Theorem abex 5308

Description: Conditions for a class abstraction to be a set. Remark: This proof is shorter than a proof using abexd 5307. (Contributed by AV, 19-Apr-2025.)

Hypotheses

Ref	Expression
abex.1	⊢ (𝜑 → 𝑥 ∈ 𝐴)
abex.2	⊢ 𝐴 ∈ V

Assertion

Ref	Expression
abex	⊢ {𝑥 ∣ 𝜑} ∈ V

Distinct variable group:   𝑥,𝐴

Allowed substitution hint:   𝜑(𝑥)

Proof of Theorem abex

Step	Hyp	Ref	Expression
1		abex.2	. 2 ⊢ 𝐴 ∈ V
2		abss 4045	. . 3 ⊢ ({𝑥 ∣ 𝜑} ⊆ 𝐴 ↔ ∀𝑥(𝜑 → 𝑥 ∈ 𝐴))
3		abex.1	. . 3 ⊢ (𝜑 → 𝑥 ∈ 𝐴)
4	2, 3	mpgbir 1798	. 2 ⊢ {𝑥 ∣ 𝜑} ⊆ 𝐴
5	1, 4	ssexi 5304	1 ⊢ {𝑥 ∣ 𝜑} ∈ V

Syntax hints:   → wi 4   ∈ wcel 2107  {cab 2712  Vcvv 3464   ⊆ wss 3933

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1794  ax-4 1808  ax-5 1909  ax-6 1966  ax-7 2006  ax-8 2109  ax-9 2117  ax-10 2140  ax-11 2156  ax-12 2176  ax-ext 2706  ax-sep 5278

This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1542  df-ex 1779  df-nf 1783  df-sb 2064  df-clab 2713  df-cleq 2726  df-clel 2808  df-nfc 2884  df-rab 3421  df-v 3466  df-in 3940  df-ss 3950

This theorem is referenced by:  grimfn  47807  isgrim  47810