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| Mirrors > Home > MPE Home > Th. List > Mathboxes > uniinn0 | Structured version Visualization version GIF version | ||
| Description: Sufficient and necessary condition for a union to intersect with a given set. (Contributed by Thierry Arnoux, 27-Jan-2020.) |
| Ref | Expression |
|---|---|
| uniinn0 | ⊢ ((∪ 𝐴 ∩ 𝐵) ≠ ∅ ↔ ∃𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) ≠ ∅) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | nne 2964 | . . . 4 ⊢ (¬ (𝑥 ∩ 𝐵) ≠ ∅ ↔ (𝑥 ∩ 𝐵) = ∅) | |
| 2 | 1 | ralbii 3113 | . . 3 ⊢ (∀𝑥 ∈ 𝐴 ¬ (𝑥 ∩ 𝐵) ≠ ∅ ↔ ∀𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) = ∅) |
| 3 | ralnex 3093 | . . 3 ⊢ (∀𝑥 ∈ 𝐴 ¬ (𝑥 ∩ 𝐵) ≠ ∅ ↔ ¬ ∃𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) ≠ ∅) | |
| 4 | unissb 4908 | . . . 4 ⊢ (∪ 𝐴 ⊆ (V ∖ 𝐵) ↔ ∀𝑥 ∈ 𝐴 𝑥 ⊆ (V ∖ 𝐵)) | |
| 5 | disj2 4418 | . . . 4 ⊢ ((∪ 𝐴 ∩ 𝐵) = ∅ ↔ ∪ 𝐴 ⊆ (V ∖ 𝐵)) | |
| 6 | disj2 4418 | . . . . 5 ⊢ ((𝑥 ∩ 𝐵) = ∅ ↔ 𝑥 ⊆ (V ∖ 𝐵)) | |
| 7 | 6 | ralbii 3113 | . . . 4 ⊢ (∀𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) = ∅ ↔ ∀𝑥 ∈ 𝐴 𝑥 ⊆ (V ∖ 𝐵)) |
| 8 | 4, 5, 7 | 3bitr4ri 307 | . . 3 ⊢ (∀𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) = ∅ ↔ (∪ 𝐴 ∩ 𝐵) = ∅) |
| 9 | 2, 3, 8 | 3bitr3i 304 | . 2 ⊢ (¬ ∃𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) ≠ ∅ ↔ (∪ 𝐴 ∩ 𝐵) = ∅) |
| 10 | 9 | necon1abii 3008 | 1 ⊢ ((∪ 𝐴 ∩ 𝐵) ≠ ∅ ↔ ∃𝑥 ∈ 𝐴 (𝑥 ∩ 𝐵) ≠ ∅) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: ¬ wn 3 ↔ wb 209 = wceq 1570 ≠ wne 2960 ∀wral 3081 ∃wrex 3091 Vcvv 3457 ∖ cdif 3903 ∩ cin 3905 ⊆ wss 3906 ∅c0 4286 ∪ cuni 4874 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1828 ax-4 1842 ax-5 1943 ax-6 2000 ax-7 2041 ax-8 2148 ax-9 2156 ax-ext 2737 |
| This proof depends on definitions: df-bi 210 df-an 402 df-tru 1573 df-fal 1583 df-ex 1813 df-sb 2100 df-clab 2744 df-cleq 2757 df-clel 2840 df-ne 2961 df-ral 3082 df-rex 3092 df-v 3459 df-dif 3909 df-in 3913 df-ss 3923 df-nul 4287 df-uni 4875 |
| This theorem is used by: locfinreflem 34270 |
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