-ne 2957  df-ral 3076  df-rex 3086  df-dif 3907  df-nul 4286
This theorem is referenced by:  kmlem7  10110
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