Theorem xpeq12d 4756

Description: Equality deduction for Cartesian product. (Contributed by NM, 8-Dec-2013.)

Hypotheses

Ref	Expression
xpeq1d.1	⊢ (𝜑 → 𝐴 = 𝐵)
xpeq12d.2	⊢ (𝜑 → 𝐶 = 𝐷)

Assertion

Ref	Expression
xpeq12d	⊢ (𝜑 → (𝐴 × 𝐶) = (𝐵 × 𝐷))

Proof of Theorem xpeq12d

Step	Hyp	Ref	Expression
1		xpeq1d.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		xpeq12d.2	. 2 ⊢ (𝜑 → 𝐶 = 𝐷)
3		xpeq12 4750	. 2 ⊢ ((𝐴 = 𝐵 ∧ 𝐶 = 𝐷) → (𝐴 × 𝐶) = (𝐵 × 𝐷))
4	1, 2, 3	syl2anc 411	1 ⊢ (𝜑 → (𝐴 × 𝐶) = (𝐵 × 𝐷))

Syntax hints:   → wi 4   = wceq 1398   × cxp 4729

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-11 1555  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2213

This theorem depends on definitions:  df-bi 117  df-tru 1401  df-nf 1510  df-sb 1811  df-clab 2218  df-cleq 2224  df-clel 2227  df-opab 4156  df-xp 4737

This theorem is referenced by:  sqxpeqd  4757  opeliunxp  4787  mpomptsx  6371  dmmpossx  6373  fmpox  6374  disjxp1  6410  erssxp  6768  cc2lem  7528  cc2  7529  fsum2dlemstep  12056  fisumcom2  12060  fprod2dlemstep  12244  fprodcom2fi  12248  psrval  14742  txbas  15049