Theorem ordgt0ge1 6523

Description: Two ways to express that an ordinal class is positive. (Contributed by NM, 21-Dec-2004.)

Assertion

Ref	Expression
ordgt0ge1	|- ( Ord A -> ( (/) e. A <-> 1o C_ A ) )

Proof of Theorem ordgt0ge1

Step	Hyp	Ref	Expression
1		0elon 4440	. . 3 |- (/) e. On
2		ordelsuc 4554	. . 3 |- ( ( (/) e. On /\ Ord A ) -> ( (/) e. A <-> suc (/) C_ A ) )
3	1, 2	mpan 424	. 2 |- ( Ord A -> ( (/) e. A <-> suc (/) C_ A ) )
4		df-1o 6504	. . 3 |- 1o = suc (/)
5	4	sseq1i 3219	. 2 |- ( 1o C_ A <-> suc (/) C_ A )
6	3, 5	bitr4di 198	1 |- ( Ord A -> ( (/) e. A <-> 1o C_ A ) )

Syntax hints:   -> wi 4   <-> wb 105   e. wcel 2176   C_ wss 3166   (/)c0 3460   Ord word 4410   Oncon0 4411   suc csuc 4413   1oc1o 6497

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-io 711  ax-5 1470  ax-7 1471  ax-gen 1472  ax-ie1 1516  ax-ie2 1517  ax-8 1527  ax-10 1528  ax-11 1529  ax-i12 1530  ax-bndl 1532  ax-4 1533  ax-17 1549  ax-i9 1553  ax-ial 1557  ax-i5r 1558  ax-ext 2187  ax-nul 4171

This theorem depends on definitions:  df-bi 117  df-tru 1376  df-nf 1484  df-sb 1786  df-clab 2192  df-cleq 2198  df-clel 2201  df-nfc 2337  df-ral 2489  df-rex 2490  df-v 2774  df-dif 3168  df-un 3170  df-in 3172  df-ss 3179  df-nul 3461  df-pw 3618  df-sn 3639  df-uni 3851  df-tr 4144  df-iord 4414  df-on 4416  df-suc 4419  df-1o 6504

This theorem is referenced by:  ordge1n0im  6524  archnqq  7532