| Metamath Proof Explorer |
< Previous
Next >
Nearby theorems |
||
| Mirrors > Home > MPE Home > Th. List > ssdifin0 | Structured version Visualization version GIF version | ||
| Description: A subset of a difference does not intersect the subtrahend. (Contributed by Jeff Hankins, 1-Sep-2013.) (Proof shortened by Mario Carneiro, 24-Aug-2015.) |
| Ref | Expression |
|---|---|
| ssdifin0 | ⊢ (𝐴 ⊆ (𝐵 ∖ 𝐶) → (𝐴 ∩ 𝐶) = ∅) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ssrin 4195 | . 2 ⊢ (𝐴 ⊆ (𝐵 ∖ 𝐶) → (𝐴 ∩ 𝐶) ⊆ ((𝐵 ∖ 𝐶) ∩ 𝐶)) | |
| 2 | disjdifr 4429 | . 2 ⊢ ((𝐵 ∖ 𝐶) ∩ 𝐶) = ∅ | |
| 3 | sseq0 4359 | . 2 ⊢ (((𝐴 ∩ 𝐶) ⊆ ((𝐵 ∖ 𝐶) ∩ 𝐶) ∧ ((𝐵 ∖ 𝐶) ∩ 𝐶) = ∅) → (𝐴 ∩ 𝐶) = ∅) | |
| 4 | 1, 2, 3 | sylancl 595 | 1 ⊢ (𝐴 ⊆ (𝐵 ∖ 𝐶) → (𝐴 ∩ 𝐶) = ∅) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 = wceq 1562 ∖ cdif 3903 ∩ cin 3905 ⊆ wss 3906 ∅c0 4287 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1817 ax-4 1831 ax-5 1932 ax-6 1989 ax-7 2030 ax-8 2146 ax-9 2154 ax-ext 2736 |
| This theorem depends on definitions: df-bi 209 df-an 400 df-tru 1565 df-fal 1575 df-ex 1802 df-sb 2093 df-clab 2743 df-cleq 2756 df-clel 2839 df-rab 3417 df-v 3458 df-dif 3909 df-in 3913 df-ss 3923 df-nul 4288 |
| This theorem is referenced by: ssdifeq0 4442 marypha1lem 9381 numacn 10007 mreexexlem2d 17679 mreexexlem4d 17681 nrmsep2 23418 isnrm3 23421 |
| Copyright terms: Public domain | W3C validator |