P. 65 of Theorem List - Intuitionistic Logic Explorer

Theorem List for Intuitionistic Logic Explorer - 6401-6500   *Has distinct variable group(s)

Type	Label	Description
Statement
Theorem	smoiso 6401	If F is an isomorphism from an ordinal A onto B, which is a subset of the ordinals, then F is a strictly monotonic function. Exercise 3 in [TakeutiZaring] p. 50. (Contributed by Andrew Salmon, 24-Nov-2011.)
|- ( ( F Isom _E , _E ( A , B ) /\ Ord A /\ B C_ On ) -> Smo F )
Theorem	smoel2 6402	A strictly monotone ordinal function preserves the epsilon relation. (Contributed by Mario Carneiro, 12-Mar-2013.)
|- ( ( ( F Fn A /\ Smo F ) /\ ( B e. A /\ C e. B ) ) -> ( F ` C ) e. ( F ` B ) )
2.6.20  "Strong" transfinite recursion
Syntax	crecs 6403	Notation for a function defined by strong transfinite recursion.
class recs ( F )
Definition	df-recs 6404*	Define a function recs ( F ) on On, the class of ordinal numbers, by transfinite recursion given a rule F which sets the next value given all values so far. See df-irdg 6469 for more details on why this definition is desirable. Unlike df-irdg 6469 which restricts the update rule to use only the previous value, this version allows the update rule to use all previous values, which is why it is described as "strong", although it is actually more primitive. See tfri1d 6434 and tfri2d 6435 for the primary contract of this definition. (Contributed by Stefan O'Rear, 18-Jan-2015.)
|- recs ( F ) = U. { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }
Theorem	recseq 6405	Equality theorem for recs. (Contributed by Stefan O'Rear, 18-Jan-2015.)
|- ( F = G -> recs ( F ) = recs ( G ) )
Theorem	nfrecs 6406	Bound-variable hypothesis builder for recs. (Contributed by Stefan O'Rear, 18-Jan-2015.)
|- F/_ x F   =>    |- F/_ xrecs ( F )
Theorem	tfrlem1 6407*	A technical lemma for transfinite recursion. Compare Lemma 1 of [TakeutiZaring] p. 47. (Contributed by NM, 23-Mar-1995.) (Revised by Mario Carneiro, 24-May-2019.)
|- ( ph -> A e. On )   &    |- ( ph -> ( Fun F /\ A C_ dom F ) )   &    |- ( ph -> ( Fun G /\ A C_ dom G ) )   &    |- ( ph -> A. x e. A ( F ` x ) = ( B ` ( F |` x ) ) )   &    |- ( ph -> A. x e. A ( G ` x ) = ( B ` ( G |` x ) ) )   =>    |- ( ph -> A. x e. A ( F ` x ) = ( G ` x ) )
Theorem	tfrlem3ag 6408*	Lemma for transfinite recursion. This lemma just changes some bound variables in A for later use. (Contributed by Jim Kingdon, 5-Jul-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   =>    |- ( G e. _V -> ( G e. A <-> E. z e. On ( G Fn z /\ A. w e. z ( G ` w ) = ( F ` ( G |` w ) ) ) ) )
Theorem	tfrlem3a 6409*	Lemma for transfinite recursion. Let A be the class of "acceptable" functions. The final thing we're interested in is the union of all these acceptable functions. This lemma just changes some bound variables in A for later use. (Contributed by NM, 9-Apr-1995.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   &    |- G e. _V   =>    |- ( G e. A <-> E. z e. On ( G Fn z /\ A. w e. z ( G ` w ) = ( F ` ( G |` w ) ) ) )
Theorem	tfrlem3 6410*	Lemma for transfinite recursion. Let A be the class of "acceptable" functions. The final thing we're interested in is the union of all these acceptable functions. This lemma just changes some bound variables in A for later use. (Contributed by NM, 9-Apr-1995.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   =>    |- A = { g | E. z e. On ( g Fn z /\ A. w e. z ( g ` w ) = ( F ` ( g |` w ) ) ) }
Theorem	tfrlem3-2d 6411*	Lemma for transfinite recursion which changes a bound variable (Contributed by Jim Kingdon, 2-Jul-2019.)
|- ( ph -> A. x ( Fun F /\ ( F ` x ) e. _V ) )   =>    |- ( ph -> ( Fun F /\ ( F ` g ) e. _V ) )
Theorem	tfrlem4 6412*	Lemma for transfinite recursion. A is the class of all "acceptable" functions, and F is their union. First we show that an acceptable function is in fact a function. (Contributed by NM, 9-Apr-1995.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   =>    |- ( g e. A -> Fun g )
Theorem	tfrlem5 6413*	Lemma for transfinite recursion. The values of two acceptable functions are the same within their domains. (Contributed by NM, 9-Apr-1995.) (Revised by Mario Carneiro, 24-May-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   =>    |- ( ( g e. A /\ h e. A ) -> ( ( x g u /\ x h v ) -> u = v ) )
Theorem	recsfval 6414*	Lemma for transfinite recursion. The definition recs is the union of all acceptable functions. (Contributed by Mario Carneiro, 9-May-2015.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   =>    |- recs ( F ) = U. A
Theorem	tfrlem6 6415*	Lemma for transfinite recursion. The union of all acceptable functions is a relation. (Contributed by NM, 8-Aug-1994.) (Revised by Mario Carneiro, 9-May-2015.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   =>    |- Rel recs ( F )
Theorem	tfrlem7 6416*	Lemma for transfinite recursion. The union of all acceptable functions is a function. (Contributed by NM, 9-Aug-1994.) (Revised by Mario Carneiro, 24-May-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   =>    |- Fun recs ( F )
Theorem	tfrlem8 6417*	Lemma for transfinite recursion. The domain of recs is ordinal. (Contributed by NM, 14-Aug-1994.) (Proof shortened by Alan Sare, 11-Mar-2008.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   =>    |- Ord dom recs ( F )
Theorem	tfrlem9 6418*	Lemma for transfinite recursion. Here we compute the value of recs (the union of all acceptable functions). (Contributed by NM, 17-Aug-1994.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   =>    |- ( B e. dom recs ( F ) -> (recs ( F ) ` B ) = ( F ` (recs ( F ) |` B ) ) )
Theorem	tfrfun 6419	Transfinite recursion produces a function. (Contributed by Jim Kingdon, 20-Aug-2021.)
|- Fun recs ( F )
Theorem	tfr2a 6420	A weak version of transfinite recursion. (Contributed by Mario Carneiro, 24-Jun-2015.)
|- F = recs ( G )   =>    |- ( A e. dom F -> ( F ` A ) = ( G ` ( F |` A ) ) )
Theorem	tfr0dm 6421	Transfinite recursion is defined at the empty set. (Contributed by Jim Kingdon, 8-Mar-2022.)
|- F = recs ( G )   =>    |- ( ( G ` (/) ) e. V -> (/) e. dom F )
Theorem	tfr0 6422	Transfinite recursion at the empty set. (Contributed by Jim Kingdon, 8-May-2020.)
|- F = recs ( G )   =>    |- ( ( G ` (/) ) e. V -> ( F ` (/) ) = ( G ` (/) ) )
Theorem	tfrlemisucfn 6423*	We can extend an acceptable function by one element to produce a function. Lemma for tfrlemi1 6431. (Contributed by Jim Kingdon, 2-Jul-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   &    |- ( ph -> A. x ( Fun F /\ ( F ` x ) e. _V ) )   &    |- ( ph -> z e. On )   &    |- ( ph -> g Fn z )   &    |- ( ph -> g e. A )   =>    |- ( ph -> ( g u. { <. z , ( F ` g ) >. } ) Fn suc z )
Theorem	tfrlemisucaccv 6424*	We can extend an acceptable function by one element to produce an acceptable function. Lemma for tfrlemi1 6431. (Contributed by Jim Kingdon, 4-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   &    |- ( ph -> A. x ( Fun F /\ ( F ` x ) e. _V ) )   &    |- ( ph -> z e. On )   &    |- ( ph -> g Fn z )   &    |- ( ph -> g e. A )   =>    |- ( ph -> ( g u. { <. z , ( F ` g ) >. } ) e. A )
Theorem	tfrlemibacc 6425*	Each element of B is an acceptable function. Lemma for tfrlemi1 6431. (Contributed by Jim Kingdon, 14-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   &    |- ( ph -> A. x ( Fun F /\ ( F ` x ) e. _V ) )   &    |- B = { h | E. z e. x E. g ( g Fn z /\ g e. A /\ h = ( g u. { <. z , ( F ` g ) >. } ) ) }   &    |- ( ph -> x e. On )   &    |- ( ph -> A. z e. x E. g ( g Fn z /\ A. w e. z ( g ` w ) = ( F ` ( g |` w ) ) ) )   =>    |- ( ph -> B C_ A )
Theorem	tfrlemibxssdm 6426*	The union of B is defined on all ordinals. Lemma for tfrlemi1 6431. (Contributed by Jim Kingdon, 18-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   &    |- ( ph -> A. x ( Fun F /\ ( F ` x ) e. _V ) )   &    |- B = { h | E. z e. x E. g ( g Fn z /\ g e. A /\ h = ( g u. { <. z , ( F ` g ) >. } ) ) }   &    |- ( ph -> x e. On )   &    |- ( ph -> A. z e. x E. g ( g Fn z /\ A. w e. z ( g ` w ) = ( F ` ( g |` w ) ) ) )   =>    |- ( ph -> x C_ dom U. B )
Theorem	tfrlemibfn 6427*	The union of B is a function defined on x. Lemma for tfrlemi1 6431. (Contributed by Jim Kingdon, 18-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   &    |- ( ph -> A. x ( Fun F /\ ( F ` x ) e. _V ) )   &    |- B = { h | E. z e. x E. g ( g Fn z /\ g e. A /\ h = ( g u. { <. z , ( F ` g ) >. } ) ) }   &    |- ( ph -> x e. On )   &    |- ( ph -> A. z e. x E. g ( g Fn z /\ A. w e. z ( g ` w ) = ( F ` ( g |` w ) ) ) )   =>    |- ( ph -> U. B Fn x )
Theorem	tfrlemibex 6428*	The set B exists. Lemma for tfrlemi1 6431. (Contributed by Jim Kingdon, 17-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   &    |- ( ph -> A. x ( Fun F /\ ( F ` x ) e. _V ) )   &    |- B = { h | E. z e. x E. g ( g Fn z /\ g e. A /\ h = ( g u. { <. z , ( F ` g ) >. } ) ) }   &    |- ( ph -> x e. On )   &    |- ( ph -> A. z e. x E. g ( g Fn z /\ A. w e. z ( g ` w ) = ( F ` ( g |` w ) ) ) )   =>    |- ( ph -> B e. _V )
Theorem	tfrlemiubacc 6429*	The union of B satisfies the recursion rule (lemma for tfrlemi1 6431). (Contributed by Jim Kingdon, 22-Apr-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   &    |- ( ph -> A. x ( Fun F /\ ( F ` x ) e. _V ) )   &    |- B = { h | E. z e. x E. g ( g Fn z /\ g e. A /\ h = ( g u. { <. z , ( F ` g ) >. } ) ) }   &    |- ( ph -> x e. On )   &    |- ( ph -> A. z e. x E. g ( g Fn z /\ A. w e. z ( g ` w ) = ( F ` ( g |` w ) ) ) )   =>    |- ( ph -> A. u e. x ( U. B ` u ) = ( F ` ( U. B |` u ) ) )
Theorem	tfrlemiex 6430*	Lemma for tfrlemi1 6431. (Contributed by Jim Kingdon, 18-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   &    |- ( ph -> A. x ( Fun F /\ ( F ` x ) e. _V ) )   &    |- B = { h | E. z e. x E. g ( g Fn z /\ g e. A /\ h = ( g u. { <. z , ( F ` g ) >. } ) ) }   &    |- ( ph -> x e. On )   &    |- ( ph -> A. z e. x E. g ( g Fn z /\ A. w e. z ( g ` w ) = ( F ` ( g |` w ) ) ) )   =>    |- ( ph -> E. f ( f Fn x /\ A. u e. x ( f ` u ) = ( F ` ( f |` u ) ) ) )
Theorem	tfrlemi1 6431*	We can define an acceptable function on any ordinal. As with many of the transfinite recursion theorems, we have a hypothesis that states that F is a function and that it is defined for all ordinals. (Contributed by Jim Kingdon, 4-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   &    |- ( ph -> A. x ( Fun F /\ ( F ` x ) e. _V ) )   =>    |- ( ( ph /\ C e. On ) -> E. g ( g Fn C /\ A. u e. C ( g ` u ) = ( F ` ( g |` u ) ) ) )
Theorem	tfrlemi14d 6432*	The domain of recs is all ordinals (lemma for transfinite recursion). (Contributed by Jim Kingdon, 9-Jul-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   &    |- ( ph -> A. x ( Fun F /\ ( F ` x ) e. _V ) )   =>    |- ( ph -> dom recs ( F ) = On )
Theorem	tfrexlem 6433*	The transfinite recursion function is set-like if the input is. (Contributed by Mario Carneiro, 3-Jul-2019.)
|- A = { f | E. x e. On ( f Fn x /\ A. y e. x ( f ` y ) = ( F ` ( f |` y ) ) ) }   &    |- ( ph -> A. x ( Fun F /\ ( F ` x ) e. _V ) )   =>    |- ( ( ph /\ C e. V ) -> (recs ( F ) ` C ) e. _V )
Theorem	tfri1d 6434*	Principle of Transfinite Recursion, part 1 of 3. Theorem 7.41(1) of [TakeutiZaring] p. 47, with an additional condition. The condition is that G is defined "everywhere", which is stated here as ( G ` x ) e. _V. Alternately, A. x e. On A. f ( f Fn x -> f e. dom G ) would suffice. Given a function G satisfying that condition, we define a class A of all "acceptable" functions. The final function we're interested in is the union F = recs ( G ) of them. F is then said to be defined by transfinite recursion. The purpose of the 3 parts of this theorem is to demonstrate properties of F. In this first part we show that F is a function whose domain is all ordinal numbers. (Contributed by Jim Kingdon, 4-May-2019.) (Revised by Mario Carneiro, 24-May-2019.)
|- F = recs ( G )   &    |- ( ph -> A. x ( Fun G /\ ( G ` x ) e. _V ) )   =>    |- ( ph -> F Fn On )
Theorem	tfri2d 6435*	Principle of Transfinite Recursion, part 2 of 3. Theorem 7.41(2) of [TakeutiZaring] p. 47, with an additional condition on the recursion rule G ( as described at tfri1 6464). Here we show that the function F has the property that for any function G satisfying that condition, the "next" value of F is G recursively applied to all "previous" values of F. (Contributed by Jim Kingdon, 4-May-2019.)
|- F = recs ( G )   &    |- ( ph -> A. x ( Fun G /\ ( G ` x ) e. _V ) )   =>    |- ( ( ph /\ A e. On ) -> ( F ` A ) = ( G ` ( F |` A ) ) )
Theorem	tfr1onlem3ag 6436*	Lemma for transfinite recursion. This lemma changes some bound variables in A (version of tfrlem3ag 6408 but for tfr1on 6449 related lemmas). (Contributed by Jim Kingdon, 13-Mar-2022.)
|- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   =>    |- ( H e. V -> ( H e. A <-> E. z e. X ( H Fn z /\ A. w e. z ( H ` w ) = ( G ` ( H |` w ) ) ) ) )
Theorem	tfr1onlem3 6437*	Lemma for transfinite recursion. This lemma changes some bound variables in A (version of tfrlem3 6410 but for tfr1on 6449 related lemmas). (Contributed by Jim Kingdon, 14-Mar-2022.)
|- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   =>    |- A = { g | E. z e. X ( g Fn z /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) }
Theorem	tfr1onlemssrecs 6438*	Lemma for tfr1on 6449. The union of functions acceptable for tfr1on 6449 is a subset of recs. (Contributed by Jim Kingdon, 15-Mar-2022.)
|- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- ( ph -> Ord X )   =>    |- ( ph -> U. A C_ recs ( G ) )
Theorem	tfr1onlemsucfn 6439*	We can extend an acceptable function by one element to produce a function. Lemma for tfr1on 6449. (Contributed by Jim Kingdon, 12-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )   &    |- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- ( ph -> z e. X )   &    |- ( ph -> g Fn z )   &    |- ( ph -> g e. A )   =>    |- ( ph -> ( g u. { <. z , ( G ` g ) >. } ) Fn suc z )
Theorem	tfr1onlemsucaccv 6440*	Lemma for tfr1on 6449. We can extend an acceptable function by one element to produce an acceptable function. (Contributed by Jim Kingdon, 12-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )   &    |- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- ( ph -> Y e. X )   &    |- ( ph -> z e. Y )   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> g Fn z )   &    |- ( ph -> g e. A )   =>    |- ( ph -> ( g u. { <. z , ( G ` g ) >. } ) e. A )
Theorem	tfr1onlembacc 6441*	Lemma for tfr1on 6449. Each element of B is an acceptable function. (Contributed by Jim Kingdon, 14-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )   &    |- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- B = { h | E. z e. D E. g ( g Fn z /\ g e. A /\ h = ( g u. { <. z , ( G ` g ) >. } ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> D e. X )   &    |- ( ph -> A. z e. D E. g ( g Fn z /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) )   =>    |- ( ph -> B C_ A )
Theorem	tfr1onlembxssdm 6442*	Lemma for tfr1on 6449. The union of B is defined on all elements of X. (Contributed by Jim Kingdon, 14-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )   &    |- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- B = { h | E. z e. D E. g ( g Fn z /\ g e. A /\ h = ( g u. { <. z , ( G ` g ) >. } ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> D e. X )   &    |- ( ph -> A. z e. D E. g ( g Fn z /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) )   =>    |- ( ph -> D C_ dom U. B )
Theorem	tfr1onlembfn 6443*	Lemma for tfr1on 6449. The union of B is a function defined on x. (Contributed by Jim Kingdon, 15-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )   &    |- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- B = { h | E. z e. D E. g ( g Fn z /\ g e. A /\ h = ( g u. { <. z , ( G ` g ) >. } ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> D e. X )   &    |- ( ph -> A. z e. D E. g ( g Fn z /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) )   =>    |- ( ph -> U. B Fn D )
Theorem	tfr1onlembex 6444*	Lemma for tfr1on 6449. The set B exists. (Contributed by Jim Kingdon, 14-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )   &    |- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- B = { h | E. z e. D E. g ( g Fn z /\ g e. A /\ h = ( g u. { <. z , ( G ` g ) >. } ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> D e. X )   &    |- ( ph -> A. z e. D E. g ( g Fn z /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) )   =>    |- ( ph -> B e. _V )
Theorem	tfr1onlemubacc 6445*	Lemma for tfr1on 6449. The union of B satisfies the recursion rule. (Contributed by Jim Kingdon, 15-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )   &    |- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- B = { h | E. z e. D E. g ( g Fn z /\ g e. A /\ h = ( g u. { <. z , ( G ` g ) >. } ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> D e. X )   &    |- ( ph -> A. z e. D E. g ( g Fn z /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) )   =>    |- ( ph -> A. u e. D ( U. B ` u ) = ( G ` ( U. B |` u ) ) )
Theorem	tfr1onlemex 6446*	Lemma for tfr1on 6449. (Contributed by Jim Kingdon, 16-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )   &    |- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- B = { h | E. z e. D E. g ( g Fn z /\ g e. A /\ h = ( g u. { <. z , ( G ` g ) >. } ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> D e. X )   &    |- ( ph -> A. z e. D E. g ( g Fn z /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) )   =>    |- ( ph -> E. f ( f Fn D /\ A. u e. D ( f ` u ) = ( G ` ( f |` u ) ) ) )
Theorem	tfr1onlemaccex 6447*	We can define an acceptable function on any element of X. As with many of the transfinite recursion theorems, we have hypotheses that state that F is a function and that it is defined up to X. (Contributed by Jim Kingdon, 16-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )   &    |- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   =>    |- ( ( ph /\ C e. X ) -> E. g ( g Fn C /\ A. u e. C ( g ` u ) = ( G ` ( g |` u ) ) ) )
Theorem	tfr1onlemres 6448*	Lemma for tfr1on 6449. Recursion is defined on an ordinal if the characteristic function is defined up to a suitable point. (Contributed by Jim Kingdon, 18-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )   &    |- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> Y e. X )   =>    |- ( ph -> Y C_ dom F )
Theorem	tfr1on 6449*	Recursion is defined on an ordinal if the characteristic function is defined up to a suitable point. (Contributed by Jim Kingdon, 12-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> Y e. X )   =>    |- ( ph -> Y C_ dom F )
Theorem	tfri1dALT 6450*	Alternate proof of tfri1d 6434 in terms of tfr1on 6449. Although this does show that the tfr1on 6449 proof is general enough to also prove tfri1d 6434, the tfri1d 6434 proof is simpler in places because it does not need to deal with X being any ordinal. For that reason, we have both proofs. (Proof modification is discouraged.) (New usage is discouraged.) (Contributed by Jim Kingdon, 20-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> A. x ( Fun G /\ ( G ` x ) e. _V ) )   =>    |- ( ph -> F Fn On )
Theorem	tfrcllemssrecs 6451*	Lemma for tfrcl 6463. The union of functions acceptable for tfrcl 6463 is a subset of recs. (Contributed by Jim Kingdon, 25-Mar-2022.)
|- A = { f | E. x e. X ( f : x --> S /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- ( ph -> Ord X )   =>    |- ( ph -> U. A C_ recs ( G ) )
Theorem	tfrcllemsucfn 6452*	We can extend an acceptable function by one element to produce a function. Lemma for tfrcl 6463. (Contributed by Jim Kingdon, 24-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f : x --> S ) -> ( G ` f ) e. S )   &    |- A = { f | E. x e. X ( f : x --> S /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- ( ph -> z e. X )   &    |- ( ph -> g : z --> S )   &    |- ( ph -> g e. A )   =>    |- ( ph -> ( g u. { <. z , ( G ` g ) >. } ) : suc z --> S )
Theorem	tfrcllemsucaccv 6453*	Lemma for tfrcl 6463. We can extend an acceptable function by one element to produce an acceptable function. (Contributed by Jim Kingdon, 24-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f : x --> S ) -> ( G ` f ) e. S )   &    |- A = { f | E. x e. X ( f : x --> S /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- ( ph -> Y e. X )   &    |- ( ph -> z e. Y )   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> g : z --> S )   &    |- ( ph -> g e. A )   =>    |- ( ph -> ( g u. { <. z , ( G ` g ) >. } ) e. A )
Theorem	tfrcllembacc 6454*	Lemma for tfrcl 6463. Each element of B is an acceptable function. (Contributed by Jim Kingdon, 25-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f : x --> S ) -> ( G ` f ) e. S )   &    |- A = { f | E. x e. X ( f : x --> S /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- B = { h | E. z e. D E. g ( g : z --> S /\ g e. A /\ h = ( g u. { <. z , ( G ` g ) >. } ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> D e. X )   &    |- ( ph -> A. z e. D E. g ( g : z --> S /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) )   =>    |- ( ph -> B C_ A )
Theorem	tfrcllembxssdm 6455*	Lemma for tfrcl 6463. The union of B is defined on all elements of X. (Contributed by Jim Kingdon, 25-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f : x --> S ) -> ( G ` f ) e. S )   &    |- A = { f | E. x e. X ( f : x --> S /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- B = { h | E. z e. D E. g ( g : z --> S /\ g e. A /\ h = ( g u. { <. z , ( G ` g ) >. } ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> D e. X )   &    |- ( ph -> A. z e. D E. g ( g : z --> S /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) )   =>    |- ( ph -> D C_ dom U. B )
Theorem	tfrcllembfn 6456*	Lemma for tfrcl 6463. The union of B is a function defined on x. (Contributed by Jim Kingdon, 25-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f : x --> S ) -> ( G ` f ) e. S )   &    |- A = { f | E. x e. X ( f : x --> S /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- B = { h | E. z e. D E. g ( g : z --> S /\ g e. A /\ h = ( g u. { <. z , ( G ` g ) >. } ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> D e. X )   &    |- ( ph -> A. z e. D E. g ( g : z --> S /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) )   =>    |- ( ph -> U. B : D --> S )
Theorem	tfrcllembex 6457*	Lemma for tfrcl 6463. The set B exists. (Contributed by Jim Kingdon, 25-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f : x --> S ) -> ( G ` f ) e. S )   &    |- A = { f | E. x e. X ( f : x --> S /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- B = { h | E. z e. D E. g ( g : z --> S /\ g e. A /\ h = ( g u. { <. z , ( G ` g ) >. } ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> D e. X )   &    |- ( ph -> A. z e. D E. g ( g : z --> S /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) )   =>    |- ( ph -> B e. _V )
Theorem	tfrcllemubacc 6458*	Lemma for tfrcl 6463. The union of B satisfies the recursion rule. (Contributed by Jim Kingdon, 25-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f : x --> S ) -> ( G ` f ) e. S )   &    |- A = { f | E. x e. X ( f : x --> S /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- B = { h | E. z e. D E. g ( g : z --> S /\ g e. A /\ h = ( g u. { <. z , ( G ` g ) >. } ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> D e. X )   &    |- ( ph -> A. z e. D E. g ( g : z --> S /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) )   =>    |- ( ph -> A. u e. D ( U. B ` u ) = ( G ` ( U. B |` u ) ) )
Theorem	tfrcllemex 6459*	Lemma for tfrcl 6463. (Contributed by Jim Kingdon, 26-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f : x --> S ) -> ( G ` f ) e. S )   &    |- A = { f | E. x e. X ( f : x --> S /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- B = { h | E. z e. D E. g ( g : z --> S /\ g e. A /\ h = ( g u. { <. z , ( G ` g ) >. } ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> D e. X )   &    |- ( ph -> A. z e. D E. g ( g : z --> S /\ A. w e. z ( g ` w ) = ( G ` ( g |` w ) ) ) )   =>    |- ( ph -> E. f ( f : D --> S /\ A. u e. D ( f ` u ) = ( G ` ( f |` u ) ) ) )
Theorem	tfrcllemaccex 6460*	We can define an acceptable function on any element of X. As with many of the transfinite recursion theorems, we have hypotheses that state that F is a function and that it is defined up to X. (Contributed by Jim Kingdon, 26-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f : x --> S ) -> ( G ` f ) e. S )   &    |- A = { f | E. x e. X ( f : x --> S /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   =>    |- ( ( ph /\ C e. X ) -> E. g ( g : C --> S /\ A. u e. C ( g ` u ) = ( G ` ( g |` u ) ) ) )
Theorem	tfrcllemres 6461*	Lemma for tfr1on 6449. Recursion is defined on an ordinal if the characteristic function is defined up to a suitable point. (Contributed by Jim Kingdon, 18-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f : x --> S ) -> ( G ` f ) e. S )   &    |- A = { f | E. x e. X ( f : x --> S /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> Y e. X )   =>    |- ( ph -> Y C_ dom F )
Theorem	tfrcldm 6462*	Recursion is defined on an ordinal if the characteristic function satisfies a closure hypothesis up to a suitable point. (Contributed by Jim Kingdon, 26-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f : x --> S ) -> ( G ` f ) e. S )   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> Y e. U. X )   =>    |- ( ph -> Y e. dom F )
Theorem	tfrcl 6463*	Closure for transfinite recursion. As with tfr1on 6449, the characteristic function must be defined up to a suitable point, not necessarily on all ordinals. (Contributed by Jim Kingdon, 25-Mar-2022.)
|- F = recs ( G )   &    |- ( ph -> Fun G )   &    |- ( ph -> Ord X )   &    |- ( ( ph /\ x e. X /\ f : x --> S ) -> ( G ` f ) e. S )   &    |- ( ( ph /\ x e. U. X ) -> suc x e. X )   &    |- ( ph -> Y e. U. X )   =>    |- ( ph -> ( F ` Y ) e. S )
Theorem	tfri1 6464*	Principle of Transfinite Recursion, part 1 of 3. Theorem 7.41(1) of [TakeutiZaring] p. 47, with an additional condition. The condition is that G is defined "everywhere", which is stated here as ( G ` x ) e. _V. Alternately, A. x e. On A. f ( f Fn x -> f e. dom G ) would suffice. Given a function G satisfying that condition, we define a class A of all "acceptable" functions. The final function we're interested in is the union F = recs ( G ) of them. F is then said to be defined by transfinite recursion. The purpose of the 3 parts of this theorem is to demonstrate properties of F. In this first part we show that F is a function whose domain is all ordinal numbers. (Contributed by Jim Kingdon, 4-May-2019.) (Revised by Mario Carneiro, 24-May-2019.)
|- F = recs ( G )   &    |- ( Fun G /\ ( G ` x ) e. _V )   =>    |- F Fn On
Theorem	tfri2 6465*	Principle of Transfinite Recursion, part 2 of 3. Theorem 7.41(2) of [TakeutiZaring] p. 47, with an additional condition on the recursion rule G ( as described at tfri1 6464). Here we show that the function F has the property that for any function G satisfying that condition, the "next" value of F is G recursively applied to all "previous" values of F. (Contributed by Jim Kingdon, 4-May-2019.)
|- F = recs ( G )   &    |- ( Fun G /\ ( G ` x ) e. _V )   =>    |- ( A e. On -> ( F ` A ) = ( G ` ( F |` A ) ) )
Theorem	tfri3 6466*	Principle of Transfinite Recursion, part 3 of 3. Theorem 7.41(3) of [TakeutiZaring] p. 47, with an additional condition on the recursion rule G ( as described at tfri1 6464). Finally, we show that F is unique. We do this by showing that any class B with the same properties of F that we showed in parts 1 and 2 is identical to F. (Contributed by Jim Kingdon, 4-May-2019.)
|- F = recs ( G )   &    |- ( Fun G /\ ( G ` x ) e. _V )   =>    |- ( ( B Fn On /\ A. x e. On ( B ` x ) = ( G ` ( B |` x ) ) ) -> B = F )
Theorem	tfrex 6467*	The transfinite recursion function is set-like if the input is. (Contributed by Mario Carneiro, 3-Jul-2019.)
|- F = recs ( G )   &    |- ( ph -> A. x ( Fun G /\ ( G ` x ) e. _V ) )   =>    |- ( ( ph /\ A e. V ) -> ( F ` A ) e. _V )
2.6.21  Recursive definition generator
Syntax	crdg 6468	Extend class notation with the recursive definition generator, with characteristic function F and initial value I.
class rec ( F , I )
Definition	df-irdg 6469*	Define a recursive definition generator on On (the class of ordinal numbers) with characteristic function F and initial value I. This rather amazing operation allows us to define, with compact direct definitions, functions that are usually defined in textbooks only with indirect self-referencing recursive definitions. A recursive definition requires advanced metalogic to justify - in particular, eliminating a recursive definition is very difficult and often not even shown in textbooks. On the other hand, the elimination of a direct definition is a matter of simple mechanical substitution. The price paid is the daunting complexity of our rec operation (especially when df-recs 6404 that it is built on is also eliminated). But once we get past this hurdle, definitions that would otherwise be recursive become relatively simple. In classical logic it would be easier to divide this definition into cases based on whether the domain of g is zero, a successor, or a limit ordinal. Cases do not (in general) work that way in intuitionistic logic, so instead we choose a definition which takes the union of all the results of the characteristic function for ordinals in the domain of g. This means that this definition has the expected properties for increasing and continuous ordinal functions, which include ordinal addition and multiplication. For finite recursion we also define df-frec 6490 and for suitable characteristic functions df-frec 6490 yields the same result as rec restricted to om, as seen at frecrdg 6507. Note: We introduce rec with the philosophical goal of being able to eliminate all definitions with direct mechanical substitution and to verify easily the soundness of definitions. Metamath itself has no built-in technical limitation that prevents multiple-part recursive definitions in the traditional textbook style. (Contributed by Jim Kingdon, 19-May-2019.)
|- rec ( F , I ) = recs ( ( g e. _V |-> ( I u. U_ x e. dom g ( F ` ( g ` x ) ) ) ) )
Theorem	rdgeq1 6470	Equality theorem for the recursive definition generator. (Contributed by NM, 9-Apr-1995.) (Revised by Mario Carneiro, 9-May-2015.)
|- ( F = G -> rec ( F , A ) = rec ( G , A ) )
Theorem	rdgeq2 6471	Equality theorem for the recursive definition generator. (Contributed by NM, 9-Apr-1995.) (Revised by Mario Carneiro, 9-May-2015.)
|- ( A = B -> rec ( F , A ) = rec ( F , B ) )
Theorem	rdgfun 6472	The recursive definition generator is a function. (Contributed by Mario Carneiro, 16-Nov-2014.)
|- Fun rec ( F , A )
Theorem	rdgtfr 6473*	The recursion rule for the recursive definition generator is defined everywhere. (Contributed by Jim Kingdon, 14-May-2020.)
|- ( ( A. z ( F ` z ) e. _V /\ A e. V ) -> ( Fun ( g e. _V |-> ( A u. U_ x e. dom g ( F ` ( g ` x ) ) ) ) /\ ( ( g e. _V |-> ( A u. U_ x e. dom g ( F ` ( g ` x ) ) ) ) ` f ) e. _V ) )
Theorem	rdgruledefgg 6474*	The recursion rule for the recursive definition generator is defined everywhere. (Contributed by Jim Kingdon, 4-Jul-2019.)
|- ( ( F Fn _V /\ A e. V ) -> ( Fun ( g e. _V |-> ( A u. U_ x e. dom g ( F ` ( g ` x ) ) ) ) /\ ( ( g e. _V |-> ( A u. U_ x e. dom g ( F ` ( g ` x ) ) ) ) ` f ) e. _V ) )
Theorem	rdgruledefg 6475*	The recursion rule for the recursive definition generator is defined everywhere. (Contributed by Jim Kingdon, 4-Jul-2019.)
|- F Fn _V   =>    |- ( A e. V -> ( Fun ( g e. _V |-> ( A u. U_ x e. dom g ( F ` ( g ` x ) ) ) ) /\ ( ( g e. _V |-> ( A u. U_ x e. dom g ( F ` ( g ` x ) ) ) ) ` f ) e. _V ) )
Theorem	rdgexggg 6476	The recursive definition generator produces a set on a set input. (Contributed by Jim Kingdon, 4-Jul-2019.)
|- ( ( F Fn _V /\ A e. V /\ B e. W ) -> ( rec ( F , A ) ` B ) e. _V )
Theorem	rdgexgg 6477	The recursive definition generator produces a set on a set input. (Contributed by Jim Kingdon, 4-Jul-2019.)
|- F Fn _V   =>    |- ( ( A e. V /\ B e. W ) -> ( rec ( F , A ) ` B ) e. _V )
Theorem	rdgifnon 6478	The recursive definition generator is a function on ordinal numbers. The F Fn _V condition states that the characteristic function is defined for all sets (being defined for all ordinals might be enough if being used in a manner similar to rdgon 6485; in cases like df-oadd 6519 either presumably could work). (Contributed by Jim Kingdon, 13-Jul-2019.)
|- ( ( F Fn _V /\ A e. V ) -> rec ( F , A ) Fn On )
Theorem	rdgifnon2 6479*	The recursive definition generator is a function on ordinal numbers. (Contributed by Jim Kingdon, 14-May-2020.)
|- ( ( A. z ( F ` z ) e. _V /\ A e. V ) -> rec ( F , A ) Fn On )
Theorem	rdgivallem 6480*	Value of the recursive definition generator. Lemma for rdgival 6481 which simplifies the value further. (Contributed by Jim Kingdon, 13-Jul-2019.) (New usage is discouraged.)
|- ( ( F Fn _V /\ A e. V /\ B e. On ) -> ( rec ( F , A ) ` B ) = ( A u. U_ x e. B ( F ` ( ( rec ( F , A ) |` B ) ` x ) ) ) )
Theorem	rdgival 6481*	Value of the recursive definition generator. (Contributed by Jim Kingdon, 26-Jul-2019.)
|- ( ( F Fn _V /\ A e. V /\ B e. On ) -> ( rec ( F , A ) ` B ) = ( A u. U_ x e. B ( F ` ( rec ( F , A ) ` x ) ) ) )
Theorem	rdgss 6482	Subset and recursive definition generator. (Contributed by Jim Kingdon, 15-Jul-2019.)
|- ( ph -> F Fn _V )   &    |- ( ph -> I e. V )   &    |- ( ph -> A e. On )   &    |- ( ph -> B e. On )   &    |- ( ph -> A C_ B )   =>    |- ( ph -> ( rec ( F , I ) ` A ) C_ ( rec ( F , I ) ` B ) )
Theorem	rdgisuc1 6483*	One way of describing the value of the recursive definition generator at a successor. There is no condition on the characteristic function F other than F Fn _V. Given that, the resulting expression encompasses both the expected successor term ( F ` ( rec ( F , A ) ` B ) ) but also terms that correspond to the initial value A and to limit ordinals U_ x e. B ( F ` ( rec ( F , A ) ` x ) ). If we add conditions on the characteristic function, we can show tighter results such as rdgisucinc 6484. (Contributed by Jim Kingdon, 9-Jun-2019.)
|- ( ph -> F Fn _V )   &    |- ( ph -> A e. V )   &    |- ( ph -> B e. On )   =>    |- ( ph -> ( rec ( F , A ) ` suc B ) = ( A u. ( U_ x e. B ( F ` ( rec ( F , A ) ` x ) ) u. ( F ` ( rec ( F , A ) ` B ) ) ) ) )
Theorem	rdgisucinc 6484*	Value of the recursive definition generator at a successor. This can be thought of as a generalization of oasuc 6563 and omsuc 6571. (Contributed by Jim Kingdon, 29-Aug-2019.)
|- ( ph -> F Fn _V )   &    |- ( ph -> A e. V )   &    |- ( ph -> B e. On )   &    |- ( ph -> A. x x C_ ( F ` x ) )   =>    |- ( ph -> ( rec ( F , A ) ` suc B ) = ( F ` ( rec ( F , A ) ` B ) ) )
Theorem	rdgon 6485*	Evaluating the recursive definition generator produces an ordinal. There is a hypothesis that the characteristic function produces ordinals on ordinal arguments. (Contributed by Jim Kingdon, 26-Jul-2019.) (Revised by Jim Kingdon, 13-Apr-2022.)
|- ( ph -> A e. On )   &    |- ( ph -> A. x e. On ( F ` x ) e. On )   =>    |- ( ( ph /\ B e. On ) -> ( rec ( F , A ) ` B ) e. On )
Theorem	rdg0 6486	The initial value of the recursive definition generator. (Contributed by NM, 23-Apr-1995.) (Revised by Mario Carneiro, 14-Nov-2014.)
|- A e. _V   =>    |- ( rec ( F , A ) ` (/) ) = A
Theorem	rdg0g 6487	The initial value of the recursive definition generator. (Contributed by NM, 25-Apr-1995.)
|- ( A e. C -> ( rec ( F , A ) ` (/) ) = A )
Theorem	rdgexg 6488	The recursive definition generator produces a set on a set input. (Contributed by Mario Carneiro, 3-Jul-2019.)
|- A e. _V   &    |- F Fn _V   =>    |- ( B e. V -> ( rec ( F , A ) ` B ) e. _V )
2.6.22  Finite recursion
Syntax	cfrec 6489	Extend class notation with the finite recursive definition generator, with characteristic function F and initial value I.
class frec ( F , I )
Definition	df-frec 6490*	Define a recursive definition generator on om (the class of finite ordinals) with characteristic function F and initial value I. This rather amazing operation allows us to define, with compact direct definitions, functions that are usually defined in textbooks only with indirect self-referencing recursive definitions. A recursive definition requires advanced metalogic to justify - in particular, eliminating a recursive definition is very difficult and often not even shown in textbooks. On the other hand, the elimination of a direct definition is a matter of simple mechanical substitution. The price paid is the daunting complexity of our frec operation (especially when df-recs 6404 that it is built on is also eliminated). But once we get past this hurdle, definitions that would otherwise be recursive become relatively simple; see frec0g 6496 and frecsuc 6506. Unlike with transfinite recursion, finite recurson can readily divide definitions and proofs into zero and successor cases, because even without excluded middle we have theorems such as nn0suc 4660. The analogous situation with transfinite recursion - being able to say that an ordinal is zero, successor, or limit - is enabled by excluded middle and thus is not available to us. For the characteristic functions which satisfy the conditions given at frecrdg 6507, this definition and df-irdg 6469 restricted to om produce the same result. Note: We introduce frec with the philosophical goal of being able to eliminate all definitions with direct mechanical substitution and to verify easily the soundness of definitions. Metamath itself has no built-in technical limitation that prevents multiple-part recursive definitions in the traditional textbook style. (Contributed by Mario Carneiro and Jim Kingdon, 10-Aug-2019.)
|- frec ( F , I ) = (recs ( ( g e. _V |-> { x | ( E. m e. om ( dom g = suc m /\ x e. ( F ` ( g ` m ) ) ) \/ ( dom g = (/) /\ x e. I ) ) } ) ) |` om )
Theorem	freceq1 6491	Equality theorem for the finite recursive definition generator. (Contributed by Jim Kingdon, 30-May-2020.)
|- ( F = G -> frec ( F , A ) = frec ( G , A ) )
Theorem	freceq2 6492	Equality theorem for the finite recursive definition generator. (Contributed by Jim Kingdon, 30-May-2020.)
|- ( A = B -> frec ( F , A ) = frec ( F , B ) )
Theorem	frecex 6493	Finite recursion produces a set. (Contributed by Jim Kingdon, 20-Aug-2021.)
|- frec ( F , A ) e. _V
Theorem	frecfun 6494	Finite recursion produces a function. See also frecfnom 6500 which also states that the domain of that function is om but which puts conditions on A and F. (Contributed by Jim Kingdon, 13-Feb-2022.)
|- Fun frec ( F , A )
Theorem	nffrec 6495	Bound-variable hypothesis builder for the finite recursive definition generator. (Contributed by Jim Kingdon, 30-May-2020.)
|- F/_ x F   &    |- F/_ x A   =>    |- F/_ xfrec ( F , A )
Theorem	frec0g 6496	The initial value resulting from finite recursive definition generation. (Contributed by Jim Kingdon, 7-May-2020.)
|- ( A e. V -> (frec ( F , A ) ` (/) ) = A )
Theorem	frecabex 6497*	The class abstraction from df-frec 6490 exists. This is a lemma for other finite recursion proofs. (Contributed by Jim Kingdon, 13-May-2020.)
|- ( ph -> S e. V )   &    |- ( ph -> A. y ( F ` y ) e. _V )   &    |- ( ph -> A e. W )   =>    |- ( ph -> { x | ( E. m e. om ( dom S = suc m /\ x e. ( F ` ( S ` m ) ) ) \/ ( dom S = (/) /\ x e. A ) ) } e. _V )
Theorem	frecabcl 6498*	The class abstraction from df-frec 6490 exists. Unlike frecabex 6497 the function F only needs to be defined on S, not all sets. This is a lemma for other finite recursion proofs. (Contributed by Jim Kingdon, 21-Mar-2022.)
|- ( ph -> N e. om )   &    |- ( ph -> G : N --> S )   &    |- ( ph -> A. y e. S ( F ` y ) e. S )   &    |- ( ph -> A e. S )   =>    |- ( ph -> { x | ( E. m e. om ( dom G = suc m /\ x e. ( F ` ( G ` m ) ) ) \/ ( dom G = (/) /\ x e. A ) ) } e. S )
Theorem	frectfr 6499*	Lemma to connect transfinite recursion theorems with finite recursion. That is, given the conditions F Fn _V and A e. V on frec ( F , A ), we want to be able to apply tfri1d 6434 or tfri2d 6435, and this lemma lets us satisfy hypotheses of those theorems. (Contributed by Jim Kingdon, 15-Aug-2019.)
|- G = ( g e. _V |-> { x | ( E. m e. om ( dom g = suc m /\ x e. ( F ` ( g ` m ) ) ) \/ ( dom g = (/) /\ x e. A ) ) } )   =>    |- ( ( A. z ( F ` z ) e. _V /\ A e. V ) -> A. y ( Fun G /\ ( G ` y ) e. _V ) )
Theorem	frecfnom 6500*	The function generated by finite recursive definition generation is a function on omega. (Contributed by Jim Kingdon, 13-May-2020.)
|- ( ( A. z ( F ` z ) e. _V /\ A e. V ) -> frec ( F , A ) Fn om )