| Metamath Proof Explorer |
< Previous
Next >
Nearby theorems |
||
| Mirrors > Home > MPE Home > Th. List > sscon34b | Structured version Visualization version GIF version | ||
| Description: Relative complementation reverses inclusion of subclasses. Relativized version of complss 4081. (Contributed by RP, 3-Jun-2021.) |
| Ref | Expression |
|---|---|
| sscon34b | ⊢ ((𝐴 ⊆ 𝐶 ∧ 𝐵 ⊆ 𝐶) → (𝐴 ⊆ 𝐵 ↔ (𝐶 ∖ 𝐵) ⊆ (𝐶 ∖ 𝐴))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | sscon 4073 | . 2 ⊢ (𝐴 ⊆ 𝐵 → (𝐶 ∖ 𝐵) ⊆ (𝐶 ∖ 𝐴)) | |
| 2 | sscon 4073 | . . 3 ⊢ ((𝐶 ∖ 𝐵) ⊆ (𝐶 ∖ 𝐴) → (𝐶 ∖ (𝐶 ∖ 𝐴)) ⊆ (𝐶 ∖ (𝐶 ∖ 𝐵))) | |
| 3 | dfss4 4197 | . . . . 5 ⊢ (𝐴 ⊆ 𝐶 ↔ (𝐶 ∖ (𝐶 ∖ 𝐴)) = 𝐴) | |
| 4 | 3 | birani 504 | . . . 4 ⊢ ((𝐴 ⊆ 𝐶 ∧ 𝐵 ⊆ 𝐶) → (𝐶 ∖ (𝐶 ∖ 𝐴)) = 𝐴) |
| 5 | dfss4 4197 | . . . . 5 ⊢ (𝐵 ⊆ 𝐶 ↔ (𝐶 ∖ (𝐶 ∖ 𝐵)) = 𝐵) | |
| 6 | 5 | bilani 505 | . . . 4 ⊢ ((𝐴 ⊆ 𝐶 ∧ 𝐵 ⊆ 𝐶) → (𝐶 ∖ (𝐶 ∖ 𝐵)) = 𝐵) |
| 7 | 4, 6 | sseq12d 3948 | . . 3 ⊢ ((𝐴 ⊆ 𝐶 ∧ 𝐵 ⊆ 𝐶) → ((𝐶 ∖ (𝐶 ∖ 𝐴)) ⊆ (𝐶 ∖ (𝐶 ∖ 𝐵)) ↔ 𝐴 ⊆ 𝐵)) |
| 8 | 2, 7 | imbitrid 245 | . 2 ⊢ ((𝐴 ⊆ 𝐶 ∧ 𝐵 ⊆ 𝐶) → ((𝐶 ∖ 𝐵) ⊆ (𝐶 ∖ 𝐴) → 𝐴 ⊆ 𝐵)) |
| 9 | 1, 8 | impbid2 227 | 1 ⊢ ((𝐴 ⊆ 𝐶 ∧ 𝐵 ⊆ 𝐶) → (𝐴 ⊆ 𝐵 ↔ (𝐶 ∖ 𝐵) ⊆ (𝐶 ∖ 𝐴))) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 ↔ wb 207 ∧ wa 396 = wceq 1547 ∖ cdif 3880 ⊆ wss 3883 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1802 ax-4 1816 ax-5 1917 ax-6 1974 ax-7 2015 ax-8 2121 ax-9 2129 ax-ext 2711 |
| This theorem depends on definitions: df-bi 208 df-an 397 df-3an 1094 df-tru 1550 df-ex 1787 df-sb 2074 df-clab 2718 df-cleq 2731 df-clel 2814 df-rab 3392 df-v 3433 df-dif 3886 df-in 3890 df-ss 3900 |
| This theorem is referenced by: rcompleq 4233 ntrclsss 44507 ntrclsiso 44511 ntrclsk2 44512 ntrclsk3 44514 |
| Copyright terms: Public domain | W3C validator |