Theorem ssab2 4027

Description: Subclass relation for the restriction of a class abstraction. Prefer using the more natural statement ssrab2 4028. (Contributed by NM, 31-Mar-1995.)

Assertion

Ref	Expression
ssab2	⊢ {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜑)} ⊆ 𝐴

Distinct variable group:   𝑥,𝐴

Allowed substitution hint:   𝜑(𝑥)

Proof of Theorem ssab2

Step	Hyp	Ref	Expression
1		simpl 488	. 2 ⊢ ((𝑥 ∈ 𝐴 ∧ 𝜑) → 𝑥 ∈ 𝐴)
2	1	abssi 4016	1 ⊢ {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜑)} ⊆ 𝐴

This proof depends on syntax axioms:   ∧ wa 401   ∈ wcel 2145  {cab 2738   ⊆ wss 3899

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732

This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-ss 3916

This theorem is used by:  sepab  5297  exss  5438  dmopabss  5902  rnopabss  5939  isf32lem9  10364  psubspset  40618  psubclsetN  40810