Theorem xpeq12d 4745

Description: Equality deduction for Cartesian product. (Contributed by NM, 8-Dec-2013.)

Hypotheses

Ref	Expression
xpeq1d.1	⊢ (𝜑 → 𝐴 = 𝐵)
xpeq12d.2	⊢ (𝜑 → 𝐶 = 𝐷)

Assertion

Ref	Expression
xpeq12d	⊢ (𝜑 → (𝐴 × 𝐶) = (𝐵 × 𝐷))

Proof of Theorem xpeq12d

Step	Hyp	Ref	Expression
1		xpeq1d.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		xpeq12d.2	. 2 ⊢ (𝜑 → 𝐶 = 𝐷)
3		xpeq12 4739	. 2 ⊢ ((𝐴 = 𝐵 ∧ 𝐶 = 𝐷) → (𝐴 × 𝐶) = (𝐵 × 𝐷))
4	1, 2, 3	syl2anc 411	1 ⊢ (𝜑 → (𝐴 × 𝐶) = (𝐵 × 𝐷))

Syntax hints:   → wi 4   = wceq 1395   × cxp 4718

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1493  ax-7 1494  ax-gen 1495  ax-ie1 1539  ax-ie2 1540  ax-8 1550  ax-11 1552  ax-4 1556  ax-17 1572  ax-i9 1576  ax-ial 1580  ax-i5r 1581  ax-ext 2211

This theorem depends on definitions:  df-bi 117  df-tru 1398  df-nf 1507  df-sb 1809  df-clab 2216  df-cleq 2222  df-clel 2225  df-opab 4146  df-xp 4726

This theorem is referenced by:  sqxpeqd  4746  opeliunxp  4776  mpomptsx  6354  dmmpossx  6356  fmpox  6357  disjxp1  6393  erssxp  6716  cc2lem  7468  cc2  7469  fsum2dlemstep  11966  fisumcom2  11970  fprod2dlemstep  12154  fprodcom2fi  12158  psrval  14651  txbas  14953