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| Mirrors > Home > MPE Home > Th. List > Mathboxes > uniinn0 | Structured version Visualization version GIF version | ||
| Description: Sufficient and necessary condition for a union to intersect with a given set. (Contributed by Thierry Arnoux, 27-Jan-2020.) |
| Ref | Expression |
|---|---|
| uniinn0 | ⊢ ((∪ 𝐴 ∩ 𝐵) ≠ ∅ ↔ ∃𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) ≠ ∅) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | nne 2933 | . . . 4 ⊢ (¬ (𝑥 ∩ 𝐵) ≠ ∅ ↔ (𝑥 ∩ 𝐵) = ∅) | |
| 2 | 1 | ralbii 3079 | . . 3 ⊢ (∀𝑥 ∈ 𝐴 ¬ (𝑥 ∩ 𝐵) ≠ ∅ ↔ ∀𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) = ∅) |
| 3 | ralnex 3059 | . . 3 ⊢ (∀𝑥 ∈ 𝐴 ¬ (𝑥 ∩ 𝐵) ≠ ∅ ↔ ¬ ∃𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) ≠ ∅) | |
| 4 | unissb 4893 | . . . 4 ⊢ (∪ 𝐴 ⊆ (V ∖ 𝐵) ↔ ∀𝑥 ∈ 𝐴 𝑥 ⊆ (V ∖ 𝐵)) | |
| 5 | disj2 4407 | . . . 4 ⊢ ((∪ 𝐴 ∩ 𝐵) = ∅ ↔ ∪ 𝐴 ⊆ (V ∖ 𝐵)) | |
| 6 | disj2 4407 | . . . . 5 ⊢ ((𝑥 ∩ 𝐵) = ∅ ↔ 𝑥 ⊆ (V ∖ 𝐵)) | |
| 7 | 6 | ralbii 3079 | . . . 4 ⊢ (∀𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) = ∅ ↔ ∀𝑥 ∈ 𝐴 𝑥 ⊆ (V ∖ 𝐵)) |
| 8 | 4, 5, 7 | 3bitr4ri 304 | . . 3 ⊢ (∀𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) = ∅ ↔ (∪ 𝐴 ∩ 𝐵) = ∅) |
| 9 | 2, 3, 8 | 3bitr3i 301 | . 2 ⊢ (¬ ∃𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) ≠ ∅ ↔ (∪ 𝐴 ∩ 𝐵) = ∅) |
| 10 | 9 | necon1abii 2977 | 1 ⊢ ((∪ 𝐴 ∩ 𝐵) ≠ ∅ ↔ ∃𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) ≠ ∅) |
| Colors of variables: wff setvar class |
| Syntax hints: ¬ wn 3 ↔ wb 206 = wceq 1541 ≠ wne 2929 ∀wral 3048 ∃wrex 3057 Vcvv 3437 ∖ cdif 3895 ∩ cin 3897 ⊆ wss 3898 ∅c0 4282 ∪ cuni 4860 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1796 ax-4 1810 ax-5 1911 ax-6 1968 ax-7 2009 ax-8 2115 ax-9 2123 ax-ext 2705 |
| This theorem depends on definitions: df-bi 207 df-an 396 df-tru 1544 df-fal 1554 df-ex 1781 df-sb 2068 df-clab 2712 df-cleq 2725 df-clel 2808 df-ne 2930 df-ral 3049 df-rex 3058 df-v 3439 df-dif 3901 df-in 3905 df-ss 3915 df-nul 4283 df-uni 4861 |
| This theorem is referenced by: locfinreflem 33925 |
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