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Theorem List for Intuitionistic Logic Explorer - 6401-6500   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremtfrlemisucaccv 6401* We can extend an acceptable function by one element to produce an acceptable function. Lemma for tfrlemi1 6408. (Contributed by Jim Kingdon, 4-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
 |-  A  =  { f  |  E. x  e.  On  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( F `
  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  A. x ( Fun  F  /\  ( F `  x )  e.  _V )
 )   &    |-  ( ph  ->  z  e.  On )   &    |-  ( ph  ->  g  Fn  z )   &    |-  ( ph  ->  g  e.  A )   =>    |-  ( ph  ->  (
 g  u.  { <. z ,  ( F `  g ) >. } )  e.  A )
 
Theoremtfrlemibacc 6402* Each element of  B is an acceptable function. Lemma for tfrlemi1 6408. (Contributed by Jim Kingdon, 14-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
 |-  A  =  { f  |  E. x  e.  On  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( F `
  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  A. x ( Fun  F  /\  ( F `  x )  e.  _V )
 )   &    |-  B  =  { h  |  E. z  e.  x  E. g ( g  Fn  z  /\  g  e.  A  /\  h  =  ( g  u.  { <. z ,  ( F `
  g ) >. } ) ) }   &    |-  ( ph  ->  x  e.  On )   &    |-  ( ph  ->  A. z  e.  x  E. g
 ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( F `  ( g  |`  w ) ) ) )   =>    |-  ( ph  ->  B 
 C_  A )
 
Theoremtfrlemibxssdm 6403* The union of  B is defined on all ordinals. Lemma for tfrlemi1 6408. (Contributed by Jim Kingdon, 18-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
 |-  A  =  { f  |  E. x  e.  On  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( F `
  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  A. x ( Fun  F  /\  ( F `  x )  e.  _V )
 )   &    |-  B  =  { h  |  E. z  e.  x  E. g ( g  Fn  z  /\  g  e.  A  /\  h  =  ( g  u.  { <. z ,  ( F `
  g ) >. } ) ) }   &    |-  ( ph  ->  x  e.  On )   &    |-  ( ph  ->  A. z  e.  x  E. g
 ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( F `  ( g  |`  w ) ) ) )   =>    |-  ( ph  ->  x 
 C_  dom  U. B )
 
Theoremtfrlemibfn 6404* The union of  B is a function defined on  x. Lemma for tfrlemi1 6408. (Contributed by Jim Kingdon, 18-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
 |-  A  =  { f  |  E. x  e.  On  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( F `
  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  A. x ( Fun  F  /\  ( F `  x )  e.  _V )
 )   &    |-  B  =  { h  |  E. z  e.  x  E. g ( g  Fn  z  /\  g  e.  A  /\  h  =  ( g  u.  { <. z ,  ( F `
  g ) >. } ) ) }   &    |-  ( ph  ->  x  e.  On )   &    |-  ( ph  ->  A. z  e.  x  E. g
 ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( F `  ( g  |`  w ) ) ) )   =>    |-  ( ph  ->  U. B  Fn  x )
 
Theoremtfrlemibex 6405* The set  B exists. Lemma for tfrlemi1 6408. (Contributed by Jim Kingdon, 17-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
 |-  A  =  { f  |  E. x  e.  On  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( F `
  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  A. x ( Fun  F  /\  ( F `  x )  e.  _V )
 )   &    |-  B  =  { h  |  E. z  e.  x  E. g ( g  Fn  z  /\  g  e.  A  /\  h  =  ( g  u.  { <. z ,  ( F `
  g ) >. } ) ) }   &    |-  ( ph  ->  x  e.  On )   &    |-  ( ph  ->  A. z  e.  x  E. g
 ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( F `  ( g  |`  w ) ) ) )   =>    |-  ( ph  ->  B  e.  _V )
 
Theoremtfrlemiubacc 6406* The union of  B satisfies the recursion rule (lemma for tfrlemi1 6408). (Contributed by Jim Kingdon, 22-Apr-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
 |-  A  =  { f  |  E. x  e.  On  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( F `
  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  A. x ( Fun  F  /\  ( F `  x )  e.  _V )
 )   &    |-  B  =  { h  |  E. z  e.  x  E. g ( g  Fn  z  /\  g  e.  A  /\  h  =  ( g  u.  { <. z ,  ( F `
  g ) >. } ) ) }   &    |-  ( ph  ->  x  e.  On )   &    |-  ( ph  ->  A. z  e.  x  E. g
 ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( F `  ( g  |`  w ) ) ) )   =>    |-  ( ph  ->  A. u  e.  x  (
 U. B `  u )  =  ( F `  ( U. B  |`  u ) ) )
 
Theoremtfrlemiex 6407* Lemma for tfrlemi1 6408. (Contributed by Jim Kingdon, 18-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)
 |-  A  =  { f  |  E. x  e.  On  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( F `
  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  A. x ( Fun  F  /\  ( F `  x )  e.  _V )
 )   &    |-  B  =  { h  |  E. z  e.  x  E. g ( g  Fn  z  /\  g  e.  A  /\  h  =  ( g  u.  { <. z ,  ( F `
  g ) >. } ) ) }   &    |-  ( ph  ->  x  e.  On )   &    |-  ( ph  ->  A. z  e.  x  E. g
 ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( F `  ( g  |`  w ) ) ) )   =>    |-  ( ph  ->  E. f ( f  Fn  x  /\  A. u  e.  x  ( f `  u )  =  ( F `  ( f  |`  u ) ) ) )
 
Theoremtfrlemi1 6408* We can define an acceptable function on any ordinal.

As with many of the transfinite recursion theorems, we have a hypothesis that states that  F is a function and that it is defined for all ordinals. (Contributed by Jim Kingdon, 4-Mar-2019.) (Proof shortened by Mario Carneiro, 24-May-2019.)

 |-  A  =  { f  |  E. x  e.  On  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( F `
  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  A. x ( Fun  F  /\  ( F `  x )  e.  _V )
 )   =>    |-  ( ( ph  /\  C  e.  On )  ->  E. g
 ( g  Fn  C  /\  A. u  e.  C  ( g `  u )  =  ( F `  ( g  |`  u ) ) ) )
 
Theoremtfrlemi14d 6409* The domain of recs is all ordinals (lemma for transfinite recursion). (Contributed by Jim Kingdon, 9-Jul-2019.)
 |-  A  =  { f  |  E. x  e.  On  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( F `
  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  A. x ( Fun  F  /\  ( F `  x )  e.  _V )
 )   =>    |-  ( ph  ->  dom recs ( F )  =  On )
 
Theoremtfrexlem 6410* The transfinite recursion function is set-like if the input is. (Contributed by Mario Carneiro, 3-Jul-2019.)
 |-  A  =  { f  |  E. x  e.  On  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( F `
  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  A. x ( Fun  F  /\  ( F `  x )  e.  _V )
 )   =>    |-  ( ( ph  /\  C  e.  V )  ->  (recs ( F ) `  C )  e.  _V )
 
Theoremtfri1d 6411* Principle of Transfinite Recursion, part 1 of 3. Theorem 7.41(1) of [TakeutiZaring] p. 47, with an additional condition.

The condition is that  G is defined "everywhere", which is stated here as  ( G `  x )  e.  _V. Alternately,  A. x  e.  On A. f ( f  Fn  x  -> 
f  e.  dom  G
) would suffice.

Given a function  G satisfying that condition, we define a class  A of all "acceptable" functions. The final function we're interested in is the union 
F  = recs ( G ) of them.  F is then said to be defined by transfinite recursion. The purpose of the 3 parts of this theorem is to demonstrate properties of  F. In this first part we show that  F is a function whose domain is all ordinal numbers. (Contributed by Jim Kingdon, 4-May-2019.) (Revised by Mario Carneiro, 24-May-2019.)

 |-  F  = recs ( G )   &    |-  ( ph  ->  A. x ( Fun  G  /\  ( G `  x )  e.  _V )
 )   =>    |-  ( ph  ->  F  Fn  On )
 
Theoremtfri2d 6412* Principle of Transfinite Recursion, part 2 of 3. Theorem 7.41(2) of [TakeutiZaring] p. 47, with an additional condition on the recursion rule  G ( as described at tfri1 6441). Here we show that the function  F has the property that for any function  G satisfying that condition, the "next" value of  F is  G recursively applied to all "previous" values of  F. (Contributed by Jim Kingdon, 4-May-2019.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  A. x ( Fun  G  /\  ( G `  x )  e.  _V )
 )   =>    |-  ( ( ph  /\  A  e.  On )  ->  ( F `  A )  =  ( G `  ( F  |`  A ) ) )
 
Theoremtfr1onlem3ag 6413* Lemma for transfinite recursion. This lemma changes some bound variables in  A (version of tfrlem3ag 6385 but for tfr1on 6426 related lemmas). (Contributed by Jim Kingdon, 13-Mar-2022.)
 |-  A  =  { f  |  E. x  e.  X  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( G `
  ( f  |`  y ) ) ) }   =>    |-  ( H  e.  V  ->  ( H  e.  A  <->  E. z  e.  X  ( H  Fn  z  /\  A. w  e.  z  ( H `  w )  =  ( G `  ( H  |`  w ) ) ) ) )
 
Theoremtfr1onlem3 6414* Lemma for transfinite recursion. This lemma changes some bound variables in  A (version of tfrlem3 6387 but for tfr1on 6426 related lemmas). (Contributed by Jim Kingdon, 14-Mar-2022.)
 |-  A  =  { f  |  E. x  e.  X  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( G `
  ( f  |`  y ) ) ) }   =>    |-  A  =  { g  |  E. z  e.  X  ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( G `  ( g  |`  w ) ) ) }
 
Theoremtfr1onlemssrecs 6415* Lemma for tfr1on 6426. The union of functions acceptable for tfr1on 6426 is a subset of recs. (Contributed by Jim Kingdon, 15-Mar-2022.)
 |-  A  =  { f  |  E. x  e.  X  ( f  Fn  x  /\  A. y  e.  x  ( f `  y
 )  =  ( G `
  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  Ord 
 X )   =>    |-  ( ph  ->  U. A  C_ recs
 ( G ) )
 
Theoremtfr1onlemsucfn 6416* We can extend an acceptable function by one element to produce a function. Lemma for tfr1on 6426. (Contributed by Jim Kingdon, 12-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f  Fn  x )  ->  ( G `  f )  e.  _V )   &    |-  A  =  { f  |  E. x  e.  X  (
 f  Fn  x  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  z  e.  X )   &    |-  ( ph  ->  g  Fn  z )   &    |-  ( ph  ->  g  e.  A )   =>    |-  ( ph  ->  ( g  u.  { <. z ,  ( G `  g ) >. } )  Fn  suc  z )
 
Theoremtfr1onlemsucaccv 6417* Lemma for tfr1on 6426. We can extend an acceptable function by one element to produce an acceptable function. (Contributed by Jim Kingdon, 12-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f  Fn  x )  ->  ( G `  f )  e.  _V )   &    |-  A  =  { f  |  E. x  e.  X  (
 f  Fn  x  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  Y  e.  X )   &    |-  ( ph  ->  z  e.  Y )   &    |-  ( ( ph  /\  x  e.  U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  g  Fn  z )   &    |-  ( ph  ->  g  e.  A )   =>    |-  ( ph  ->  (
 g  u.  { <. z ,  ( G `  g ) >. } )  e.  A )
 
Theoremtfr1onlembacc 6418* Lemma for tfr1on 6426. Each element of  B is an acceptable function. (Contributed by Jim Kingdon, 14-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f  Fn  x )  ->  ( G `  f )  e.  _V )   &    |-  A  =  { f  |  E. x  e.  X  (
 f  Fn  x  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  B  =  { h  |  E. z  e.  D  E. g
 ( g  Fn  z  /\  g  e.  A  /\  h  =  (
 g  u.  { <. z ,  ( G `  g ) >. } )
 ) }   &    |-  ( ( ph  /\  x  e.  U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  D  e.  X )   &    |-  ( ph  ->  A. z  e.  D  E. g ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( G `  ( g  |`  w ) ) ) )   =>    |-  ( ph  ->  B  C_  A )
 
Theoremtfr1onlembxssdm 6419* Lemma for tfr1on 6426. The union of  B is defined on all elements of  X. (Contributed by Jim Kingdon, 14-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f  Fn  x )  ->  ( G `  f )  e.  _V )   &    |-  A  =  { f  |  E. x  e.  X  (
 f  Fn  x  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  B  =  { h  |  E. z  e.  D  E. g
 ( g  Fn  z  /\  g  e.  A  /\  h  =  (
 g  u.  { <. z ,  ( G `  g ) >. } )
 ) }   &    |-  ( ( ph  /\  x  e.  U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  D  e.  X )   &    |-  ( ph  ->  A. z  e.  D  E. g ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( G `  ( g  |`  w ) ) ) )   =>    |-  ( ph  ->  D  C_ 
 dom  U. B )
 
Theoremtfr1onlembfn 6420* Lemma for tfr1on 6426. The union of  B is a function defined on  x. (Contributed by Jim Kingdon, 15-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f  Fn  x )  ->  ( G `  f )  e.  _V )   &    |-  A  =  { f  |  E. x  e.  X  (
 f  Fn  x  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  B  =  { h  |  E. z  e.  D  E. g
 ( g  Fn  z  /\  g  e.  A  /\  h  =  (
 g  u.  { <. z ,  ( G `  g ) >. } )
 ) }   &    |-  ( ( ph  /\  x  e.  U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  D  e.  X )   &    |-  ( ph  ->  A. z  e.  D  E. g ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( G `  ( g  |`  w ) ) ) )   =>    |-  ( ph  ->  U. B  Fn  D )
 
Theoremtfr1onlembex 6421* Lemma for tfr1on 6426. The set  B exists. (Contributed by Jim Kingdon, 14-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f  Fn  x )  ->  ( G `  f )  e.  _V )   &    |-  A  =  { f  |  E. x  e.  X  (
 f  Fn  x  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  B  =  { h  |  E. z  e.  D  E. g
 ( g  Fn  z  /\  g  e.  A  /\  h  =  (
 g  u.  { <. z ,  ( G `  g ) >. } )
 ) }   &    |-  ( ( ph  /\  x  e.  U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  D  e.  X )   &    |-  ( ph  ->  A. z  e.  D  E. g ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( G `  ( g  |`  w ) ) ) )   =>    |-  ( ph  ->  B  e.  _V )
 
Theoremtfr1onlemubacc 6422* Lemma for tfr1on 6426. The union of  B satisfies the recursion rule. (Contributed by Jim Kingdon, 15-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f  Fn  x )  ->  ( G `  f )  e.  _V )   &    |-  A  =  { f  |  E. x  e.  X  (
 f  Fn  x  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  B  =  { h  |  E. z  e.  D  E. g
 ( g  Fn  z  /\  g  e.  A  /\  h  =  (
 g  u.  { <. z ,  ( G `  g ) >. } )
 ) }   &    |-  ( ( ph  /\  x  e.  U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  D  e.  X )   &    |-  ( ph  ->  A. z  e.  D  E. g ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( G `  ( g  |`  w ) ) ) )   =>    |-  ( ph  ->  A. u  e.  D  ( U. B `  u )  =  ( G `  ( U. B  |`  u ) ) )
 
Theoremtfr1onlemex 6423* Lemma for tfr1on 6426. (Contributed by Jim Kingdon, 16-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f  Fn  x )  ->  ( G `  f )  e.  _V )   &    |-  A  =  { f  |  E. x  e.  X  (
 f  Fn  x  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  B  =  { h  |  E. z  e.  D  E. g
 ( g  Fn  z  /\  g  e.  A  /\  h  =  (
 g  u.  { <. z ,  ( G `  g ) >. } )
 ) }   &    |-  ( ( ph  /\  x  e.  U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  D  e.  X )   &    |-  ( ph  ->  A. z  e.  D  E. g ( g  Fn  z  /\  A. w  e.  z  ( g `  w )  =  ( G `  ( g  |`  w ) ) ) )   =>    |-  ( ph  ->  E. f
 ( f  Fn  D  /\  A. u  e.  D  ( f `  u )  =  ( G `  ( f  |`  u ) ) ) )
 
Theoremtfr1onlemaccex 6424* We can define an acceptable function on any element of  X.

As with many of the transfinite recursion theorems, we have hypotheses that state that  F is a function and that it is defined up to  X. (Contributed by Jim Kingdon, 16-Mar-2022.)

 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f  Fn  x )  ->  ( G `  f )  e.  _V )   &    |-  A  =  { f  |  E. x  e.  X  (
 f  Fn  x  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  (
 ( ph  /\  x  e. 
 U. X )  ->  suc  x  e.  X )   =>    |-  ( ( ph  /\  C  e.  X )  ->  E. g
 ( g  Fn  C  /\  A. u  e.  C  ( g `  u )  =  ( G `  ( g  |`  u ) ) ) )
 
Theoremtfr1onlemres 6425* Lemma for tfr1on 6426. Recursion is defined on an ordinal if the characteristic function is defined up to a suitable point. (Contributed by Jim Kingdon, 18-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f  Fn  x )  ->  ( G `  f )  e.  _V )   &    |-  A  =  { f  |  E. x  e.  X  (
 f  Fn  x  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  (
 ( ph  /\  x  e. 
 U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  Y  e.  X )   =>    |-  ( ph  ->  Y  C_ 
 dom  F )
 
Theoremtfr1on 6426* Recursion is defined on an ordinal if the characteristic function is defined up to a suitable point. (Contributed by Jim Kingdon, 12-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f  Fn  x )  ->  ( G `  f )  e.  _V )   &    |-  (
 ( ph  /\  x  e. 
 U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  Y  e.  X )   =>    |-  ( ph  ->  Y  C_ 
 dom  F )
 
Theoremtfri1dALT 6427* Alternate proof of tfri1d 6411 in terms of tfr1on 6426.

Although this does show that the tfr1on 6426 proof is general enough to also prove tfri1d 6411, the tfri1d 6411 proof is simpler in places because it does not need to deal with 
X being any ordinal. For that reason, we have both proofs. (Proof modification is discouraged.) (New usage is discouraged.) (Contributed by Jim Kingdon, 20-Mar-2022.)

 |-  F  = recs ( G )   &    |-  ( ph  ->  A. x ( Fun  G  /\  ( G `  x )  e.  _V )
 )   =>    |-  ( ph  ->  F  Fn  On )
 
Theoremtfrcllemssrecs 6428* Lemma for tfrcl 6440. The union of functions acceptable for tfrcl 6440 is a subset of recs. (Contributed by Jim Kingdon, 25-Mar-2022.)
 |-  A  =  { f  |  E. x  e.  X  ( f : x --> S  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  Ord 
 X )   =>    |-  ( ph  ->  U. A  C_ recs
 ( G ) )
 
Theoremtfrcllemsucfn 6429* We can extend an acceptable function by one element to produce a function. Lemma for tfrcl 6440. (Contributed by Jim Kingdon, 24-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f : x --> S ) 
 ->  ( G `  f
 )  e.  S )   &    |-  A  =  { f  |  E. x  e.  X  ( f : x --> S  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  z  e.  X )   &    |-  ( ph  ->  g : z --> S )   &    |-  ( ph  ->  g  e.  A )   =>    |-  ( ph  ->  ( g  u.  { <. z ,  ( G `  g ) >. } ) : suc  z --> S )
 
Theoremtfrcllemsucaccv 6430* Lemma for tfrcl 6440. We can extend an acceptable function by one element to produce an acceptable function. (Contributed by Jim Kingdon, 24-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f : x --> S ) 
 ->  ( G `  f
 )  e.  S )   &    |-  A  =  { f  |  E. x  e.  X  ( f : x --> S  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  ( ph  ->  Y  e.  X )   &    |-  ( ph  ->  z  e.  Y )   &    |-  ( ( ph  /\  x  e.  U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  g :
 z --> S )   &    |-  ( ph  ->  g  e.  A )   =>    |-  ( ph  ->  (
 g  u.  { <. z ,  ( G `  g ) >. } )  e.  A )
 
Theoremtfrcllembacc 6431* Lemma for tfrcl 6440. Each element of  B is an acceptable function. (Contributed by Jim Kingdon, 25-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f : x --> S ) 
 ->  ( G `  f
 )  e.  S )   &    |-  A  =  { f  |  E. x  e.  X  ( f : x --> S  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  B  =  { h  |  E. z  e.  D  E. g ( g : z --> S  /\  g  e.  A  /\  h  =  ( g  u.  { <. z ,  ( G `  g ) >. } ) ) }   &    |-  (
 ( ph  /\  x  e. 
 U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  D  e.  X )   &    |-  ( ph  ->  A. z  e.  D  E. g ( g : z --> S  /\  A. w  e.  z  (
 g `  w )  =  ( G `  (
 g  |`  w ) ) ) )   =>    |-  ( ph  ->  B  C_  A )
 
Theoremtfrcllembxssdm 6432* Lemma for tfrcl 6440. The union of  B is defined on all elements of  X. (Contributed by Jim Kingdon, 25-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f : x --> S ) 
 ->  ( G `  f
 )  e.  S )   &    |-  A  =  { f  |  E. x  e.  X  ( f : x --> S  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  B  =  { h  |  E. z  e.  D  E. g ( g : z --> S  /\  g  e.  A  /\  h  =  ( g  u.  { <. z ,  ( G `  g ) >. } ) ) }   &    |-  (
 ( ph  /\  x  e. 
 U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  D  e.  X )   &    |-  ( ph  ->  A. z  e.  D  E. g ( g : z --> S  /\  A. w  e.  z  (
 g `  w )  =  ( G `  (
 g  |`  w ) ) ) )   =>    |-  ( ph  ->  D  C_ 
 dom  U. B )
 
Theoremtfrcllembfn 6433* Lemma for tfrcl 6440. The union of  B is a function defined on  x. (Contributed by Jim Kingdon, 25-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f : x --> S ) 
 ->  ( G `  f
 )  e.  S )   &    |-  A  =  { f  |  E. x  e.  X  ( f : x --> S  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  B  =  { h  |  E. z  e.  D  E. g ( g : z --> S  /\  g  e.  A  /\  h  =  ( g  u.  { <. z ,  ( G `  g ) >. } ) ) }   &    |-  (
 ( ph  /\  x  e. 
 U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  D  e.  X )   &    |-  ( ph  ->  A. z  e.  D  E. g ( g : z --> S  /\  A. w  e.  z  (
 g `  w )  =  ( G `  (
 g  |`  w ) ) ) )   =>    |-  ( ph  ->  U. B : D --> S )
 
Theoremtfrcllembex 6434* Lemma for tfrcl 6440. The set  B exists. (Contributed by Jim Kingdon, 25-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f : x --> S ) 
 ->  ( G `  f
 )  e.  S )   &    |-  A  =  { f  |  E. x  e.  X  ( f : x --> S  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  B  =  { h  |  E. z  e.  D  E. g ( g : z --> S  /\  g  e.  A  /\  h  =  ( g  u.  { <. z ,  ( G `  g ) >. } ) ) }   &    |-  (
 ( ph  /\  x  e. 
 U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  D  e.  X )   &    |-  ( ph  ->  A. z  e.  D  E. g ( g : z --> S  /\  A. w  e.  z  (
 g `  w )  =  ( G `  (
 g  |`  w ) ) ) )   =>    |-  ( ph  ->  B  e.  _V )
 
Theoremtfrcllemubacc 6435* Lemma for tfrcl 6440. The union of  B satisfies the recursion rule. (Contributed by Jim Kingdon, 25-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f : x --> S ) 
 ->  ( G `  f
 )  e.  S )   &    |-  A  =  { f  |  E. x  e.  X  ( f : x --> S  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  B  =  { h  |  E. z  e.  D  E. g ( g : z --> S  /\  g  e.  A  /\  h  =  ( g  u.  { <. z ,  ( G `  g ) >. } ) ) }   &    |-  (
 ( ph  /\  x  e. 
 U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  D  e.  X )   &    |-  ( ph  ->  A. z  e.  D  E. g ( g : z --> S  /\  A. w  e.  z  (
 g `  w )  =  ( G `  (
 g  |`  w ) ) ) )   =>    |-  ( ph  ->  A. u  e.  D  ( U. B `  u )  =  ( G `  ( U. B  |`  u ) ) )
 
Theoremtfrcllemex 6436* Lemma for tfrcl 6440. (Contributed by Jim Kingdon, 26-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f : x --> S ) 
 ->  ( G `  f
 )  e.  S )   &    |-  A  =  { f  |  E. x  e.  X  ( f : x --> S  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  B  =  { h  |  E. z  e.  D  E. g ( g : z --> S  /\  g  e.  A  /\  h  =  ( g  u.  { <. z ,  ( G `  g ) >. } ) ) }   &    |-  (
 ( ph  /\  x  e. 
 U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  D  e.  X )   &    |-  ( ph  ->  A. z  e.  D  E. g ( g : z --> S  /\  A. w  e.  z  (
 g `  w )  =  ( G `  (
 g  |`  w ) ) ) )   =>    |-  ( ph  ->  E. f
 ( f : D --> S  /\  A. u  e.  D  ( f `  u )  =  ( G `  ( f  |`  u ) ) ) )
 
Theoremtfrcllemaccex 6437* We can define an acceptable function on any element of  X.

As with many of the transfinite recursion theorems, we have hypotheses that state that  F is a function and that it is defined up to  X. (Contributed by Jim Kingdon, 26-Mar-2022.)

 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f : x --> S ) 
 ->  ( G `  f
 )  e.  S )   &    |-  A  =  { f  |  E. x  e.  X  ( f : x --> S  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  ( ( ph  /\  x  e.  U. X )  ->  suc  x  e.  X )   =>    |-  ( ( ph  /\  C  e.  X )  ->  E. g
 ( g : C --> S  /\  A. u  e.  C  ( g `  u )  =  ( G `  ( g  |`  u ) ) ) )
 
Theoremtfrcllemres 6438* Lemma for tfr1on 6426. Recursion is defined on an ordinal if the characteristic function is defined up to a suitable point. (Contributed by Jim Kingdon, 18-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f : x --> S ) 
 ->  ( G `  f
 )  e.  S )   &    |-  A  =  { f  |  E. x  e.  X  ( f : x --> S  /\  A. y  e.  x  ( f `  y )  =  ( G `  ( f  |`  y ) ) ) }   &    |-  ( ( ph  /\  x  e.  U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  Y  e.  X )   =>    |-  ( ph  ->  Y 
 C_  dom  F )
 
Theoremtfrcldm 6439* Recursion is defined on an ordinal if the characteristic function satisfies a closure hypothesis up to a suitable point. (Contributed by Jim Kingdon, 26-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f : x --> S ) 
 ->  ( G `  f
 )  e.  S )   &    |-  ( ( ph  /\  x  e.  U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  Y  e.  U. X )   =>    |-  ( ph  ->  Y  e.  dom  F )
 
Theoremtfrcl 6440* Closure for transfinite recursion. As with tfr1on 6426, the characteristic function must be defined up to a suitable point, not necessarily on all ordinals. (Contributed by Jim Kingdon, 25-Mar-2022.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  Fun 
 G )   &    |-  ( ph  ->  Ord 
 X )   &    |-  ( ( ph  /\  x  e.  X  /\  f : x --> S ) 
 ->  ( G `  f
 )  e.  S )   &    |-  ( ( ph  /\  x  e.  U. X )  ->  suc  x  e.  X )   &    |-  ( ph  ->  Y  e.  U. X )   =>    |-  ( ph  ->  ( F `  Y )  e.  S )
 
Theoremtfri1 6441* Principle of Transfinite Recursion, part 1 of 3. Theorem 7.41(1) of [TakeutiZaring] p. 47, with an additional condition.

The condition is that  G is defined "everywhere", which is stated here as  ( G `  x )  e.  _V. Alternately,  A. x  e.  On A. f ( f  Fn  x  -> 
f  e.  dom  G
) would suffice.

Given a function  G satisfying that condition, we define a class  A of all "acceptable" functions. The final function we're interested in is the union 
F  = recs ( G ) of them.  F is then said to be defined by transfinite recursion. The purpose of the 3 parts of this theorem is to demonstrate properties of  F. In this first part we show that  F is a function whose domain is all ordinal numbers. (Contributed by Jim Kingdon, 4-May-2019.) (Revised by Mario Carneiro, 24-May-2019.)

 |-  F  = recs ( G )   &    |-  ( Fun  G  /\  ( G `  x )  e.  _V )   =>    |-  F  Fn  On
 
Theoremtfri2 6442* Principle of Transfinite Recursion, part 2 of 3. Theorem 7.41(2) of [TakeutiZaring] p. 47, with an additional condition on the recursion rule  G ( as described at tfri1 6441). Here we show that the function  F has the property that for any function  G satisfying that condition, the "next" value of  F is  G recursively applied to all "previous" values of  F. (Contributed by Jim Kingdon, 4-May-2019.)
 |-  F  = recs ( G )   &    |-  ( Fun  G  /\  ( G `  x )  e.  _V )   =>    |-  ( A  e.  On  ->  ( F `  A )  =  ( G `  ( F  |`  A ) ) )
 
Theoremtfri3 6443* Principle of Transfinite Recursion, part 3 of 3. Theorem 7.41(3) of [TakeutiZaring] p. 47, with an additional condition on the recursion rule  G ( as described at tfri1 6441). Finally, we show that  F is unique. We do this by showing that any class  B with the same properties of  F that we showed in parts 1 and 2 is identical to  F. (Contributed by Jim Kingdon, 4-May-2019.)
 |-  F  = recs ( G )   &    |-  ( Fun  G  /\  ( G `  x )  e.  _V )   =>    |-  (
 ( B  Fn  On  /\ 
 A. x  e.  On  ( B `  x )  =  ( G `  ( B  |`  x ) ) )  ->  B  =  F )
 
Theoremtfrex 6444* The transfinite recursion function is set-like if the input is. (Contributed by Mario Carneiro, 3-Jul-2019.)
 |-  F  = recs ( G )   &    |-  ( ph  ->  A. x ( Fun  G  /\  ( G `  x )  e.  _V )
 )   =>    |-  ( ( ph  /\  A  e.  V )  ->  ( F `  A )  e. 
 _V )
 
2.6.21  Recursive definition generator
 
Syntaxcrdg 6445 Extend class notation with the recursive definition generator, with characteristic function  F and initial value  I.
 class  rec ( F ,  I
 )
 
Definitiondf-irdg 6446* Define a recursive definition generator on  On (the class of ordinal numbers) with characteristic function  F and initial value  I. This rather amazing operation allows us to define, with compact direct definitions, functions that are usually defined in textbooks only with indirect self-referencing recursive definitions. A recursive definition requires advanced metalogic to justify - in particular, eliminating a recursive definition is very difficult and often not even shown in textbooks. On the other hand, the elimination of a direct definition is a matter of simple mechanical substitution. The price paid is the daunting complexity of our 
rec operation (especially when df-recs 6381 that it is built on is also eliminated). But once we get past this hurdle, definitions that would otherwise be recursive become relatively simple. In classical logic it would be easier to divide this definition into cases based on whether the domain of  g is zero, a successor, or a limit ordinal. Cases do not (in general) work that way in intuitionistic logic, so instead we choose a definition which takes the union of all the results of the characteristic function for ordinals in the domain of  g. This means that this definition has the expected properties for increasing and continuous ordinal functions, which include ordinal addition and multiplication.

For finite recursion we also define df-frec 6467 and for suitable characteristic functions df-frec 6467 yields the same result as  rec restricted to  om, as seen at frecrdg 6484.

Note: We introduce 
rec with the philosophical goal of being able to eliminate all definitions with direct mechanical substitution and to verify easily the soundness of definitions. Metamath itself has no built-in technical limitation that prevents multiple-part recursive definitions in the traditional textbook style. (Contributed by Jim Kingdon, 19-May-2019.)

 |- 
 rec ( F ,  I )  = recs (
 ( g  e.  _V  |->  ( I  u.  U_ x  e.  dom  g ( F `
  ( g `  x ) ) ) ) )
 
Theoremrdgeq1 6447 Equality theorem for the recursive definition generator. (Contributed by NM, 9-Apr-1995.) (Revised by Mario Carneiro, 9-May-2015.)
 |-  ( F  =  G  ->  rec ( F ,  A )  =  rec ( G ,  A ) )
 
Theoremrdgeq2 6448 Equality theorem for the recursive definition generator. (Contributed by NM, 9-Apr-1995.) (Revised by Mario Carneiro, 9-May-2015.)
 |-  ( A  =  B  ->  rec ( F ,  A )  =  rec ( F ,  B ) )
 
Theoremrdgfun 6449 The recursive definition generator is a function. (Contributed by Mario Carneiro, 16-Nov-2014.)
 |- 
 Fun  rec ( F ,  A )
 
Theoremrdgtfr 6450* The recursion rule for the recursive definition generator is defined everywhere. (Contributed by Jim Kingdon, 14-May-2020.)
 |-  ( ( A. z
 ( F `  z
 )  e.  _V  /\  A  e.  V )  ->  ( Fun  ( g  e.  _V  |->  ( A  u.  U_ x  e.  dom  g ( F `  ( g `  x ) ) ) ) 
 /\  ( ( g  e.  _V  |->  ( A  u.  U_ x  e.  dom  g ( F `  ( g `  x ) ) ) ) `
  f )  e. 
 _V ) )
 
Theoremrdgruledefgg 6451* The recursion rule for the recursive definition generator is defined everywhere. (Contributed by Jim Kingdon, 4-Jul-2019.)
 |-  ( ( F  Fn  _V 
 /\  A  e.  V )  ->  ( Fun  (
 g  e.  _V  |->  ( A  u.  U_ x  e.  dom  g ( F `
  ( g `  x ) ) ) )  /\  ( ( g  e.  _V  |->  ( A  u.  U_ x  e.  dom  g ( F `
  ( g `  x ) ) ) ) `  f )  e.  _V ) )
 
Theoremrdgruledefg 6452* The recursion rule for the recursive definition generator is defined everywhere. (Contributed by Jim Kingdon, 4-Jul-2019.)
 |-  F  Fn  _V   =>    |-  ( A  e.  V  ->  ( Fun  (
 g  e.  _V  |->  ( A  u.  U_ x  e.  dom  g ( F `
  ( g `  x ) ) ) )  /\  ( ( g  e.  _V  |->  ( A  u.  U_ x  e.  dom  g ( F `
  ( g `  x ) ) ) ) `  f )  e.  _V ) )
 
Theoremrdgexggg 6453 The recursive definition generator produces a set on a set input. (Contributed by Jim Kingdon, 4-Jul-2019.)
 |-  ( ( F  Fn  _V 
 /\  A  e.  V  /\  B  e.  W ) 
 ->  ( rec ( F ,  A ) `  B )  e.  _V )
 
Theoremrdgexgg 6454 The recursive definition generator produces a set on a set input. (Contributed by Jim Kingdon, 4-Jul-2019.)
 |-  F  Fn  _V   =>    |-  ( ( A  e.  V  /\  B  e.  W )  ->  ( rec ( F ,  A ) `  B )  e. 
 _V )
 
Theoremrdgifnon 6455 The recursive definition generator is a function on ordinal numbers. The  F  Fn  _V condition states that the characteristic function is defined for all sets (being defined for all ordinals might be enough if being used in a manner similar to rdgon 6462; in cases like df-oadd 6496 either presumably could work). (Contributed by Jim Kingdon, 13-Jul-2019.)
 |-  ( ( F  Fn  _V 
 /\  A  e.  V )  ->  rec ( F ,  A )  Fn  On )
 
Theoremrdgifnon2 6456* The recursive definition generator is a function on ordinal numbers. (Contributed by Jim Kingdon, 14-May-2020.)
 |-  ( ( A. z
 ( F `  z
 )  e.  _V  /\  A  e.  V )  ->  rec ( F ,  A )  Fn  On )
 
Theoremrdgivallem 6457* Value of the recursive definition generator. Lemma for rdgival 6458 which simplifies the value further. (Contributed by Jim Kingdon, 13-Jul-2019.) (New usage is discouraged.)
 |-  ( ( F  Fn  _V 
 /\  A  e.  V  /\  B  e.  On )  ->  ( rec ( F ,  A ) `  B )  =  ( A  u.  U_ x  e.  B  ( F `  ( ( rec ( F ,  A )  |`  B ) `
  x ) ) ) )
 
Theoremrdgival 6458* Value of the recursive definition generator. (Contributed by Jim Kingdon, 26-Jul-2019.)
 |-  ( ( F  Fn  _V 
 /\  A  e.  V  /\  B  e.  On )  ->  ( rec ( F ,  A ) `  B )  =  ( A  u.  U_ x  e.  B  ( F `  ( rec ( F ,  A ) `  x ) ) ) )
 
Theoremrdgss 6459 Subset and recursive definition generator. (Contributed by Jim Kingdon, 15-Jul-2019.)
 |-  ( ph  ->  F  Fn  _V )   &    |-  ( ph  ->  I  e.  V )   &    |-  ( ph  ->  A  e.  On )   &    |-  ( ph  ->  B  e.  On )   &    |-  ( ph  ->  A 
 C_  B )   =>    |-  ( ph  ->  ( rec ( F ,  I ) `  A )  C_  ( rec ( F ,  I ) `  B ) )
 
Theoremrdgisuc1 6460* One way of describing the value of the recursive definition generator at a successor. There is no condition on the characteristic function  F other than  F  Fn  _V. Given that, the resulting expression encompasses both the expected successor term  ( F `  ( rec ( F ,  A ) `  B
) ) but also terms that correspond to the initial value  A and to limit ordinals  U_ x  e.  B ( F `  ( rec ( F ,  A ) `  x
) ).

If we add conditions on the characteristic function, we can show tighter results such as rdgisucinc 6461. (Contributed by Jim Kingdon, 9-Jun-2019.)

 |-  ( ph  ->  F  Fn  _V )   &    |-  ( ph  ->  A  e.  V )   &    |-  ( ph  ->  B  e.  On )   =>    |-  ( ph  ->  ( rec ( F ,  A ) `  suc  B )  =  ( A  u.  ( U_ x  e.  B  ( F `  ( rec ( F ,  A ) `  x ) )  u.  ( F `  ( rec ( F ,  A ) `  B ) ) ) ) )
 
Theoremrdgisucinc 6461* Value of the recursive definition generator at a successor.

This can be thought of as a generalization of oasuc 6540 and omsuc 6548. (Contributed by Jim Kingdon, 29-Aug-2019.)

 |-  ( ph  ->  F  Fn  _V )   &    |-  ( ph  ->  A  e.  V )   &    |-  ( ph  ->  B  e.  On )   &    |-  ( ph  ->  A. x  x  C_  ( F `  x ) )   =>    |-  ( ph  ->  ( rec ( F ,  A ) `  suc  B )  =  ( F `
  ( rec ( F ,  A ) `  B ) ) )
 
Theoremrdgon 6462* Evaluating the recursive definition generator produces an ordinal. There is a hypothesis that the characteristic function produces ordinals on ordinal arguments. (Contributed by Jim Kingdon, 26-Jul-2019.) (Revised by Jim Kingdon, 13-Apr-2022.)
 |-  ( ph  ->  A  e.  On )   &    |-  ( ph  ->  A. x  e.  On  ( F `  x )  e. 
 On )   =>    |-  ( ( ph  /\  B  e.  On )  ->  ( rec ( F ,  A ) `  B )  e. 
 On )
 
Theoremrdg0 6463 The initial value of the recursive definition generator. (Contributed by NM, 23-Apr-1995.) (Revised by Mario Carneiro, 14-Nov-2014.)
 |-  A  e.  _V   =>    |-  ( rec ( F ,  A ) `  (/) )  =  A
 
Theoremrdg0g 6464 The initial value of the recursive definition generator. (Contributed by NM, 25-Apr-1995.)
 |-  ( A  e.  C  ->  ( rec ( F ,  A ) `  (/) )  =  A )
 
Theoremrdgexg 6465 The recursive definition generator produces a set on a set input. (Contributed by Mario Carneiro, 3-Jul-2019.)
 |-  A  e.  _V   &    |-  F  Fn  _V   =>    |-  ( B  e.  V  ->  ( rec ( F ,  A ) `  B )  e.  _V )
 
2.6.22  Finite recursion
 
Syntaxcfrec 6466 Extend class notation with the finite recursive definition generator, with characteristic function  F and initial value  I.
 class frec ( F ,  I )
 
Definitiondf-frec 6467* Define a recursive definition generator on  om (the class of finite ordinals) with characteristic function  F and initial value  I. This rather amazing operation allows us to define, with compact direct definitions, functions that are usually defined in textbooks only with indirect self-referencing recursive definitions. A recursive definition requires advanced metalogic to justify - in particular, eliminating a recursive definition is very difficult and often not even shown in textbooks. On the other hand, the elimination of a direct definition is a matter of simple mechanical substitution. The price paid is the daunting complexity of our frec operation (especially when df-recs 6381 that it is built on is also eliminated). But once we get past this hurdle, definitions that would otherwise be recursive become relatively simple; see frec0g 6473 and frecsuc 6483.

Unlike with transfinite recursion, finite recurson can readily divide definitions and proofs into zero and successor cases, because even without excluded middle we have theorems such as nn0suc 4650. The analogous situation with transfinite recursion - being able to say that an ordinal is zero, successor, or limit - is enabled by excluded middle and thus is not available to us. For the characteristic functions which satisfy the conditions given at frecrdg 6484, this definition and df-irdg 6446 restricted to  om produce the same result.

Note: We introduce frec with the philosophical goal of being able to eliminate all definitions with direct mechanical substitution and to verify easily the soundness of definitions. Metamath itself has no built-in technical limitation that prevents multiple-part recursive definitions in the traditional textbook style. (Contributed by Mario Carneiro and Jim Kingdon, 10-Aug-2019.)

 |- frec
 ( F ,  I
 )  =  (recs (
 ( g  e.  _V  |->  { x  |  ( E. m  e.  om  ( dom  g  =  suc  m  /\  x  e.  ( F `  ( g `  m ) ) )  \/  ( dom  g  =  (/)  /\  x  e.  I ) ) }
 ) )  |`  om )
 
Theoremfreceq1 6468 Equality theorem for the finite recursive definition generator. (Contributed by Jim Kingdon, 30-May-2020.)
 |-  ( F  =  G  -> frec ( F ,  A )  = frec ( G ,  A ) )
 
Theoremfreceq2 6469 Equality theorem for the finite recursive definition generator. (Contributed by Jim Kingdon, 30-May-2020.)
 |-  ( A  =  B  -> frec ( F ,  A )  = frec ( F ,  B ) )
 
Theoremfrecex 6470 Finite recursion produces a set. (Contributed by Jim Kingdon, 20-Aug-2021.)
 |- frec
 ( F ,  A )  e.  _V
 
Theoremfrecfun 6471 Finite recursion produces a function. See also frecfnom 6477 which also states that the domain of that function is  om but which puts conditions on  A and  F. (Contributed by Jim Kingdon, 13-Feb-2022.)
 |- 
 Fun frec ( F ,  A )
 
Theoremnffrec 6472 Bound-variable hypothesis builder for the finite recursive definition generator. (Contributed by Jim Kingdon, 30-May-2020.)
 |-  F/_ x F   &    |-  F/_ x A   =>    |-  F/_ xfrec ( F ,  A )
 
Theoremfrec0g 6473 The initial value resulting from finite recursive definition generation. (Contributed by Jim Kingdon, 7-May-2020.)
 |-  ( A  e.  V  ->  (frec ( F ,  A ) `  (/) )  =  A )
 
Theoremfrecabex 6474* The class abstraction from df-frec 6467 exists. This is a lemma for other finite recursion proofs. (Contributed by Jim Kingdon, 13-May-2020.)
 |-  ( ph  ->  S  e.  V )   &    |-  ( ph  ->  A. y ( F `  y )  e.  _V )   &    |-  ( ph  ->  A  e.  W )   =>    |-  ( ph  ->  { x  |  ( E. m  e. 
 om  ( dom  S  =  suc  m  /\  x  e.  ( F `  ( S `  m ) ) )  \/  ( dom 
 S  =  (/)  /\  x  e.  A ) ) }  e.  _V )
 
Theoremfrecabcl 6475* The class abstraction from df-frec 6467 exists. Unlike frecabex 6474 the function  F only needs to be defined on  S, not all sets. This is a lemma for other finite recursion proofs. (Contributed by Jim Kingdon, 21-Mar-2022.)
 |-  ( ph  ->  N  e.  om )   &    |-  ( ph  ->  G : N --> S )   &    |-  ( ph  ->  A. y  e.  S  ( F `  y )  e.  S )   &    |-  ( ph  ->  A  e.  S )   =>    |-  ( ph  ->  { x  |  ( E. m  e. 
 om  ( dom  G  =  suc  m  /\  x  e.  ( F `  ( G `  m ) ) )  \/  ( dom 
 G  =  (/)  /\  x  e.  A ) ) }  e.  S )
 
Theoremfrectfr 6476* Lemma to connect transfinite recursion theorems with finite recursion. That is, given the conditions  F  Fn  _V and  A  e.  V on frec ( F ,  A ), we want to be able to apply tfri1d 6411 or tfri2d 6412, and this lemma lets us satisfy hypotheses of those theorems.

(Contributed by Jim Kingdon, 15-Aug-2019.)

 |-  G  =  ( g  e.  _V  |->  { x  |  ( E. m  e. 
 om  ( dom  g  =  suc  m  /\  x  e.  ( F `  (
 g `  m )
 ) )  \/  ( dom  g  =  (/)  /\  x  e.  A ) ) }
 )   =>    |-  ( ( A. z
 ( F `  z
 )  e.  _V  /\  A  e.  V )  ->  A. y ( Fun 
 G  /\  ( G `  y )  e.  _V ) )
 
Theoremfrecfnom 6477* The function generated by finite recursive definition generation is a function on omega. (Contributed by Jim Kingdon, 13-May-2020.)
 |-  ( ( A. z
 ( F `  z
 )  e.  _V  /\  A  e.  V )  -> frec ( F ,  A )  Fn  om )
 
Theoremfreccllem 6478* Lemma for freccl 6479. Just giving a name to a common expression to simplify the proof. (Contributed by Jim Kingdon, 27-Mar-2022.)
 |-  ( ph  ->  A  e.  S )   &    |-  ( ( ph  /\  z  e.  S ) 
 ->  ( F `  z
 )  e.  S )   &    |-  ( ph  ->  B  e.  om )   &    |-  G  = recs (
 ( g  e.  _V  |->  { x  |  ( E. m  e.  om  ( dom  g  =  suc  m  /\  x  e.  ( F `  ( g `  m ) ) )  \/  ( dom  g  =  (/)  /\  x  e.  A ) ) }
 ) )   =>    |-  ( ph  ->  (frec ( F ,  A ) `
  B )  e.  S )
 
Theoremfreccl 6479* Closure for finite recursion. (Contributed by Jim Kingdon, 27-Mar-2022.)
 |-  ( ph  ->  A  e.  S )   &    |-  ( ( ph  /\  z  e.  S ) 
 ->  ( F `  z
 )  e.  S )   &    |-  ( ph  ->  B  e.  om )   =>    |-  ( ph  ->  (frec ( F ,  A ) `
  B )  e.  S )
 
Theoremfrecfcllem 6480* Lemma for frecfcl 6481. Just giving a name to a common expression to simplify the proof. (Contributed by Jim Kingdon, 30-Mar-2022.)
 |-  G  = recs ( ( g  e.  _V  |->  { x  |  ( E. m  e.  om  ( dom  g  =  suc  m  /\  x  e.  ( F `  ( g `  m ) ) )  \/  ( dom  g  =  (/)  /\  x  e.  A ) ) }
 ) )   =>    |-  ( ( A. z  e.  S  ( F `  z )  e.  S  /\  A  e.  S ) 
 -> frec ( F ,  A ) : om --> S )
 
Theoremfrecfcl 6481* Finite recursion yields a function on the natural numbers. (Contributed by Jim Kingdon, 30-Mar-2022.)
 |-  ( ( A. z  e.  S  ( F `  z )  e.  S  /\  A  e.  S ) 
 -> frec ( F ,  A ) : om --> S )
 
Theoremfrecsuclem 6482* Lemma for frecsuc 6483. Just giving a name to a common expression to simplify the proof. (Contributed by Jim Kingdon, 29-Mar-2022.)
 |-  G  =  ( g  e.  _V  |->  { x  |  ( E. m  e. 
 om  ( dom  g  =  suc  m  /\  x  e.  ( F `  (
 g `  m )
 ) )  \/  ( dom  g  =  (/)  /\  x  e.  A ) ) }
 )   =>    |-  ( ( A. z  e.  S  ( F `  z )  e.  S  /\  A  e.  S  /\  B  e.  om )  ->  (frec ( F ,  A ) `  suc  B )  =  ( F `
  (frec ( F ,  A ) `  B ) ) )
 
Theoremfrecsuc 6483* The successor value resulting from finite recursive definition generation. (Contributed by Jim Kingdon, 31-Mar-2022.)
 |-  ( ( A. z  e.  S  ( F `  z )  e.  S  /\  A  e.  S  /\  B  e.  om )  ->  (frec ( F ,  A ) `  suc  B )  =  ( F `
  (frec ( F ,  A ) `  B ) ) )
 
Theoremfrecrdg 6484* Transfinite recursion restricted to omega.

Given a suitable characteristic function, df-frec 6467 produces the same results as df-irdg 6446 restricted to  om.

Presumably the theorem would also hold if  F  Fn  _V were changed to  A. z ( F `  z )  e.  _V. (Contributed by Jim Kingdon, 29-Aug-2019.)

 |-  ( ph  ->  F  Fn  _V )   &    |-  ( ph  ->  A  e.  V )   &    |-  ( ph  ->  A. x  x  C_  ( F `  x ) )   =>    |-  ( ph  -> frec ( F ,  A )  =  ( rec ( F ,  A )  |`  om ) )
 
2.6.23  Ordinal arithmetic
 
Syntaxc1o 6485 Extend the definition of a class to include the ordinal number 1.
 class  1o
 
Syntaxc2o 6486 Extend the definition of a class to include the ordinal number 2.
 class  2o
 
Syntaxc3o 6487 Extend the definition of a class to include the ordinal number 3.
 class  3o
 
Syntaxc4o 6488 Extend the definition of a class to include the ordinal number 4.
 class  4o
 
Syntaxcoa 6489 Extend the definition of a class to include the ordinal addition operation.
 class  +o
 
Syntaxcomu 6490 Extend the definition of a class to include the ordinal multiplication operation.
 class  .o
 
Syntaxcoei 6491 Extend the definition of a class to include the ordinal exponentiation operation.
 classo
 
Definitiondf-1o 6492 Define the ordinal number 1. (Contributed by NM, 29-Oct-1995.)
 |- 
 1o  =  suc  (/)
 
Definitiondf-2o 6493 Define the ordinal number 2. (Contributed by NM, 18-Feb-2004.)
 |- 
 2o  =  suc  1o
 
Definitiondf-3o 6494 Define the ordinal number 3. (Contributed by Mario Carneiro, 14-Jul-2013.)
 |- 
 3o  =  suc  2o
 
Definitiondf-4o 6495 Define the ordinal number 4. (Contributed by Mario Carneiro, 14-Jul-2013.)
 |- 
 4o  =  suc  3o
 
Definitiondf-oadd 6496* Define the ordinal addition operation. (Contributed by NM, 3-May-1995.)
 |- 
 +o  =  ( x  e.  On ,  y  e.  On  |->  ( rec (
 ( z  e.  _V  |->  suc  z ) ,  x ) `  y ) )
 
Definitiondf-omul 6497* Define the ordinal multiplication operation. (Contributed by NM, 26-Aug-1995.)
 |- 
 .o  =  ( x  e.  On ,  y  e.  On  |->  ( rec (
 ( z  e.  _V  |->  ( z  +o  x ) ) ,  (/) ) `  y ) )
 
Definitiondf-oexpi 6498* Define the ordinal exponentiation operation.

This definition is similar to a conventional definition of exponentiation except that it defines  (/)o  A to be  1o for all  A  e.  On, in order to avoid having different cases for whether the base is  (/) or not.

We do not yet have an extensive development of ordinal exponentiation. For background on ordinal exponentiation without excluded middle, see Tom de Jong, Nicolai Kraus, Fredrik Nordvall Forsberg, and Chuangjie Xu (2025), "Ordinal Exponentiation in Homotopy Type Theory", arXiv:2501.14542 , https://arxiv.org/abs/2501.14542 which is formalized in the TypeTopology proof library at https://ordinal-exponentiation-hott.github.io/.

(Contributed by Mario Carneiro, 4-Jul-2019.)

 |-o  =  ( x  e.  On ,  y  e.  On  |->  ( rec ( ( z  e.  _V  |->  ( z  .o  x ) ) ,  1o ) `  y ) )
 
Theorem1on 6499 Ordinal 1 is an ordinal number. (Contributed by NM, 29-Oct-1995.)
 |- 
 1o  e.  On
 
Theorem1oex 6500 Ordinal 1 is a set. (Contributed by BJ, 4-Jul-2022.)
 |- 
 1o  e.  _V
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