Theorem unrab 3311

Description: Union of two restricted class abstractions. (Contributed by NM, 25-Mar-2004.)

Assertion

Ref	Expression
unrab	|- ( { x e. A | ph } u. { x e. A | ps } ) = { x e. A | ( ph \/ ps ) }

Proof of Theorem unrab

Step	Hyp	Ref	Expression
1		df-rab 2397	. . 3 |- { x e. A | ph } = { x | ( x e. A /\ ph ) }
2		df-rab 2397	. . 3 |- { x e. A | ps } = { x | ( x e. A /\ ps ) }
3	1, 2	uneq12i 3192	. 2 |- ( { x e. A | ph } u. { x e. A | ps } ) = ( { x | ( x e. A /\ ph ) } u. { x | ( x e. A /\ ps ) } )
4		df-rab 2397	. . 3 |- { x e. A | ( ph \/ ps ) } = { x | ( x e. A /\ ( ph \/ ps ) ) }
5		unab 3307	. . . 4 |- ( { x | ( x e. A /\ ph ) } u. { x | ( x e. A /\ ps ) } ) = { x | ( ( x e. A /\ ph ) \/ ( x e. A /\ ps ) ) }
6		andi 790	. . . . 5 |- ( ( x e. A /\ ( ph \/ ps ) ) <-> ( ( x e. A /\ ph ) \/ ( x e. A /\ ps ) ) )
7	6	abbii 2228	. . . 4 |- { x | ( x e. A /\ ( ph \/ ps ) ) } = { x | ( ( x e. A /\ ph ) \/ ( x e. A /\ ps ) ) }
8	5, 7	eqtr4i 2136	. . 3 |- ( { x | ( x e. A /\ ph ) } u. { x | ( x e. A /\ ps ) } ) = { x | ( x e. A /\ ( ph \/ ps ) ) }
9	4, 8	eqtr4i 2136	. 2 |- { x e. A | ( ph \/ ps ) } = ( { x | ( x e. A /\ ph ) } u. { x | ( x e. A /\ ps ) } )
10	3, 9	eqtr4i 2136	1 |- ( { x e. A | ph } u. { x e. A | ps } ) = { x e. A | ( ph \/ ps ) }

Syntax hints:   /\ wa 103   \/ wo 680   = wceq 1312   e. wcel 1461   {cab 2099   {crab 2392   u. cun 3033

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 681  ax-5 1404  ax-7 1405  ax-gen 1406  ax-ie1 1450  ax-ie2 1451  ax-8 1463  ax-10 1464  ax-11 1465  ax-i12 1466  ax-bndl 1467  ax-4 1468  ax-17 1487  ax-i9 1491  ax-ial 1495  ax-i5r 1496  ax-ext 2095

This theorem depends on definitions:  df-bi 116  df-tru 1315  df-nf 1418  df-sb 1717  df-clab 2100  df-cleq 2106  df-clel 2109  df-nfc 2242  df-rab 2397  df-v 2657  df-un 3039

This theorem is referenced by:  rabxmdc  3358  phiprmpw  11736  unennn  11748  znnen  11749