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| Mirrors > Home > MPE Home > Th. List > Mathboxes > uniinn0 | Structured version Visualization version GIF version | ||
| Description: Sufficient and necessary condition for a union to intersect with a given set. (Contributed by Thierry Arnoux, 27-Jan-2020.) |
| Ref | Expression |
|---|---|
| uniinn0 | ⊢ ((∪ 𝐴 ∩ 𝐵) ≠ ∅ ↔ ∃𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) ≠ ∅) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | nne 2968 | . . . 4 ⊢ (¬ (𝑥 ∩ 𝐵) ≠ ∅ ↔ (𝑥 ∩ 𝐵) = ∅) | |
| 2 | 1 | ralbii 3117 | . . 3 ⊢ (∀𝑥 ∈ 𝐴 ¬ (𝑥 ∩ 𝐵) ≠ ∅ ↔ ∀𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) = ∅) |
| 3 | ralnex 3097 | . . 3 ⊢ (∀𝑥 ∈ 𝐴 ¬ (𝑥 ∩ 𝐵) ≠ ∅ ↔ ¬ ∃𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) ≠ ∅) | |
| 4 | unissb 4907 | . . . 4 ⊢ (∪ 𝐴 ⊆ (V ∖ 𝐵) ↔ ∀𝑥 ∈ 𝐴 𝑥 ⊆ (V ∖ 𝐵)) | |
| 5 | disj2 4421 | . . . 4 ⊢ ((∪ 𝐴 ∩ 𝐵) = ∅ ↔ ∪ 𝐴 ⊆ (V ∖ 𝐵)) | |
| 6 | disj2 4421 | . . . . 5 ⊢ ((𝑥 ∩ 𝐵) = ∅ ↔ 𝑥 ⊆ (V ∖ 𝐵)) | |
| 7 | 6 | ralbii 3117 | . . . 4 ⊢ (∀𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) = ∅ ↔ ∀𝑥 ∈ 𝐴 𝑥 ⊆ (V ∖ 𝐵)) |
| 8 | 4, 5, 7 | 3bitr4ri 307 | . . 3 ⊢ (∀𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) = ∅ ↔ (∪ 𝐴 ∩ 𝐵) = ∅) |
| 9 | 2, 3, 8 | 3bitr3i 304 | . 2 ⊢ (¬ ∃𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) ≠ ∅ ↔ (∪ 𝐴 ∩ 𝐵) = ∅) |
| 10 | 9 | necon1abii 3012 | 1 ⊢ ((∪ 𝐴 ∩ 𝐵) ≠ ∅ ↔ ∃𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) ≠ ∅) |
| Colors of variables: wff setvar class |
| Syntax hints: ¬ wn 3 ↔ wb 209 = wceq 1567 ≠ wne 2964 ∀wral 3085 ∃wrex 3095 Vcvv 3463 ∖ cdif 3910 ∩ cin 3912 ⊆ wss 3913 ∅c0 4294 ∪ cuni 4873 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1822 ax-4 1836 ax-5 1937 ax-6 1994 ax-7 2035 ax-8 2151 ax-9 2159 ax-ext 2741 |
| This theorem depends on definitions: df-bi 210 df-an 401 df-tru 1570 df-fal 1580 df-ex 1807 df-sb 2098 df-clab 2748 df-cleq 2761 df-clel 2844 df-ne 2965 df-ral 3086 df-rex 3096 df-v 3465 df-dif 3916 df-in 3920 df-ss 3930 df-nul 4295 df-uni 4874 |
| This theorem is referenced by: locfinreflem 34171 |
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